# Speed and Time – Quiz 4

Home > > Tutorial
5 Steps - 3 Clicks

# Speed and Time – Quiz 4

### Introduction

Speed and Time is one of important topic in Quantitative Aptitude Section. In Speed and Time – Quiz 4 article candidates can find questions with an answer. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams. Speed and Time – Quiz 4 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.

### Q1

A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ?
A. 5 kmph B. 7 kmph C. 3 kmph D. 4 kmph

D
Speed of Man = 4.5 kmph
Speed of stream = 1.5 kmph
Speed in DownStream = 6 kmph
Speed in UpStream = 3 kmph
Average Speed = $\frac {(2 x 6 x 3)}{9}$ = 4 kmph.

### Q2

A man in a train notices that he can count 41 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?
A. 60 km/hr B. 100 km/hr C. 110 km/hr D. 120 km/hr

D
Number of gaps between 41 poles = 40
So total distance between 41 poles = 40 $\times$ 50
= 2000 meter = 2 km
In 1 minute train is moving 2 km/minute.
Speed in hour = 2 $\times$ 60 = 120 km/hour

### Q3

A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is
A. 30 B. 36 C. 40 D. 42

C
Let distance = x km and usual rate = y kmph.
Then, $\frac {X}{Y}$ - $\frac {X}{(y+3)}$ = $\frac {40}{60} \rightarrow$ 2y (y+3) = 9x ----- (i)
Also, $\frac {X}{(Y - 2)}$ - $\frac {X}{Y}$ = $\frac {40}{60} \rightarrow$ y(y-2) = 3x -------- (ii)
On dividing (i) by (ii), we get:
x = 40 km.

### Q4

A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles
A. 60bm/c B. bm/60c C. bc/60m D. 60b/cm

B
Substitute sensible numbers and work out the problem. Then change the numbers back to letters. For example if the machine puts 6 caps on bottles in 2 minutes, it will put $\frac {6}{2}$ caps on per minute, or ($\frac {6}{2}$) x 60 caps per hour. Putting letters back this is 60c/m.If you divide the required number of caps (b) by the caps per hour you will get time taken in hours. This gives bm/60c

### Q5

P is faster than Q. P and Q each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, P's speed is equal to ?
A. 3 km/hr B. 4 km/hr C. 5 km/hr D. 6 km/hr

B
Let P's speed = x km/hr.
Then, Q's speed = (7 - x) km/ hr.
So, $\frac{24}{x}$ + $\frac{24}{(7 - x)}$ = 14
${x}^{2}$ - 98x + 168 = 0
(x - 3)(x - 4) = 0 => x = 3 or 4.
Since, P is faster than Q,
so P's speed = 4 km/hr and Q's speed = 3 km/hr.