Dogs – B, D, F, H, L and M
1. Distance between F and H is 60m and only two dogs stand between them.
Case 1:
Case 2:
Let distance between two dogs be 4x as all the distance are consecutive integral multiple of 4.
4x + 4x + 4 + 4x + 8 = 60
12x + 12 = 60
12x = 48
x = 4
Hence, distance are 16, 20, 24.
2. L sits immediate left of F.
Case 1:
Case 2:
3. B sits somewhere to the right of L and distance between them is in multiple of six. Distance between F and D is 44m.
Case 1:
Distance between B and L must be multiple of 6. There is only one possibility as 12 + 16 + 20 = 48 which is multiple of 6.
Distance between F and D is 44m which is not possible in this case.
Case 2:
Distance between B and L must be multiple of 6. There is only one possibility as 24 + 28 + 32 = 84 which is multiple of 6. Distance between F and D is 44m.
4. Dog B starts moving towards east, after moving 12m, it turns to its right and moves 60m. From there after turning to its left and walking for a distance of 5m, it comes to halt at a point V. Dog L moves in north direction for a distance of 20m and them turn to ts left and moves 26m. After taking one more turn to its left it stops at a point W after walking 5M.