Calendar Quiz 5

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Calendar Quiz 5

Introduction

Calendar deals with odd days, leap year, ordinary year, counting of odd days, and day of the week related to odd days. To find the day of the week on a given date concept of odd days is used. The article Calendar Quiz 5 lists important Calendar practice questions for competitive exams like RRB ALP/Technical Exams/Junior Engineer Recruitment Exams, SSC, IBPS PO Exams and etc.

Concepts

Odd days: Extra days, apart from the complete weeks in given periods are called odd days.
Leap year: A leap year is divisible by 4 except for a century. For a century to be a leap year, it must be divisible by 400.
Examples:
Years like 1988, 2008 are leap year (divisible by 4).
Centuries like 2000, 2400 are leap year ( divisible by 400).
Years like 1999, 2003 are not leap year (not divisible by 4).
Centuries like 1700, 1800 are not leap year ( not divisible by 400).
In a century, there is 76 ordinary year and 24 leap year.

Ordinary year: Ordinary year is other than leap years. A ordinary year has 365 days.
Counting of odd days: (i) 1 ordinary year = 365 days = (52 weeks + 1 day).
An ordinary year has one odd day.
(ii) 1 leap year = 366 days = (52 weeks + 2 days). A leap year has 2 odd days.
Day of the week related to odd days: Let the number of days be 0, 1, 2, 3, 4, 5 , 6 and their days are Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday respectively.

Q1

January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008 ?
A. Monday B. Tuesday C. Wednesday D. Sunday

B
The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2007 was Monday.
1st day of the year 2008 will be 1 day beyond Monday.
Hence, it will be Tuesday.

Q2

The calendar for the year 2007 will be the same for the year:
A. 2014 B. 2016 C. 2017 D. 2018

D
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
 Year 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day 1 2 1 1 1 2 1 1 1 2 1

Sum = 14 odd days = 0 odd day.
i.e, Calendar for the year 2018 will be the same as for the year 2007.

Q3

How many days are there in x weeks x days ?
A. 7X B. 8X C. 14X D. 7

B
x weeks x days = (7x + x) days = 8x days.

Q4

On August 29, 2007 Ramesh celebrates his 2nd Birthday. What was the day
A. Tuesday B. Monday C. Thursday D. Wednesday

D
29th August 2007 = (2006 years + Period from 1st January 2007 to 29th August 2007)
Counting of odd days:
2000 years have 0 odd day.
2001 to 2006 has 5 ordinary years and 1 leap year
i.e, 5 + 2 = 7 odd day = 0 odd day
 Jan Feb Mar Apr May June July Aug 31 28 31 31 30 30 31 29

= 241 days = 34 weeks 3 days = 3 odd days.
Total No. of odd days = 0 + 0 + 3 = 3 odd days
August 29th 2007 falls on Wednesday

Q5

January 1, 2008 is Tuesday. What day of the week lies on Jan. 1, 2009 ?
A. Monday B. Wednesday C. Thursday D. Sunday

C
The year 2008 is a leap year. So, it has 2 odd days.
1st day of the year 2008 is Tuesday (Given)
So, 1st day of the year 2009 is 2 days beyond Tuesday.
Hence, it will be Thursday.