1. In an examination, Mani scored 45% marks and failed by 18 marks. In the same examination, Radhika scored 54% marks and get 27 marks more than the passing marks. What is the score of Mohan in the same examination, who secured 75 % marks?

A. 420 B. 440 C. 375 D. 360

Answer: Option C
Explanation: Here passing marks equal. So, = > 45 % of total marks + 18 = 54 % of total marks – 27 = > 18 + 27 = (54 – 45) % of total marks = > 45 = 9 % of total marks = > Total marks = 45*([latex]\frac{100}{9}[/latex]) = 500 Mohan’s mark = ([latex]\frac{75}{100}[/latex])*500 = 375
2. Raja’s monthly salary is equal to 48 % of Anu’s monthly salary. Anu’s monthly salary is Rs. 24000 less than Baghya’s monthly salary. If Baghya’s monthly salary is Rs. 48000. What is Raja’s annual salary?

A. Rs. 138240 B. Rs. 125650 C. Rs. 107860 D. Rs. 142780

Answer: Option A Raja’s monthly salary = (48/100)*Anu’s monthly salary Anu’s monthly salary = > Baghya’s monthly salary – 24000 = > 48000 – 24000 = 24000 Raja’s monthly salary = ([latex]\frac{48}{100}[/latex])* 24000 = 11520 Raja’s annual salary = 11520*12 = Rs. 138240
3. Ramesh scored 430 marks in an examination and Savitha got 72 percent marks in the same examination which is 70 marks less than Ramesh. If the minimum passing marks in the examination is 35 percent, then find the minimum passing marks in the examination?

A. 200 B. 160 C. 225 D. 175

Answer: Option D
Explanation: Ramesh’s score = 430 Savitha got 72 percent marks in the same examination which is 70 marks less than Ramesh. = > 72 % of total marks = 430 – 70 = > (72/100)*Total marks = 360 = > Total marks = 360*([latex]\frac{100}{72}[/latex]) = 500 Passing mark = ([latex]\frac{35}{100}[/latex])*500 = 175
4. Out of the total monthly salary of Mahesh, he spends 25% of his monthly salary on Rent and 20 % on travel expenses. 40 % of the remaining monthly salary for food and while the remaining salary is saved which is equal to Rs. 16500, then find his monthly salary?

A. Rs. 45000 B. Rs 50000 C. Rs. 60000 D. Rs. 40000

Answer: Option B
Explanation: Let the monthly salary of Mahesh be x, X*(55/100)*([latex]\frac{60}{100}[/latex]) = 16500 X = 16500*([latex]\frac{100}{55}[/latex])*(100/60) X = Rs. 50000 The monthly salary of Mahesh = Rs. 50000
5. In a Town, 62% of the population is male and remaining are females. Out of the males, 74% are literate and remaining is illiterate. Out of females, 65% are literate and remaining is illiterate. If the total number of illiterate population is 29420, then the population of the town is?

A. 125000 B. 113000 C. 128000 D. 100000

Answer: Option D
Explanation: Males = 62% Females = 38% Let the population of the town be x, According to the question, ([latex]\frac{62}{100}[/latex]) * x * (26/100) + ([latex]\frac{38}{100}[/latex]) * x * ([latex]\frac{35}{100}[/latex]) = 29420 => [latex]\frac{403x}{2500}[/latex] + [latex]\frac{133x}{100}[/latex] = 29420 => [latex]\frac{1471x}{5000}[/latex] = 29420 = > x = 29420*[latex]\frac{5000}{1471x}[/latex] => x = 100000 The population of the town is 100000

6. The monthly income of Santhosh and Vignesh together is Rs. 62500. The income of Santhosh and Vignesh is increased by 20% and 15% respectively. The new income of Vignesh is Rs. 1375 more than the new income of Santhosh. What is the new income of Vignesh?

