A

Let the C.P be Rs.100 and S.P be Rs.x, Then
The profit is (x - 100)
Now the S.P is doubled, then the new S.P is 2x
New profit is (2x - 100)
Now as per the given condition;
=> 3(x - 100) = 2x - 100
By solving, we get
x = 200
S.P = x = 200
gain = 200 - 100 = 100
Then the Profit percent = [latex]\frac {100 \times 100}{100}[/latex] = 100%
Hence the profit percentage is 100%

C

Cost of 4 mangoes = Rs. 6
Cost of 1 mango = Rs. [latex]\frac {6}{4}[/latex] = Rs. 1.5
Now, Selling Price of 4 mangoes = Rs. 4
Selling Price of 1 mango = Rs. [latex]\frac {4}{4}[/latex] = Rs. 1.0
We observe that, S.P < C.P
Hence, the shopkeeper incurs a loss.
Required loss% = [latex]\frac {loss}{C.P x 100}[/latex]
Loss = 1.5 - 1 = 0.5
C.P = 1.5
Loss% = [latex]\frac {0.5}{1.5}\times 100[/latex]
= [latex]\frac {5}{15}\times 100[/latex]
= [latex]\frac {1}{3}\times 100[/latex]
= [latex]\frac {100}{3}[/latex]
= 33.333%.

B

Tota profit percentage = [latex]\frac {119 x 100}{85} - 100 = \frac {3400}{85}[/latex] = 40%

A

From the given data,
The cost price of the article = 5640 x [latex]\frac {100}{60}[/latex] = Rs. 9400
The selling price of the article to gain 25% profit = 9400 x [latex]\frac {125}{100}[/latex] = Rs. 11750.

A

Given the cost price of the articles = Rs. 450
To get overall 20% gain,
Total Selling Price = ([latex]\frac{20}{100}[/latex]) x 450 = 540
One third of the CP = [latex]\frac{1}{3}[/latex] x 450 = Rs. 150
But given [latex]\frac{1}{3}[/latex] of articles are sold at 10% loss
S.P of [latex]\frac{1}{3}[/latex] of articles = 90% of 150
= 90 x [latex]\frac{150}{100}[/latex] = 135
Then, S.P on remaining [latex]\frac {2}{3}[/latex] goods must be
= 450 - 135 = 405 ...........(1)
CP on remaining goods
= [latex]\frac {2}{3}[/latex] x 450 = 300 ............(2)
Profit = SP - CP = 405 - 300 = 105
Profit % = ([latex]\frac {105}{300}[/latex]) x 100
= 35%.