# Direction Sense – Quiz 2

Home > > Tutorial
5 Steps - 3 Clicks

# Direction Sense – Quiz 2

### Introduction

What is Direction Sense Test? Direction Sense TestVerbal Reasoning Questions and Answers. … The main objective of these questions is to test the candidate’s ability to identify the direction in respect of a person who has moved in different directions from his original position.
Direction Sense is one of important topic in Reasoning Ability Section. In Direction Sense – Quiz 2 article candidates can find questions with an answer. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams. Direction Sense – Quiz 2 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.

### Q1

A boy rode his bicycle Northward, then turned left and rode 1 km and again turned left and rode 2 km. He found himself 1 km west of his starting point. How far did he ride northward initially?
A. 1 km B. 2 km C. 3 km D. 5 km

B

The boy rode 2 km. Northward.

### Q2

K is 40 m South-West of L. If M is 40 m South-East of L, then M is in which direction of K?
A. East B. West C. North-East D. South

A

Hence M is in the East of K.

### Q3

Golu started from his house towards North. After covering a distance of 8 km. he turned towards left and covered a distance of 6 km. What is the shortest distance now from his house?
A. 10 km. B. 16 km. C. 14 km. D. 2 km

A

Required distance = AC
= $\sqrt {{8}^{2} + {6}^{2}}$
= $\sqrt {64 + 36}$
= $\sqrt {100}$
= 10 km

### Q4

X started to walk straight towards south. After walking 5 m he turned to the left and walked 3 m. After this he turned to the right and walked 5 m Now to which direction X is facing?
A. North-East B. South C. North D. South-West

B

Hence X will face in the end towards South.

### Q5

The length and breadth of a room are 8 m and 6 m respectively. A cat runs along all the four walls and finally along a diagonal order to catch a rat. How much total distance is covered by the cat?
A. 10 B. 14 C. 38 D. 48

C

Required distance = 8 + 6 + 8 + 6 + $\sqrt {{8}^{2} + {6}^{2}}$
= 28 + $\sqrt {64 + 36}$
= 28 + $\sqrt {100}$
= 28 + 10 km = 38 km