A. Rs. 37375 B. Rs. 35625 C. Rs. 36500 D. Rs. 38250

Answer: Option A
Explanation: Let the income of Santhosh and Vignesh be S and V, The monthly income of Santhosh and Vignesh = 62500 S + V = 62500 Santhosh’s income = x; Vignesh’s income = 62500 – x New income of V = New income of S + 1375 V’s new income = (62500 – x)*[latex]\frac{115}{100}[/latex] S’s new income = x * [latex]\frac{120}{100}[/latex] (62500 – x)* ([latex]\frac{115}{100}[/latex]) = x * ([latex]\frac{120}{100}[/latex]) + 1375 [latex]\frac{(7187500 – 115x)}{100}[/latex] = ([latex]\frac{120X}{1471x}[/latex]) + 1375 [latex]\frac{(7187500 – 115x)}{100}[/latex] = [latex]\frac{(120x + 137500)}{100}[/latex] (7187500 – 115x) = (120x + 137500) 7187500 – 137500 = 115x + 120x 7050000 = 235x Santhosh’s income X = [latex]\frac{7050000}{235}[/latex] = 30000 Vignesh’s income = 62500 – x = 32500 New Income of Vignesh = 32500*([latex]\frac{115}{100}[/latex]) = Rs. 37375
7. In a class 125 students, if the ratio of boys and girls in a class is 3: 2. If 24% of the boys and 20% of the girls are interested in dance, then find the % of students who are all not interested in dance?

A. 72.5 % B. 75.8 % C. 6 % D. 65.6 %

Answer: Option C
Explanation: Total no of students = 125 The ratio of boys and girls in a class = 3: 2 (3x, 2x) Boys = 125*([latex]\frac{3}{5}[/latex]) = 75, Girls = 125*([latex]\frac{2}{5}[/latex]) = 50 24% of boys interested in dance = 75 * [latex]\frac{24}{100}[/latex] = 18 20% of girls interested in dance = 50 * [latex]\frac{20}{100}[/latex] = 10 Total number of students, who are all not interested in dance, = > 125 – (18 + 10) = 125 – 28 = 97 Required % = ([latex]\frac{97}{125}[/latex]) * 100 = 77.6 %
8. The cost of a camera is Rs. 3500 more than that of a phone. 3 phone and 3 camera cost is Rs. 70500. Find the cost of a camera?

A. Rs. 14000 B. Rs. 13500 C. Rs. 15500 D. Rs. 12500

Answer: Option B
Explanation: Let the cost of a phone be Rs. x The cost of a camera = x + 3500 3*(x + 3500) + 3x = 70500 3x + 10500 + 3x = 70500 6x + 10500 = 70500 6x = 70500 – 10500 X = [latex]\frac{60000}{6}[/latex] X = 10000 The cost of a phone = Rs. 10000 The cost of a camera = Rs. (10000 + 3500) = Rs. 13500
9. 15 % of monthly salary of P is equal to 30% of monthly salary of Q and 20 % of monthly salary of Q is equal to 30 % of monthly salary of R. If R’s monthly income is Rs. 40000, then the total income of P, Q and R is?

A. Rs. 227500 B. Rs. 235800 C. Rs. 215000 D. Rs. 220000

Answer: Option D
Explanation: [latex]\frac{15P}{100}[/latex] = [latex]\frac{30Q}{100}[/latex] –> 1 [latex]\frac{20Q}{100}[/latex] = [latex]\frac{30R}{100}[/latex] –> 2 From 1, P = 2Q From 2, 2Q = 3R (Here, R = 40000) Q = [latex]\frac{(3*40000)}{2}[/latex] = 60000 P = 2Q = 2*60000 = 120000 P + Q + R = 120000 + 60000 + 40000 = > 220000
10. In a cricket between 2 teams, Team ‘x’ gets 70% of the total score and defeated team ‘y’ by 72 runs. The no of runs scored by the winner?

A. 260 runs B. 190 runs C. 182 runs D. 126 runs

Answer: Option D
Explanation: Team x = 70 % Team y = 30 % According to the question, (70 % – 30 %) of the total score = 72 40 % of the total score = 72 (40/100)*total score = 72 Total score = 72*([latex]\frac{100}{40}[/latex] ) = 180 Total score get by the winner = 180*([latex]\frac{70}{100}[/latex] ) = 126 runs

11. The monthly income of Guru and Vinothini together is Rs. 52,200. The income of Guru and Vinothini is increased by 20% and 12% respectively. The new income of Vinothini is Rs. 2784 more than the new income of Guru. What is the new income of Vinothini?

