Introduction
Speed and Time is one of important topic in Quantitative Aptitude Section. In Speed and Time Quiz 12 article candidates can find questions with answer. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams. Speed and Time Quiz 12 questions are very useful for different exams such as IBPS PO, Clerk, SSC CGL, SBI PO, NIACL Assistant, NICL AO, IBPS SO, RRB, Railways, Civil Services etc.
Q1
How many seconds does Puja take to cover a distance of 500 m, if she runs at a speed of 30 km/hr?
- A. 60 sec
B. 82 sec
C. 95 sec
D. 100 sec
Hint:
Time = [latex]\frac {Distance}{Speed}[/latex]
We see that the distance is given in metres while the speed is given in km/hr and the answer is asked in seconds.
So, convert km/hr into m/s by multiplying [latex]\frac {5}{18}[/latex] m/s to the given value of speed.
[latex]30 \frac {km}{hr} = 30 \times \frac {5}{18} =\frac {75}{9} m/sec [/latex]
i.e. Place these values in the formula:
Time = 500 x [latex]\frac {9}{75} = 60 sec[/latex]
Q2
A cyclist covers a distance of 800 meter in 4 minutes 20 seconds. What is the speed in km/hr of the cyclist?
- A. 6.2 km/h
B. 8.4 km/hr
C. 11.05 km/hr
D. 16.07 km/hr
Speed = [latex]\frac {Distance}{Time}[/latex]
Hint: Convert minutes into seconds
Time= 4 min 20 sec =260 sec
Speed = [latex]\frac {800}{260}[/latex] = 3.07 m/sec
Convert the speed from m/s to km/hr by multiplying with ([latex]\frac {5}{18}[/latex])
3.07 x [latex]\frac {18}{5}[/latex] km/hr = 11.05 km/hr
Q3
A man walking at the rate of 6 km/hr crosses a bridge in 15 minutes. The length of the bridge is ______.
- A. 1000 m
B. 1250 m
C. 1500 m
D. 1800 m
Hint: To find the answer in meter, we will first convert distance from km/hour to meter/sec by multiplying it with [latex]\frac {5}{18}[/latex]. Also, change 15 minutes to seconds by multiplying it with 60.
Distance = Speed x Time
1. Convert speed into m/sec:
[latex]6 \times \frac {5}{18} m/s= 1.66 m/s[/latex]
2. Convert time from minutes into seconds = 15 x 60 s = 900 sec
3. Calculate : Distance = 1.66 x 900 = 1500 m
Q4
P & Q are 275 km apart. A bike rider starts from P towards Q at 8 a.m. at the speed of 25 km/hr. Another rider starts from Q towards P at 9 a.m. at the speed of 20 km/hr. Find at what time they will cross each other?
- A. 2.45 p.m.
B. 2.30 p.m.
C. 1.35 p.m.
D. 1.15 p.m.
Hint: We have read, relative speed between two bodies moving in opposite direction: SR = S1 + S2
Assume, distance traveled by P in x hrs = 25 x km -----(1)
distance traveled by Q in (x-1) hrs = 20 (x-1) km -----(2)
Adding (1) & (2),
25 x + 20 (x -1) = 275
x = 6.5 hrs
(x -1) = (6.5 -1) = 5.5 hrs
Time at which they cross each other = 9 a.m. + 5.5hrs = 2.30 p.m.
The two motorcycle riders cross each other at 2.30 p.m.
Q5
Jennifer travels first 4 hours of her journey at a speed of 80 miles/hr and the remaining distance in 6 hours at a speed of 30 miles/hr. What is her average speed in miles/hr?
- A. 50 miles / hr
B. 60 miles/hr
C. 75 miles/hr
D. 92 miles/hr
Hint : If time and speed are given then the average speed is calculated by considering the total distance covered and the total time required.
i.e. Average speed = [latex]\frac {Total Distance}{Time}[/latex]
Distance =Time x Speed
Total distance covered by Jennifer = Distance covered in first 4 hours + distance covered in next 6 hours
= (80 x 4) + (30 x 6)
= 500 miles / hr
Total time taken to complete the journey = 4 + 6 = 10 hrs
Therefore,
Average Speed = [latex]\frac {Total Distance}{Time}[/latex]
[latex]\frac {500}{10}[/latex]
= 50 miles/hr