1. If Rs.450 amount to Rs.540 in 4 years, what will it amount to in 6 years at the same rate % per annum?

A. Rs.575 B. Rs.675 C. Rs.585 D. Rs.685

Answer: Option C
Explanation: 90 = latex]\frac {(450*4*R)}{100}[/latex] R = 5% I = [latex]\frac {(450*6*5)}{100}[/latex] = 135 450 + 135 = 585
2. The area of a base of a cone is 30 cm[latex]^ {2}[/latex]. If the height of the cone is 6cm, find its volume?

A. 120 cm[latex]^ {3}[/latex] B. 40 cm[latex]^ {3}[/latex] C. 50 cm[latex]^ {3}[/latex] D. 60 cm[latex]^ {3}[/latex]

Answer: Option D
Explanation: πr[latex]^ {2}[/latex] = 30 h = 6 [latex]\frac {1}{3}[/latex] * 30 * 6 = 60.
3. Ratan takes turns to cycle around the circular garden and through the diameter of the garden on alternate days. His speed each day is 6m/min but when he cycles through the diameter, he takes 1 hr less to cross the park. Find the diameter of the park.

A. 1530 m B. 1680 m C. 1750 m D. 3600 m

Answer: Option B
Explanation: We know that, Time =[latex]\frac {Distance}{Speed}[/latex] Speed = 60m/min = [latex]\frac {60}{60}[/latex] m/sec = 1 m/sec We know that, Time along the park (circumference) - Time along the diameter = 60 minutes ∴[latex]\frac {2πr}{1}[/latex] - [latex]\frac {2r}{1}[/latex] = 60 minutes ∴ 2r ([latex]\frac {22}{7}[/latex]- 1) = 3600 seconds ∴ r = 840m ∴ Diameter = 2 x radius = 1680m.
4. In what time a sum of money double itself at 3% per annum simple interest?

A. 29 years B. 33 1/3 years C. 23 1/3 years D. 13 1/3 years

Answer: Option B
Explanation P = (P*3*R)/100 R = 33 1/3%
5. For a rectangular box, what is the product of the areas of the 3 adjacent faces that meet at a point?

A. The volume of the box B. Twice the volume of the box C. Half of the volume of the box D. Square of the volume of the box

Answer: Option D
Explanation: The area of the 3 adjacent faces of a rectangular box of length ‘l’, breadth ‘b’, and depth ‘h’ are ‘l*b’, ‘b*h’, and ‘l*h’. Therefore, lb*bh*lh = l[latex]^ {2}[/latex] b[latex]^ {2}[/latex] h[latex]^ {2}[/latex] = (lbh)[latex]^ {2}[/latex] = square of the volume of the box.

1. Which of the following statements is not correct?

A. [latex]log_{10}[/latex] 10 = 1 B. log (2 + 3) = log (2 x 3) C. [latex]log_{10}[/latex] 1 = 0 D. log (1 + 2 + 3) = log 1 + log 2 + log 3

Answer: Option B
Answer: Option A. Since [latex]log_{a}[/latex] a = 1, so [latex]log_{10}[/latex] 10 = 1. B. log (2 + 3) = log 5 and log (2 x 3) = log 6 = log 2 + log 3 log (2 + 3) ≠ log (2 x 3) C. Since [latex]log_{a}[/latex] 1 = 0, so [latex]log_{10}[/latex] 1 = 0. D. log (1 + 2 + 3) = log 6 = log (1 x 2 x 3) = log 1 + log 2 + log 3. So, B is incorrect.
2. If in a game of 80, P can give 16 points to Q and R can give 20 points to P, then in a game of 150, how many points can R give to Q?

A. 48 B. 60 C. 54 D. 90

Answer: Option B
Answer: Option When P scores 80, Q scores 64. When R scores 80, P scores 60 Hence, when R scores 150, Q scores (60 * 64 * 150) / (80 * 80) = 90 Therefore, in a game of 150, R can give 60 points to Q.
3. In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for?

