1. A person bought 20 pens at Rs 12 each and sold 5 of them at Rs 10 and other 7 at Rs 14 and remaining at Rs 11. What is the profit/loss percentage ?

A. 1.66% B. 2.33% C. 1.33% D. 2.66%

Answer: Option A
Explanation: Total cost price = 20 × 12 = 240 Total selling price = 5 × 10 + 14 × 7 + 8 × 11 = 50 + 98 + 88 = 236 Loss percent = 240 - [latex]\frac{236}{240}[/latex] × 100 = 1.66%
2. Marked price of an article is Rs 300 and a discount of 20% is given. If profit percent is 20% then what is the cost price ?

A. Rs 210 B. Rs 200 C. Rs 180 D. Rs 220

Answer: Option B
Explanation: MP = 300 SP = MP - discount SP = 300 × [latex]\frac{80}{100}[/latex] SP = 240 Cost price = 240 × [latex]\frac{100}{120}[/latex] Cost price = Rs 200
3. Arif sold his two mobiles for Rs 5000 each without any profit or loss. If he sold one of the mobile at 20% loss then at what profit percent should he sell the other mobile ?

A. 25% B. 20% C. 30% D. 35%

Answer: Option A
Explanation: Total SP = 10000 Cost price of First mobile = 5000([latex]\frac{100}{80}[/latex]) = 6000 Selling price of Second mobile = 5000 Cost price of Second mobile = 10000 - 6000 = 4000 Profit percent = 5000 - [latex]\frac{4000}{4000}[/latex] × 100 = 25%
4. A person purchased 20 apples for Rs 11 each and sold each apple at a different price,every price is between 1 and 20 both inclusive then what is his loss/profit percent?

A. [latex]\frac{50}{11}[/latex] % B. [latex]\frac{40}{11}[/latex] % C. [latex]\frac{60}{11}[/latex] % D. [latex]\frac{70}{11}[/latex] %

Answer: Option A
Explanation: Total Cost price = 20 × 11 = 220 As we have 20 different prices and 20 apples and eah apple is sold at a different price and so Total SP = 1 + 2 + 3 + 4 ….. 20 = [latex]\frac{20(20 + 1)}{2}[/latex] = 210 Loss percent = [latex]\frac{220 - 210}{220}[/latex] × 100 = [latex]\frac{50}{11}[/latex]%
5.The cost price of 40 articles is the same as the selling price of 25 articles. Find the gain per cent

A. 65% B. 60 % C. 15 % D. 75%

Answer: Option B
Explanation: If the cost price of x articles is equal to the selling price of y articles, then the profit percentage = [latex]\frac{x - y}{y}[/latex] × 100%. x is the number of articles the cost price of which is given = 40 y is the number of articles the selling price of which is given = 25 By the short trick approach, we get Gain% = [latex]\frac{40 - 25}{25}[/latex]4×100 = [latex]\frac{15}{25}[/latex] × 100= 60%

1. A shopkeeper gains 17% after allowing a discount of 10% on the marked price of an article. Find his profit percent if the article is sold at marked price allowing no discount.

A. 30% B. 37% C. 23% D. 27%

Answer: Option A
Explanation: [latex]\frac{(x + y)}{100 – y}[/latex] × 100% where x = gain% after allowing the discount = 17%, And y = discount offered on marked price = 10% Now, on putting values of x and y in the short trick approach, we get = [latex]\frac{17 + 10}{100 – 10}[/latex] × 100 = [latex]\frac{27}{90}[/latex] × 100 = 30%.
2. Cost price of 100 books is equal to the selling price of 60 books. The gain percentage or loss percentage is:

A. 66 [latex]\frac{3}{2}[/latex]% B. 67% C. 66% D. 66 [latex]\frac{2}{3}[/latex]%

Answer: Option D
Explanation: To solve this question, now we can apply a short trick approach Gain% or Loss% = [latex]\frac{x – y}{y}[/latex] × 100% x is the number of books the cost price of which is given = 100 y is the number of books the selling price of which is given = 60 By the short trick approach, we get Gain percentage = [latex]\frac{100 – 60}{60}[/latex] × 100% = [latex]\frac{40}{60}[/latex] × 100% = 66 [latex]\frac{2}{3}[/latex]%.
3. List price of a book is Rs 100. A dealer sells three such books for Rs 274.50 after allowing discount at a certain rate. Find the rate of discount.

