# LIC ADO Mains Reasoning Practice Set 2

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# LIC ADO Mains Reasoning Practice Set 2

### Introduction

Reasoning is an important section in the employment related competitive exams in India. In particular, exams like LIC ADO, LIC AAO, IBPS, SBI, SIB, IDBI and other bank & Insurance related employment exams have Reasoning questions along with Quantitative Aptitude. The Reasoning section primarily has questions related to the Syllogism, Directions, and Inequality , etc. This article presents LIC ADO Mains Reasoning Practice Set 2 for acing the LIC ADO Mains Examination.

### Quiz

Directions (1-5): Study the following figure and answer the questions given below
Seven people – M, L, J, I, K, O and Y are studying in three different classes, Class 9, Class 10 and Class 8. Not more than three people Studying in the same class. They secure different marks in English viz., 5, 16, 19, 20, 24, 36 and 57 but not necessarily in the same order. The persons who are studying in 8 class secure only even numbered marks and the persons who are studying in 10 class secure only Odd numbered marks.
The marks secured by class 9 students are more than that of the marks secured by class 10 students. M Secured less than 30 marks and studies with Y. The sum of marks secure by K and Y is more than 90 marks. Only O and L studying in class 10. O secured more marks than L. M and J are studying in different class. M secure more marks than I. M and K studying in different class. J and I secure a mark which is a multiple of 4. I and Y are studying in the same class. M is junior to K. The mark scored by J is not a multiple of 5.
1. What will be the mark secured by O?
A. 5 B. 19 C. None of these D. 16

Explanation [1-5]-
Note: They secure different marks in English viz., 5, 16, 19, 20, 24, 36 and 57.The persons who is studying in 8 class secure only even number marks and the person who study 10th class secure only Odd number marks.
• The sum of marks secure by K and Y is more than 90 marks.(K/Y=57/36)
• O and L only studying in class 10. ( O and L secure = 5/19 marks)
• O secure more marks than L. So O secure 19 marks and L secure 5 marks.
• M Secured less than 30 marks and studies with Y. M secure more marks than I. So M secure either 20 or 24.

• M and J studying in different class.
• I and Y studying in the same class.
• M and K studying in different class.
• M is junior to K.
• From this J and K studying in class 9.
• M, I and Y are studying in class 8.
• The mark scored by J is not a multiple of 5.
• J and I secure a mark which is a multiple of 4.
• So the final arrangement becomes

2. What will be the sum of marks secured by J and Y?
A. 52 B. 56 C. 60 D. None of these

3. Who among them are studying in class 9?
A. Y and O B. K and M C. J and K D. I and Y

4. What will be the difference between the marks secured by J and L?
A. 19 B. 21 C. 29 D. 24

5. How many persons secured more marks than J?
A. One B. Two C. Three D. None

Directions (1-2): In each problem, out of the five figures marked (1), (2), (3) & (4), three are similar in a certain manner. However, one figure is not like the other three. Choose the figure which is different from the rest.
1. Choose the figure which is different from the rest.
A. 1 B. 2 C. 3 D. 4

Explanation -
The pins, equal in number to the number of sides in the main figure are attached to the midpoint of a side of the main figure in case of figures (2), (3), (4) and (5). In fig. (1), these pins are attached to a vertex of the main figure.
2. Choose the figure which is different from the rest.
A. 1 B. 2 C. 3 D. 4

Explanation - In all other figures, the two line segments are parallel to each other.
3. January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?
A. Monday B. Wednesday C. Thursday D. Sunday

Explanation - The year 2008 is a leap year. So, it has 2 odd days.
${1}^{st}$ day of the year 2008 is Tuesday (Given)
So, ${1}^{st}$ day of the year 2009 is 2 days beyond Tuesday.
Hence, it will be Thursday.
4. what time between 4 and 5 o'clock will the hands of a clock be at right angle?
A. $3 \frac {5}{11}$ B. $4 \frac {5}{11}$ C. $5 \frac {5}{11}$ D. $6 \frac {5}{11}$