A. 160 B. 175 C. 180 D. 195

Answer: Option B
Explanation: Suppose the man works overtime for x hours. Now, working hours in 4 weeks = (5 x 8 x 4) = 160. 160 x 2.40 + x x 3.20 = 432 3.20x = 432 - 384 = 48 x = 15. Hence, total hours of work = (160 + 15) = 175.
4. Two cars cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car.

A. 906 km B. 960 m C. 960 km D. 966 km

Answer: Option C
Explanation 60(x + 1) = 64x X = 15 60 * 16 = 960 km
5. 5 mat-weavers can weave 5 mats in 5 days. At the same time, how many mats would be woven by 10 mat- weavers in 10 days?

A. 10 mats B. 15 mats C. 20 mats D. 30 mats

Answer:
Explanation More mats are weaved if more weavers work. Hence, this problem is related to a direct proportion. Let the required number of mats be x. Total 5 mats can be weaved in 5 days by 5 weavers. \[5: x:: \begin{cases} 5 : 10 - - - (Weavers)\\ 5 : 10 - - - (Days) \end{cases} \] 5 × 5 × x = 10 × 10 × 5 x = [latex]\frac {10 \times 10 \times 5}{5 \times 5}[/latex] = 20 20 mats can be weaved in 10 days by 10 mat weavers.

1. The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?

A. 720 B. 144 C. 120 D. 36 E. 204

Answer: Option B
Explanation The word MEADOWS has 7 letters of which 3 are vowels. -V-V-V- As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways. Hence the total ways are 24 * 6 = 144.
2. Find the one which does not belong to that group ?

A. 27 B. 37 C. 47 D. 67

Answer: Option A
Explanation: 37, 47, 67 and 17 are prime numbers but not 27
3. (1331)[latex]^ {– (2/3)}[/latex]

A. –[latex]\frac {1}{11}[/latex] B. –[latex]\frac {11}{121}[/latex] C. [latex]\frac {1}{121}[/latex] D. [latex]\frac {121}{11}[/latex]

Answer: Option C
Explanation Cube root of 1331 is 11. Therefore, (11)[latex]^ {(3)\times – (2/3)}[/latex] Remember the law of indices (x[latex]^ {(m){n}}[/latex]) = x[latex]^ {mn}[/latex] (11)[latex]^ {– 3 \times (2/3)}[/latex] = 11[latex]^ { –2}[/latex] x[latex]^ {–1 }[/latex]=[latex]\frac {1}{x}[/latex] Hence, 11[latex]^ {–2}[/latex] = [latex]\frac {1}{11^{2}}[/latex] = [latex]\frac {1}{121}[/latex]
4. Two pipes can fill a tank in 10 and 14 minutes respectively and a waste pipe can empty 4 gallons per minute. If all the pipes working together can fill the tank in 6 minutes, what is the capacity of the tank?

A. 120 gallons B. 240 gallons C. 450 gallons D. 840 gallons

Answer: Option D
Explanation Work done by waste pipe in 1 min = (Part filled by total pipes together) -(part filled by first pipe + part filled by second pipe) = 1/6 – [([latex]\frac {1}{10}[/latex] ) + ([latex]\frac {1}{14}[/latex] )] = [latex]\frac {1}{6}[/latex] – ([latex]\frac {24}{140}[/latex] ) = [latex]\frac {-1}{210}[/latex] Here, negative (-) sign indicates emptying of tank. To find the capacity, we need to determine the volume of 1/210 part. Therefore, volume of [latex]\frac {1}{210}[/latex] part = 4 gallons ---------(given condition) Hence, the capacity of tank = volume of whole = 4 x 210 = 840 gallons.
5. A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?

A. 10 kmph B. 5 kmph C. 20 kmph D. 22 kmph

Answer: Option C
Explanation M = 15 S = 5 DS = 15 + 5 = 20