A. Rs.35072 B. Rs. 31584 C. Rs.34150 D. Rs.29658

Answer: Option B
Explanation: Let the income of Guru and Vinothini be G and V, The monthly income of Guru and Vinothini = 52200 G + V = 32000 Guru’s income = x; Vinothini’s income = 52,200 – x New income of V = New income of G + 2784 V’s new income = (52200 – x)*[latex]\frac{112}{100}[/latex] G’s new income = x * [latex]\frac{120}{100}[/latex] (52200 – x)* ([latex]\frac{70}{100}[/latex]) = x * ([latex]\frac{120}{100}[/latex]) + 2784 [latex]\frac{(5846400 – 112x)}{100}[/latex] = [latex]\frac{120x}{100}[/latex] + 2784 (5846400 – 112x)/100 = (120x + 278400)/100 (5846400 – 112x) = (120x + 278400) 5846400 – 278400 = 112x + 120x 5568000 = 232x Guru’s income X = [latex]\frac{5568000}{232}[/latex] = 24000 Vinothini’s income = 52200 – x = 28200 New Income of Vinothini = 28200*([latex]\frac{112}{100}[/latex]) = Rs. 31584
12. In a survey done by a committee, it was found that 5000 people have a habit of reading newspapers. After a month, this number increased by 5%. And further increased by 10% in the next month. What is the total number of people reading the newspaper after 2 months?

A. 5279 B. 5109 C. 5775 D. 5625

Answer: Option C
Explanation: Number of people reading news paper after months will be, = > 5000 * (1 + ([latex]\frac{5}{100}[/latex])) (1 + ([latex]\frac{10}{100}[/latex])) = > 5000 * ([latex]\frac{105}{100}[/latex]) * ([latex]\frac{110}{100}[/latex]) = 5775
13. Kavi scored 92 marks in Computer. He scored 64% marks in Hindi and X marks in GK. The maximum marks for each subject is 200. The overall percentage of marks obtained by Kavi in all three subjects together is 65%. How many marks did Kavi score in GK?

A. 160 B. 192 C. 126 D. 170

Answer: Option D
Explanation: The maximum marks for each subject is 200 Kavi’s Computer mark =92 Hindi Mark = 64% = ([latex]\frac{64}{100}[/latex])*200 = 128 The overall percentage of all three subjects together => 65% = ([latex]\frac{65}{100}[/latex])* 600= 390 Kavi’s total mark, Computer + Hindi + GK = 390 92 + 128 + GK = 390 => GK = 390 – 220 => GK = 170
14. The total salary of Kiran and Varnan in an organization is Rs. 28000. Kiran & varnan’s salary is increased by 6% and 8% respectively, then their increased total salary will be Rs. 29940. Find the salary of Kiran?

A. Rs. 15000 B. Rs. 18000 C. Rs. 20000 D. Rs. 10000

Answer: Option A
Explanation: Total salary of Kiran and Varnan = Rs. 28000 Salary of Kiran = x, Salary of Varnan = 28000 – x According to the question, X*([latex]\frac{106}{100}[/latex]) + (28000 – x)*([latex]\frac{108}{100}[/latex]) = 29940 (106x/100) + [latex]\frac{(3024000 – 108x)}{100}[/latex] = 29940 106x + 3024000 – 108x = 2994000 3024000 – 2994000 = 2x 30000 = 2x X = 15000 Kiran Salary = Rs. 15000 Varnan’s salary = 28000 – 15000 = Rs. 13000
15. In a class of 200 students, if the ratio of boys and girls in a class is 5 : 3. If 24% of the boys and 20% of the girls are Sports students, find the % of students who are not in sports?

A. 55 % B. 72.75 % C. 77.5 % D. 68 %

Answer: Option C
Explanation: Total no of students = 200 Ratio = 5 : 3 boys = 200/8 * 5 = 125; Girls = [latex]\frac{200}{8}[/latex] * 3 = 75 24% of boys who interested in sports = 125 * [latex]\frac{(24}{100}[/latex] = 30 20% of girls who interested in sports = 75 * [latex]\frac{20}{100}[/latex] = 15 Total number of students, who do not get the scholarship = > 200 – (30 + 15) = 200 – 45 = 155 Required % = ([latex]\frac{155}{200}[/latex]) * 100 = 77.5 %