The **SIB PO 2019 Stage - 1** Online Test consists of four different sections containing different marks with a total of **200 marks** .

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There is a Negative marking in**SIB PO** Online Exam and ** 0.25** marks are deducted for each wrong answer. Candidates must clear the cut-off in all the sections to qualify for the Group Exercises & Interview.

The**Reasoning** section primarily has questions related to the Syllogism, Directions, and Inequality , etc. This article presents **SIB PO Reasoning Ability Practice Quiz 4** for acing the SIB PO Examination. The online examination for **South Indian Bank PO 2019** recruitment is scheduled to be conducted in **25.07.2019.**

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There is a Negative marking in

Sr. No | Name of Tests | No. of Qs. | Max. Marks | Version | Time allotted for each test (Separately timed) |
---|---|---|---|---|---|

1. | Reasoning & Computer Aptitude | 40 | 50 | Only English |
40 minutes |

2. | General/ Economy/ Banking Awareness | 40 | 50 | 20 minutes | |

3. | English Language | 40 | 50 | 40 minutes | |

4. | Data Analysis & Interpretation | 40 | 50 | 40 minutes | |

Total | 160 | 200 | 140 minutes |

The

1. Wednesday he didn’t arrive

2. number of possible cases S,M,T,W,T

3. possible cases W,T

But from first he didn’t arrive on Wednesday, so from 1 and 3 he arrives on Thursday

From 2 and 3, we get that either they are in PSR or in RSP manner and P and R didn’t sit at the ends, so we get S sits in the middle

From 2 and 3 we get that E>C>B and D>A>B, so we can conclude that B is the lightest

I and IV are sufficient

I and III are sufficient

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days

i.e, 148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

After 61 days, it will be Saturday.

Angle traced by the hour hand in 6 hours = [latex](\frac {360}{12} \times 6)°[/latex]= 180°

Angle traced by hour hand in 12 hrs = 360°.

Angle traced by hour hand in 5 hrs 10 min. i.e., [latex]\frac {31}{6} hrs = (\frac {360}{12} \times \frac {31}{6})°[/latex] = 155°

Angle traced by hour hand in [latex]\frac {13}{3} hrs = (\frac {360}{12} \times \frac {13}{3})°[/latex] = 130

Angle traced by min hand in 20 min. = [latex](\frac {360}{60} \times 20)°[/latex] = 120°

i.e, Required angle = (130 - 120)° = 10°.

There are six persons P, Q, R, S, T and U in a family. There are two fathers, three brothers and a mother in the family. R is the sister of U. Q is the brother of T’s husband. S is the father of P and grandfather of U.

935421 x 625 = 935421 x [latex]{5}^{4} = 935421 \times ({\frac {10}{2}}^{4})[/latex]

[latex]\frac {935421 \times {10}^{4}}{{2}^{4}} = \frac {9354210000}{16}[/latex]

132 = 4 x 3 x 11

So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.

264 [latex]\Rightarrow[/latex] 11,3,4 (/)

396 [latex]\Rightarrow[/latex] 11,3,4 (/)

462 [latex]\Rightarrow[/latex] 11,3 (X)

792 [latex]\Rightarrow[/latex] 11,3,4 (/)

968 [latex]\Rightarrow[/latex] 11,4 (X)

2178 [latex]\Rightarrow[/latex] 11,3 (X)

5184 [latex]\Rightarrow[/latex] 3,4 (X)

6336 [latex]\Rightarrow[/latex] 11,3,4 (/)

Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.

Required number of number = 4.

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