1. In a factory, there are 40% technicians and 60% non-technicians. If the 60% of the technicians and 40% of non-technicians are permanent employees, then the percentage of workers who are temporary is?

A. 32% B. 42% C. 52% D. 62%

Answer: Option C
Explanation: Total = 100 T= 40 NT= 60 40*([latex]\frac{60}{100 }[/latex]) = 24 60*([latex]\frac{40}{100 }[/latex])=24 24 + 24 = 48 => 100 - 48 = 52%
2. A mixture of 70 liters of wine and water contains 10% water. How much water must be added to make water 12 ½% of the total mixture?

A. 12 liters B. 10 liters C. 4 liters D. 2 liters

Answer: Option D
Explanation: 70 * ([latex]\frac{10}{100 }[/latex]) = 7 Wine Water 87 [latex]\frac{1}{2 }[/latex]% 12 [latex]\frac{1}{2 }[/latex]% 87 [latex]\frac{1}{2 }[/latex]% ------- 63 12 [latex]\frac{1}{2 }[/latex]% -------? => 9 - 7 = 2
3. The amount of water (in ml) that should be added to reduce 9 ml. Lotion, containing 50% alcohol, to a lotion containing 30% alcohol, is?

A. 3 B. 4 C. 5 D. 6

Answer: Option D
Explanation: 4.5 4.5 30% 70% 30% ----- 4.5 70% ------? => 10.5 - 4.5 = 6 ml
4. Find the one which does not belong to that group ?

A. Indian B. Japanian C. American D. Brazilian

Answer: Option B
Explanation: Except Japanian, all others are appropriate usage of citizenship.
5. Find the one which does not belong to that group ?

A. Regiment B. Lieutenant C. Colonel D. Major

Answer: Option A
Explanation: Except Regiment, all others are caders of army officers.

1. Find the one which does not belong to that group ?

A. India : Rupee B. America : Dollar C. Quwait : Dinar D. Australia : Pound

Answer: Option D
Explanation: Except Austriala : Pound, all others are correction combination of country and its currency.
2. By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?

A. 8 B. 9 C. 12 D. 16

Answer: Option A
Explanation: 80% --- 12 120% --- ? [latex]\frac{80}{120 }[/latex] * 12 = 8
3. Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?

A. Rs.2000 B. Rs.1980 C. Rs.1891 D. Rs.1750

Answer: Option A
Explanation: [latex]\frac{(10*10)}{100 }[/latex] = 1%loss 100 --- 99 ? --- 1980 => Rs.2000
4. A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?

A. 20% B. 45% C. 44% D. 48%

Answer: Option C
Explanation: g% = 20 + 20 + [latex]\frac{20*20}{100 }[/latex] = 44%
5. A dishonest dealer professes to sell goods at the cost price but uses a weight of 800 grams per kg, what is his percent?

A. 20% B. 25% C. 30% D. 15%

Answer: Option B
Explanation: 800 --- 200 100 --- ? => 25%

1. In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?

A. 200 sec B. 190 sec C. 210 sec D. 150 sec

Answer: Option B
Explanation: Time taken by B run 1000 meters = [latex]\frac{(1000 * 10)}{50 }[/latex]= 200 sec. Time taken by A = 200 - 10 = 190 sec.
2. A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?

A. 111.12 m B. 888.88 m C. 777.52 m D. 756.34 m

Answer: Option A
Explanation: A runs 1000 m while B runs 900 m and C runs 800 m. The number of meters that C runs when B runs 1000 m, = [latex]\frac{(1000 * 800)}{9 }[/latex] = [latex]\frac{8000}{9 }[/latex] = 888.88 m. B can give C = 1000 - 888.88 = 111.12 m.
3. In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?

A. 57.5 m B. 127.5 m C. 150.7 m D. 98.6 m

Answer: Option B
Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = [latex]\frac{(900 * 700) }{800 }[/latex] = [latex]\frac{6300 }{8 }[/latex] = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = [latex]\frac{(600 * 212.5) }{1000 }[/latex] = 127.5 m.
4. In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?

A. 50 B. 40 C. 25 D. 15

Answer: Option C
Explanation: A scores 60 while B score 40 and C scores 30. The number of points that C scores when B scores 100 = [latex]\frac{(100 * 30) }{40 }[/latex] = 25 * 3 = 75. In a game of 100 points, B gives (100 - 75) = 25 points to C.
5. What sum of money will produce Rs.70 as simple interest in 4 years at 3 [latex]\frac{1 }{2}[/latex] percent?

1584 B. 1120 C. 792 D. 1320

Answer: Option B
Explanation: 70 = [latex]\frac{P*4*7 }{2 }[/latex] X [latex]\frac{1 }{100 }[/latex] P = 500