The article

From right end

(i) Vijay’s present position: [latex]{27}^{th}[/latex]

(ii) Vijay’s former position: [latex]{17}^{th}[/latex]

Now, total number of students between Ajay and Vijay = 27 – 17 – 1 = 9.

Modi’s position from the left end = 40 + 1 – 14 = [latex]{27}^{th}[/latex]

Clearly, total number of boys in both the rows

= (Number of boys in Jayati’s row) + (Number of boys in Bharat’s row)

= (6 + 1 + 10) + (9 + 1 + 11) = 17 + 21 = 38.

Sajan rank 26th and Seema is 8 ranks ahead of Sajan. So, Seema ranks 18th. Number of students behind Seema in rank = (42 – 18) = 24.

So, Seema ranks 25th from the last.

Amita is 22nd from the top and Ramnik is 5 ranks below Amita. So, Ramnik is 27th from the top. Also,

Ramnik is 34th from the bottom.

Number of students passed = (26 + 1 + 33) = 60

Total number of students in the class = 60 + 15 = 75.

Minimum number of students will be possible in the following case

Thus, in the above case, total number of students = 9 + 6 – 1 = 14.

Here, Rajni’s position from the right end = 21 + 10 = [latex]{31}^{st}[/latex]

Meera’s position from the right end = 31 – 4 = [latex]{27}^{th}[/latex]

Meera’s position from the left end = [latex]{17}^{th}[/latex] (given)

Thus, the total number of persons in the row = 27 + 17 – 1 = 43

Sandeep’s new position is 15th from the right as well as from the left end of the row.

Number of students in the queue = (14 + 1 + 14) = 29.

Manoj’s earlier position from the right end = [latex]{17}^{th}[/latex]

Manoj’s earlier position from the left end = [latex]{13}^{th}[/latex]

Total number of persons in the row = 17 + 13 – 1 = 29

Manoj’s new position from the right

= 29 + 1 – 11= [latex]{19}^{th}[/latex]

On the basis of the given information, we get

Mehak > Nitika > Neelima > Neeta > Sania

Obviously, Neelima will occupy the middle position

Vani > Rani

Vani > Sita > Rani

Mary, Rani > Nita.

Rani > Mary

Vani > Sita > Rani > Mary > Nita.

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S U R T V

Kamal’s position from left = 9th

Veena’s position from right = 16th

After interchanging their positions,

Kamal’s position from left = 25th

So, that Kamal’s position from right = 16th

i.e, Total number of girls = (25 + 16) – 1 = 40.

Rajan’s rank in the class = [latex]{11}^{th}[/latex]

Also, Rajan’s rank in the class from bottom = [latex]{31}^{th}[/latex]

i.e, Number of boys passed = 41

Total number of boys = 41 + 31 + 1 = 45.

B = 2A

F = 2B = 4A

A = 2C

C = [latex]\frac{A}{2}[/latex]

C = 2D

D = [latex]\frac{C}{2} = \frac{A}{4}[/latex]

The correct order is F > B > A > C > D.

Hence, the second oldest is B.

Ramesh’s rank in the class = 13th

Total number of student = 33

i.e, Suresh’s rank in the class = 33 – 5 = 28th

i.e, Number of student between Ramesh and Suresh

= 28 – (13 + 1) = 14.

A tree’s rank from the left = 7th and that of from right= [latex]{14}^{th}[/latex].

i.e, Total number of trees = 14 + 7 – 1 = 20.

The given standing position is

Left ← M N Q P O → Right

The order of eldest to youngest is given below.

Sita > Lavanya > Swapna > Hari > Suvarna.

Total number of boys in the row = 22 + 12 – 1 = 33

From the given information the order is DECAB.

Ashok's rank from last = [latex]{17}^{th}[/latex]

i.e, Suresh's rank from last = 17 + 7 = [latex]{24}^{th}[/latex]

i.e, Suresh's rank from the start = 39 – 24 + 1 = [latex]{16}^{th}[/latex]

The given information can be shown as: P X Q Y Z R

Let weight of the ring D be x gm.

i.e, Weight of E = [latex]\frac{x}{2}[/latex] gm.

Weight of F = [latex]\frac{x}{2} * \frac{2}{9} = \frac{x}{9}[/latex] gm.

Weight of G = [latex]\frac{2x}{9}[/latex] gm.

Weight of H = [latex]\frac{4x}{9}[/latex] gm.

Weight of D > Weight of H > Weight of F.

i.e, Descending order of weight of the rings

D > E > H > G > F.

- B finished before 3 athletes exactly.
- C and A finished neither 1st nor 5th.
- D did not finish at last.
- C finished before A.

Order of athletes to finish race is D, B, C, A and E.

Hence, C will come [latex]{3}^{rd}[/latex].

The order of the heights of the persons according to the given information will be

Sachin > Rahul > Saurav > Dhoni > Kaif

Hence, Sachin is the tallest.

Aakash finished the race before Krishna and after

Suhail. Ravi finished the race before Suhail and Mayur.

Hence, Ravi won the race.

Hence, D is at the bottom of the pile.

From the given information, order of landing is: F A E D B C G

Hence, G landed last

Since Q is sitting to the left of S and to the right of R, their places are R Q S

Since R, Q and T are not sitting adjacent to each other, T must be to the right of S.

P is sitting between R and Q. The final arrangement is R P Q S T

Hence, R and T are sitting at the extreme ends.

- • B is heavier than only E.
• F is heavier than 4 friends exactly.
• A or C is not heaviest.
• A is heavier than C.

The order of weight is D > F > A > C > B > E.

Hence, C is the [latex]{4}^{th}[/latex] heaviest.

B | BR | BRW | BRWG | BRWGY | B | BR| BRW | BRWG

Therefore, in the above sequence G will be the next letter. Hence, Green will come next in the series.

Arranging the given information, we get

Pankaj > Mandar > Amit > Prashant > Vinod

Hence, Pankaj is the tallest.

Using the formula,

T = [latex]{R}_{T} + {R}_{B} - 1[/latex]

We get,

T = 16 + 15 – 1 = 30.

Hence, there are 30 students in the class

Given information can be shown as:

Sameer Ravi Keshav Mahesh Piyush ↑ North

OR

Mahesh Sameer Ravi Keshav Piyush

Hence, Sameer and Piyush could be sitting at the extreme ends.

The arrangement is C D A B E

So, B is E’s neighbor.

Arranging the given information in decreasing order we get B > D > A and D > E > C

but we don’t know whether A < C or C < A.

Hence, we cannot decide.

For questions 8 and 9:

Answer the questions on the basis of the information given below.

- I. There are five friends – Alok, Jayesh, Bhagat, Subodh and Pramod.
II. They are standing in a row facing South.
III. Jayesh is to the immediate right of Alok.
IV. Pramod is between Bhagat and Subodh.
V. Subodh is between Jayesh and Pramod.

Hence, B and D are to the right of E.

Hence, D touches the table

The information for weight can be summarised as shown below.

Raman > Chaman > Aman> Baman >Saman

Hence, Chaman is the second heaviest

Hence, Padma is in the middle.

Hence, Dhanush is standing in the middle.

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