1. A does half as much work as B in three –fourth of the time if together they take 18 days to complete a work. How much time shall B take to do it?

A. 30days B. 35 days C. 40 days D. None of these

Answer: Option: A
Explanation: B takes x days to do the work Therefore, A takes (2 × [latex]\frac{3}{4}[/latex])xi.e.., 3x/2 days to do it Now , (A +B)’s 1 day’s work = [latex]\frac{1}{18}[/latex] Therefore, [latex]\frac{1}{x}[/latex] + [latex]\frac{2}{3}[/latex]x = [latex]\frac{1}{18}[/latex] or x =30
2. 12 Men or 18 women can reap a field in 14 days. The number of days that 8 men and 16 women will take to reap it?

A. 5 B. 7 C. 8 D. 9

Answer: Option: D
Explanation: 12 men = 18 women or 1 man = [latex]\frac{3}{2}[/latex] women Therefore 8 men + 16 women = (8 × [latex]\frac{3}{2}[/latex] + 16) women i.e.., 28 women Now 18 women can reap the field in 14 days Therefore, 28 women can reap it in = 9 days
3. If 3 men or 4 women can construct a wall in 43 days, then the number of days that 7 men and 5 women take to construct it is?

A. 12 B. 18 C. 24 D. 30

Answer: Option: A
Explanation: 3 men = 4 women or 1 man = [latex]\frac{4}{3}[/latex] women Therefore 7 men + 5 women = (7 × [latex]\frac{4}{3}[/latex] + 5)women i.e.., 43/3 women 4 women can construct the wall in 43 days Therefore, [latex]\frac{43}{3}[/latex] women can construct it in = 12 days
4. 10 men can finish a piece of work in 10 days. Whereas it takes 12 women to finish it in 10 days if 15 men and 6 women undertake to complete the work. How many days will they take to complete it?

A. 2 B. 4 C. 5 D. 11

Answer: Option: C
Explanation: 10 men = 12 women or 1 man = [latex]\frac{6}{5}[/latex] women Therefore 15 men + 6 women = (15 x [latex]\frac{6}{5}[/latex] + 6)women i.e,, 24 women Now 12 women can do the work in 10 days Therefore, 24 women can do it in = 5 days
5. 8 Children and 12 men complete a certain piece of work in 9 days. If each child takes twice the time taken by man to finish the work. In how many days will 12 men finish the same work?

A. 8 B. 15 C. 9 D. 12

Answer: Option: D
Explanation: 2 children = 1 man Therefore (8 children +12 men) = 16 men Now fewer men more days 12: 16:: 9: x Therefore, x = ([latex]\frac{144}{12}[/latex]) = 12 days

1. A can do a piece of work in 10 days and B can do the same piece of work in 20 days. They start the work together but after 5 days. A leaves off B will do the remaining piece of work in?

A. 5 days B. 6 days C. 8 days D. 10 days

Answer: Option: A
Explanation: (A +B)’s 5 days work = 5 ([latex]\frac{1}{10}[/latex] +[latex]\frac{1}{20}[/latex]) = ¾ Remaining work =(1 -[latex]\frac{3}{4}[/latex]) = ¼ [latex]\frac{1}{20}[/latex]work is done by B in 1 day. Therefore, ¼ work is done by B in (20 x [latex]\frac{1}{4}[/latex])i.e.., 5 days
2. A and B can together finish a work in 30 days. They worked for it for 20 days and then B left. The remaining work was done by A alone in 20 more days. Alone can finish the work in?

A. 48 days B. 50 days C. 54 days D. 60 days

Answer: Option: D
Explanation: (A+ B)’s 20 day’s work =(20 x [latex]\frac{1}{30}[/latex]) = [latex]\frac{2}{3}[/latex] Remaining work = (1 - [latex]\frac{2}{3}[/latex]) = [latex]\frac{1}{3}[/latex] [latex]\frac{1}{3}[/latex] work is done by A in 20 days Whole work can be done by A in (3 x 20)days i.e.., 60 days
3. A can complete a job in 9 days. B in 10 days and C in 15 days. B and C start the work and are forced to leave after 2 days. The time taken to complete the remaining work is?

A. 6 days B. 9 days C. 10 days D. 13 days

Answer: Option: A
Explanation: (B + C)’s 2 day’s work = 2 (1/10 + 1/15) = 1/3 Remaining work = (1 – [latex]\frac{1}{3}[/latex]) = [latex]\frac{2}{3}[/latex] [latex]\frac{1}{9}[/latex] work is done by A in 1 day Therefore [latex]\frac{2}{3}[/latex] work is done by A in (9 x [latex]\frac{2}{3}[/latex]) = 6 days
4. A, B and C together earn Rs.150 per day while A and C together earn Rs. 94 and B and C together earn Rs. 76. The daily earning of C is?

