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Mensuration – Quiz 6

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Mensuration – Quiz 6

shape Introduction

Mensuration is one of important topic in Quantitative Aptitude Section. In Mensuration – Quiz 6 article candidates can find questions with answer. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams. Mensuration – Quiz 6 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.

shape Q1

The length of the longest rod that can be placed in a room which is 12 m long, 9 m broad and 8 m high is
    A. 27 m B. 19 m C. 17 m D. 13 m

SPLessons

Length of the longest rod = Diagonal of the room
= [latex]\sqrt{{12}^{2} + {9}^{2} + {8}^{2}} [/latex]
[latex]\sqrt{289} [/latex] = 17 m

shape Q2

The cross-section of a canal is in the form of a trapezium. If canal top is 10 m wide, the bottom is 6 m wide and area of the cross section is 72 m^2, then depth of the canal is
    A. 10 m B. 7 m C. 6 m D. 9 m

SPLessons

Let h the height of the trapezium
Hence area of cross-section of the channel in the form of trapezium
[latex]\frac{1}{2}[/latex](10 + 6) * h = 72
i.e, 8h = 72
h = 9 m

shape Q3

A steel wire bent in the form of a square of area 121 [latex] {cm}^{2}[/latex]. If the same wire is bent in the form of a circle, then the area of the circle is
    A. 130 B. 136 C. 154 D. None of these

SPLessons

Side of a square = [latex]\sqrt{121} [/latex] = 11 cm
i.e, Perimeter of circle = 4 * 11 = 44 cm
2πr = 44
where r is radius of the circle
i.e, 2 * [latex]\frac{22}{7}[/latex] * r = 44
r = 7 cm
i.e, Area of the circle = π[latex] {r}^{2}[/latex] = [latex]\frac{22}{7} * {7}^{2} = 154{cm}^{2} [/latex]

shape Q4

The diameter of a garden roller is 1.4 m and it is 2 m long. How much area will it cover in 5 revolutions ?
    A. 40 B. 44 C. 48 D. 36

SPLessons

Garden roller is in the form of a cylinder whose radius is 0.7 m and height is 2 m.
i.e, Area covered in 5 revolutions
= 5 * 2πrh
= 5 * 2 * [latex]\frac{22}{7}[/latex] * 0.7 * 2
= 44 [latex]{m}^{3}[/latex]

shape Q5

A bicycle wheel makes 5000 revolutions in moving 11 km. Find diameter of the wheel
    A. 55 cm B. 60 cm C. 65 cm D. 70 cm

SPLessons

Circumference of the wheel = 2πr = [latex]\frac{11000 metres}{5000}[/latex]
πr = [latex]\frac{11}{10}[/latex]
r = [latex]\frac{11}{10} * \frac{7}{22} = \frac{7}{20}[/latex]metre
[latex]\frac{7}{20} * 100 [/latex] = 35 cm
Diameter of the wheel = 70 cm.
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