# Time and Work – Quiz 8

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# Time and Work – Quiz 8

### Introduction

Time and Work is one of important topic in Quantitative Aptitude Section. In Time and Work – Quiz 8 article candidates can find questions with answer. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams. Time and Work – Quiz 8 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.

### Q1

(x - 2) men can do a piece of work in x days and (x + 7) men can do 75% of the same work in (x - 10)days. Then in how many days can (x + 10) men finish the work?
A. 11 days B. 12 days C. 13 days D. 14 days

B
$\frac {3}{4}$ × (x − 2) x = (x + 7)(x − 10)
⇒${x}^{2}$ − 6x − 280 = 0
⇒ x = 20 and x =-14
so, the acceptable values is x = 20
Therefore, Total work = (x - 2)x = 18 x 20 = 360 unit
Now 360 = 30 x k
⇒ k = 12 days

### Q2

A is twice as good a workman as B and is therefore able to finish a piece of work in 30 days less than B.In how many days they can complee the whole work; working together?
A. 20 days B. 30 days C. 40 days D. 10 days

A
Ratio of times taken by A and B = 1 : 2.
The time difference is (2 - 1) 1 day while B take 2 days and A takes 1 day.
If difference of time is 1 day, B takes 2 days.
If difference of time is 30 days, B takes 2 x 30 = 60 days.
So, A takes 30 days to do the work.
A's 1 day's work = $\frac {1}{30}$
B's 1 day's work = $\frac {1}{60}$
(A + B)'s 1 day's work = $\frac {1}{30} + \frac {1}{60} = \frac {1}{120}$
A and B together can do the work in 20 days.

### Q3

A works twice as fast as B. If B can complete a work in 18 days independently,the number of days in which A and B can together finish the work is:
A. 4 days B. 6 days C. 8 days D. 10 days

B
Ratio of rates of working of A and B = 2 : 1. So, ratio of times taken = 1:2
Therefore, A's 1 day's work = $\frac {1}{9}$
B's 1 day's work = $\frac {1}{18}$
(A+B)'s 1 day's work= $\frac {1}{9} + \frac {1}{18} = \frac {1}{6}$
so, A and B together can finish the work in 6 days

### Q4

A can do a certain work in the same time in which B and C together can do it.If A and B together could do it in 20 days and C alone in 60 days ,then B alone could do it in:
A. 20 days B. 40 days C. 50 days D. 60 days

D
(A + B)'s 1 day's work = $\frac {1}{30}$
C's 1 day work = $\frac {1}{60}$
(A + B + C)'s 1 day's work = $\frac {1}{20} + \frac {1}{60} = \frac {1}{15}$
Also A's 1 day's work = (B + C)'s 1 day's work
Therefore, we get: 2 x (A's 1 day 's work) = $\frac {1}{15}$
$\Rightarrow$ A's 1 day's work = $\frac {1}{30}$
Therefore, B's 1 day's work = $\frac {1}{20} - \frac {1}{30} = \frac {1}{60}$
So, B alone could do the work in 60 days.

### Q5

A is thrice efficient as B and C is twice as efficient as B. what is the ratio of number of days taken by A,B and C, when they work individually?
A. 2 : 6 : 3 B. 2 : 3 : 6 C. 1 : 2 : 3 D. 3 : 1 : 2

A
Ratio of efficiency A : B : C
Ratio of efficiency 3 : 1 : 2
Ratio of No.of days $\frac {1}{3}$ : $\frac {1}{1}$ : $\frac {1}{2}$
or 2 : 6 :3
Hence A is correct.

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