# Speed and Time – Quiz 3

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# Speed and Time – Quiz 3

### Introduction

Speed and Time is one of important topic in Quantitative Aptitude Section. In Speed and Time – Quiz 3 article candidates can find a question with an answer. By solving this question candidates can improve and maintain, speed, and accuracy in the exams. Speed and Time – Quiz 3 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.

### Q1

A man traveled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village ?
A. 40 km B. 30 km C. 20 km D. 10 km

C
Average speed = $\frac {2ab}{a + b}$, here a = 25 b = 4
= 2 x 25 x $\frac {4}{(25 + 4)}$ = $\frac {200}{29}$ km/hr.
Distance covered in 5 hours 48 minutes
= Speed x time = ($\frac {200}{29}$)x ($\frac {29}{5}$) Distance covered in 5 hours 48 minutes = 40 kms.
Distance of the post office from the village = ($\frac {40}{2}$) = 20 km.

### Q2

Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
A. 15 hours B. 16 hours C. 17 hours D. 18 hours

C
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5 kmph – 5 kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = $\frac {dist}{speed}$
Time= $\frac {8.5 km}{ 0.5 kmph }$ = 17 hrs

### Q3

A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ?
A. 20 km B. 16 km C. 14 km D. 10 km

D
Let distance = x km.
Time taken at 3 kmph : $\frac {dist}{speed}$ = $\frac {x}{3}$ = 20 min late.
time taken at 4 kmph : $\frac {x}{4}$ = 30 min earlier
difference between time taken : 30 -(-20) = 50 mins = $\frac {50}{60}$ hours.
$\frac {x}{3}$ - $\frac {x}{4}$ = $\frac {50}{60}$
$\frac {x}{12}$ = $\frac {5}{6}$
x = 10 km.

### Q4

A train covers a distance in 50 minutes, if it runs at a speed of 48 kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
A. 50 km/hr B. 60 km/hr C. 65 km/hr D. 70 km/hr

B
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Time = $\frac {50}{60}$ hr = $\frac {5}{6}$ hr
Speed = 48 mph
Distance = S $\times$ T = 48 $\times \frac {5}{6}$ = 40 km
New time will be 40 minutes so,
Time = $\frac {40}{60}$ hr = $\frac {2}{3}$ hr
Now we know,
Speed = $\frac {distance}{time}$
New speed = $\frac {40 \times 3}{2}$ kmph = 60 kmph

### Q5

The distance from town A to town B is five miles. C is six miles from B. Which of the following could be the maximum distance from A to C?
A. 11 B. 8 C. 2 D. 4

A
Do not assume that AB and C are on a straight line. Make a diagram with A and B marked 5 miles apart. Draw a circle centered on B, with radius 6. C could be anywhere on this circle. The minimum distance will be 1, and maximum 11