A. Rs. 75 B. Rs.56 C. Rs. 34 D. Rs.20

Answer: Option: D
Explanation: B’s daily earning = RS.(150 -94) = Rs. 56 A’s daily earning = Rs.(150 -76) = Rs.74 C’s daily earning = Rs.[150 – (56+74)] = Rs. 20
5. A can do a certain job in 12 days. B is 60% more efficient than A. Then Number of days it takes B to do the same piece of work is?

A. 6 B. 6 [latex]\frac{1}{4}[/latex] C. 7 [latex]\frac{1}{2}[/latex] D. 8

Answer: Option: C
Explanation: Ratio of times taken by A and B = 160 : 100 = 8 : 5 If A takes 8 days B takes 5 days If A takes 12 days, B takes =( 7 [latex]\frac{5}{8}[/latex] x 12) = 7 [latex]\frac{1}{2}[/latex] days

1. A, B and C contract a work for Rs. 550. Together A and B are to do 7/11 of the work. The share of C should be?

A. 7 [latex]\frac{3}{4}[/latex] B. 8 [latex]\frac{4}{5}[/latex] C. 9 [latex]\frac{3}{8}[/latex] D. 10

Answer: Option: B
Explanation: Work to be done by C = (1 – [latex]\frac{7}{11}[/latex]) = [latex]\frac{4}{11}[/latex] Therefore, (A +B) = C = [latex]\frac{7}{11}[/latex] : [latex]\frac{4}{11}[/latex] = 7 : 4 Therefore C’s share = Rs.(550 x [latex]\frac{4}{11}[/latex]) = Rs. 200
2. Mahesh and Umesh can complete a work in 10 days and 15 days respectively. Umesh starts the work and after 5 days Mahesh also joins him in all the work would be completed in

A. 7 days B. 9days C. 11 days D. None of these

Answer: Option: B
Explanation: Umesh’s 5 day’s work = 5 x [latex]\frac{1}{15}[/latex] = 1/3 Remaining work = (1 – [latex]\frac{1}{3}[/latex]) = [latex]\frac{2}{3}[/latex] ([latex]\frac{1}{10}[/latex] + [latex]\frac{1}{15}[/latex]) work is done by both in 1 day Therefore 2/3 work is done by both in (6 x [latex]\frac{2}{3}[/latex]) = 4days. The work was completed in 9 days
3. Twelve men can complete a work in 8 days. Three days after they started the work, 3 more men joined them. In how many days will all of them together complete remaining work?

A. 2 B. 4 C. 5 D. 6

Answer: Option: D
Explanation: 1 man’s one day’s work = [latex]\frac{1}{96}[/latex] 12 men’s 3 day’s work = (3 x [latex]\frac{1}{8}[/latex]) = [latex]\frac{3}{8}[/latex] Remaining work = (1 – [latex]\frac{3}{8}[/latex]) = [latex]\frac{5}{8}[/latex] 15 men’s 1 day’s work = [latex]\frac{15}{96}[/latex] Now 15/96 work is done by them in 1day Therefore 5/8 work will be done by them in ([latex]\frac{96}{15}[/latex] x [latex]\frac{5}{8}[/latex]) i.e., 4 day
4. X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?

A. 6 days B. 10 days C. 15 days D. 20 days

Answer: Option: B
Explanation: Work done by X in 4 days = ([latex]\frac{1}{20}[/latex] * 4) = [latex]\frac{1}{5}[/latex] Remaining work = (1 - [latex]\frac{1}{5}[/latex]) = [latex]\frac{4}{5}[/latex] (X + Y)'s 1 day work = ([latex]\frac{1}{20}[/latex] + [latex]\frac{1}{12}[/latex]) = [latex]\frac{2}{15}[/latex] Now, 2/15 work is done by X and Y in 1 day. So, 4/5 work will be done by X and Y in ([latex]\frac{15}{2}[/latex] * [latex]\frac{4}{5}[/latex]) = 6 days. Hence, total time taken = (6 + 4) = 10 days.
5. A and B can together do a price of work in 15 days. B alone can do it in 20 days. In how many days can A alone do it?

A. 30 days B. 40 days C. 45 days D. 60days

Answer: Option: D
Explanation: A’s 1 day’s work = ([latex]\frac{1}{15}[/latex] – [latex]\frac{1}{20}[/latex]) = [latex]\frac{1}{60}[/latex] Therefore, A alone can finish = 60 days