A. 8.5% B. 8.34% C. 8.33% D. 8.16%

Answer: Option A
Explanation: Discount% = CP – SP × 100% CP = [latex]\frac{300 – 274.50 }{300}[/latex] × 100 = [latex]\frac{25.50}{3}[/latex] = 8.5%.
4. The printed price of an article is 40% higher than its cost price. Then the rate of discount so that he gains 12% profit is:

A. 21% B. 18% C. 20% D. 15%

Answer: Option C
Explanation: Let's assume CP = 100, therefore MP = 140 and SP = 112. Discount% = [latex]\frac{MP – SP}{MP}[/latex] × 100% {As discount is always calculated on Marked Price.} = [latex]\frac{140 – 112}{140}[/latex] × 100 = [latex]\frac{28 × 100}{140}[/latex] = 20%.
5. Mohan sold his watch at 10% loss. If he had sold it for Rs. 45 more, he would have made 5% profit. The selling price (in Rs.) of watch was

A. 300 B. 900 C. 110 D. 270

Answer: Option D
Explanation: Let the original SP = x Therefore, new SP = (x + 45) New SP = [latex]\frac{100 + Profit%}{100 – Discount%}[/latex] × old SP ⇒ [latex]\frac{(x + 45)}{100 – 10}[/latex] = 100 + 5 × x ⇒ [latex]\frac{(x + 45)}{90}[/latex] = 105 × x ⇒ 90x + 90 × 45 = 105x ⇒ 15x = 90 × 45 ⇒ x = [latex]\frac{90 × 45}{15}[/latex] = 270.

1. A vendor loses the selling price of 4 oranges on selling 36 oranges. His loss per cent is

A. 12 [latex]\frac{1}{2}[/latex]% B. 9% C. 10% D. 11 [latex]\frac{1}{2}[/latex]%

Answer: Option C
Explanation: Given, In case of loss, 36 CP – 36 SP = 4 SP ⇒ 36 CP = 40 SP To solve this question now, we can apply a short trick approach Gain% or Loss% = [latex]\frac{x – y}{y}[/latex] × 100% x is the number of oranges the cost price of which is given = 36 y is the number of oranges the selling price of which is given = 40 By the short trick approach, we get Loss% = [latex]\frac{36 – 40}{40}[/latex] × 100% = [latex]\frac{–4}{40}[/latex] × 100% = – 10%.
2.The total discount on Rs. 1860 due after a certain time at 5% is Rs. 60. Find the time after which it is due

A. 9 months B. 10 months C. 8 months D. 7 months

Answer: Option C
Explanation: Amount (A) = 1860/-, True Discount = 60/-, Rate of interest (R) = 5% Time (T) = 100 ×[latex]\frac{TD}{(A – TD) × R}[/latex] = 100 × [latex]\frac{60}{(1860 – 60) × 5 1800 × 5}[/latex] ⇒ T = [latex]\frac{100 × 60}{3}[/latex] = 2 years Total months = [latex]\frac{12 × 2}{3}[/latex] = 8 months.
3. Simon purchased a bicycle for Rs. 6810. He had paid a VAT of 13.5%. The list price of the bicycle was

A. Rs. 5970.50 B. Rs. 6696.50 C. Rs. 6000 D. Rs. 6140

Answer: Option C
Explanation: let's take the original price (list price) of the bicycle be x, then 113.5% of x = 6810 ⇒ x = [latex]\frac{6810 × 100}{113.5}[/latex] = [latex]\frac{6810 × 1000}{1135}[/latex] = 6000/-
4. There is 10% loss if an article is sold at Rs. 270. Then the cost price of the article is

A. Rs. 320 B. Rs. 300 C. Rs. 270 D. Rs. 250

Answer: Option B
Explanation: let's take CP = x, then 90% of x = 270 ⇒ x = [latex]\frac{270 × 100}{90}[/latex] = 300/-
5. An article is sold at a gain of 15%. Had it been sold for ₹ 27 more, the profit would have been 20%. The cost price of the article is

A. Rs. 500 B. Rs. 700 C. Rs. 540 D. Rs. 545

Answer: Option C
Explanation: Let the CP of article be Rs x, then 120% of x – 115% of x = 27 ⇒ 5% of x = 27 ⇒ x = [latex]\frac{27 × 100}{5}[/latex] = Rs. 540