# SIB PO Reasoning Ability Practice Quiz 4

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# SIB PO Reasoning Ability Practice Quiz 4

### Introduction

The SIB PO 2019 Stage - 1 Online Test consists of four different sections containing different marks with a total of 200 marks .
There is a Negative marking in SIB PO Online Exam and 0.25 marks are deducted for each wrong answer. Candidates must clear the cut-off in all the sections to qualify for the Group Exercises & Interview.
Sr. No Name of Tests No. of Qs. Max. Marks Version Time allotted for each test (Separately timed)
1. Reasoning & Computer Aptitude 40 50

Only English
40 minutes
2. General/ Economy/ Banking Awareness 40 50 20 minutes
3. English Language 40 50 40 minutes
4. Data Analysis & Interpretation 40 50 40 minutes
Total 160 200 140 minutes

The Reasoning section primarily has questions related to the Syllogism, Directions, and Inequality , etc. This article presents SIB PO Reasoning Ability Practice Quiz 4 for acing the SIB PO Examination. The online examination for South Indian Bank PO 2019 recruitment is scheduled to be conducted in 25.07.2019.

### Quiz

1. On which day of the week did Anil arrive? 1. His sister, Tanvi, correctly remembers that he did not arrive on Wednesday. 2. His friend, Manav, correctly remembers that he arrived before Friday. 3. His mother correctly mentions that he arrived before Friday but after Tuesday.
A. only 1 and 2 B. only 2 and 3 C. only 1 and 3 D. all 1,2 and 3 E. none of these

2. P, Q, R, S and T are sitting in a row facing North. Who among them is in the middle? 1. T is at the right end of the row. 2. S sits between P and R. 3. Neither P nor R sits at an extreme end
A. only 2 and 3 B. only 3 C. only 1 and 3 D. all of them E. none of these

3. Among A, B, C, D and E each with a different weight, who is the lightest? 1. C is heavier than B but lighter than E. 2. A is heavier than B but lighter than D. 3. E is not the heaviest
A. only 1 and 3 B. only 2 C. only 1 and 2 D. only 2 and 3 E. none of these

Direction(4-5): Study the following information carefully and answer the following questions.
I. “Plants Grow Fast” is coded as “ncs bky naa” II. “Earth Is Planet” is coded as “ora mul atx” III. “Plants Grow Earth” is coded as “ora bky naa” IV. “Grow Is Fast” is coded as “bky atx ncs”
4. Which of the following given statements is necessary to identify the code for the word ‘Plants’ as ‘naa’?
A. I and III are sufficient B. I and IV are sufficient C. I, II and III are sufficient D. III and IV are sufficient E. All I, II, III and IV are necessary

5. In the above question which of the statements is necessary to identify the code for the word ‘Fast’ as ‘ncs’?
A. I and III are sufficient B. I and IV are sufficient C. I, II and III are sufficient D. III and IV are sufficient E. All I, II, III and IV are necessary

Explanation -
1. Wednesday he didn’t arrive
2. number of possible cases S,M,T,W,T
3. possible cases W,T
But from first he didn’t arrive on Wednesday, so from 1 and 3 he arrives on Thursday
Explanation -
From 2 and 3, we get that either they are in PSR or in RSP manner and P and R didn’t sit at the ends, so we get S sits in the middle
Explanation -
From 2 and 3 we get that E>C>B and D>A>B, so we can conclude that B is the lightest
Explanation -
I and IV are sufficient
Explanation -
I and III are sufficient
1. What was the day of the week on 28th May, 2006?
A. Thursday B. Friday C. Saturday D. Sunday E. Wednesday

2. Today is Monday. After 61 days, it will be:
A. Wednesday B. Saturday C. Tuesday D. Thursday E. Friday

3. An accurate clock shows 8 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?
A. 144°° B. 150° C. 168° D. 180° E. 160°

4. A clock is started at noon. By 10 minutes past 5, the hour hand has turned through:
A. 145° B. 150° C. 155° D. 160° E. 170°

5. The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
A.B. 10° C.D. 20° E. 30°

Explanation -
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
i.e, 148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Explanation -
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
Explanation -
Angle traced by the hour hand in 6 hours = $(\frac {360}{12} \times 6)°$= 180°
Explanation -
Angle traced by hour hand in 12 hrs = 360°.
Angle traced by hour hand in 5 hrs 10 min. i.e., $\frac {31}{6} hrs = (\frac {360}{12} \times \frac {31}{6})°$ = 155°
Explanation -
Angle traced by hour hand in $\frac {13}{3} hrs = (\frac {360}{12} \times \frac {13}{3})°$ = 130
Angle traced by min hand in 20 min. = $(\frac {360}{60} \times 20)°$ = 120°
i.e, Required angle = (130 - 120)° = 10°.
1. (935421 x 625) = ?
A. 575648125 B. 584638125 C. 584649125 D. 585628125 E. 685628125

2. How many of the following numbers are divisible by 132 ? 264, 396, 462, 792, 968, 2178, 5184, 6336
A. 4 B. 5 C. 6 D. 7 E. 8

There are six persons P, Q, R, S, T and U in a family. There are two fathers, three brothers and a mother in the family. R is the sister of U. Q is the brother of T’s husband. S is the father of P and grandfather of U.
3. Who is the mother in the family?
A. P B. R C. T D. S E. None of these

4. How many males are there in the family?
A. one B. two C. three D. four E. None of these

5. How is U related to T?
A. son B. daughter C. niece D. nephew E. None of these

Explanation -
935421 x 625 = 935421 x ${5}^{4} = 935421 \times ({\frac {10}{2}}^{4})$
$\frac {935421 \times {10}^{4}}{{2}^{4}} = \frac {9354210000}{16}$
Explanation -
132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 $\Rightarrow$ 11,3,4 (/)
396 $\Rightarrow$ 11,3,4 (/)
462 $\Rightarrow$ 11,3 (X)
792 $\Rightarrow$ 11,3,4 (/)
968 $\Rightarrow$ 11,4 (X)
2178 $\Rightarrow$ 11,3 (X)
5184 $\Rightarrow$ 3,4 (X)
6336 $\Rightarrow$ 11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
Explanation [3-5] -

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