Explanation - $(5 \times x + or - 15) \times (\frac {12}{11})$
Here x is replaced by the first interval of given time here i.e 4
Case 1 : $(5 \times x + 15) \times (\frac {12}{11})$
$(5 \times 4 + 15) \times (\frac {12}{11})$
$(20 + 15) \times (\frac {12}{11})$
$35 \times \frac {12}{11} = \frac {420}{11} = 38 \frac {2}{11}$ min.
Therefore they are right angles at 38 $\frac {2}{11}$ min .past 4
Case 2 : $(5 \times x - 15) \times (\frac {12}{11})$
$(5 \times 4 - 15) \times (\frac {12}{11})$
$(20-15) \times (\frac {12}{11})$
$5 \times \frac {12}{11} = \frac {60}{11}$ min = 5 $\frac {5}{11}$ min
Therefore they are right angles at 5 $\frac {5}{11}$ min. past 4.
Directions (5): In each question below is given a statement followed by two assumptions numbered I and II. You have to consider the statement and the following assumptions and decide which of the assumptions is implicit in the statement.
5. Statement: A's advice to B - "Go to Jammu via Amritsar - the shortest route". Assumptions: I. B wishes to go to Jammu. II. A gives advice to everybody
A. Only assumption I is implicit B. Only assumption II is implicit C. Either I or II is implicit D. Neither I nor II is implicit

Explanation - A has advised B the route to Jammu. This means that B wishes to go to Jammu. So, I is implicit. The statement mentions only A's advice to B. So, II is not implicit.
1. Anupam said to a lady sitting in a car, "The only daughter of the brother of my wife is the sister-in-law of the brother of your sister." How the husband of the lady is related to Anupam?
A. Maternal uncle B. Uncle C. Father D. Son-in-law

Explanation - Anupam's son-in-law is the brother of the lady who was sitting in the car. Hence, the husband is also the son-in-law of Anupam.
2. If P + Q means P is the brother of Q; P x Q means P is the father of Q and P - Q means P is the sister of Q, which of the following relations shows that I is the niece of K?
A. K + Y + Z - I B. K + Y x I - Z C. Z - I x Y + K D. K x Y + I - Z

Explanation - K + Y → K is the brother of Y
Y x I → Y is the father of I
Hence, → K is the uncle of I
and I - Z → I is the sister of Z
Hence, → I is the niece of K.
3. How many such pairs of digits are there in the number 421579368 each of which has as many digits between them in the number as when they are arranged in ascending order?
A. 1 B. 2 C. 4 D. 3

Explanation - Given Number: 4 2 1 5 7 9 3 6 8
Ascending order: 1 2 3 4 5 6 7 8 9
Hence the required pairs are 12, 49, 16
4. How many of the following numbers are divisible by 132 ? 264, 396, 462, 792, 968, 2178, 5184, 6336
A. 4 B. 5 C. 6 D. 7

Explanation - 132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 $\rightarrow$ 11,3,4 (/)
396 $\rightarrow$ 11,3,4 (/)
462 $\rightarrow$ 11,3 (X)
792 $\rightarrow$ 11,3,4 (/)
968 $\rightarrow$ 11,4 (X)
2178 $\rightarrow$ 11,3 (X)
5184 $\rightarrow$ 3,4 (X)
6336 $\rightarrow$ 11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
5. In a certain code ‘MONARCHY’ is written as ‘NPOBSDIZ’. How will ‘STANDARD’ be written in that code?
A. UUBOEBSE B. TSSOEBSE C. TUBOPBSE D. TUBOEBSE

Explanation - In this question, each letter of ‘MONARCHY’ is simply replaced by its next letter as per English Alphabet.
M + 1 = N;
O + 1 = P;
N + 1 = O;
A + 1 = B;
R + 1 = S;
C + 1 = D;
H + 1 = I;
Y + 1 = Z.
Based on similar pattern, code for ‘STANDARD’ is ‘TUBOEBSE’.

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