1. A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

A. 3.6 B. 7.2 C. 8.4 D. 10

Answer: Option B
Explanation: Speed = [[latex]\frac{600}{5× 60}[/latex] ]m/sec = 2 m/sec. Converting m/sec to km/hr = 2 x[latex]\frac{18}{5}[/latex] km/hr = 7.2 km/hr.
2. An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hour, it must travel at a speed of:

A. 300 kmph B. 360 kmph C. 600 kmph D. 720 kmph

Answer: Option D
Explanation: Distance = (240 x 5) = 1200 km. Speed = Distance/Time Speed = [latex]\frac{1200}{5/3}[/latex] km/hr. Required speed = 1200 x [latex]\frac{3}{5}[/latex] km/hr= 720 km/hr
3. If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is:

A. 50 km B. 56 km C. 70 km D. 80 km

Answer: Option A
Explanation: Let the actual distance travelled be x km. Then, [latex]\frac{×}{10}[/latex] = [latex]\frac{× + 20 }{14}[/latex] ⇒14x = 10x + 200 ⇒4x = 200 ⇒ x = 50 km.
4. A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

A. 100 kmph B. 110 kmph C. 120 kmph D. 130 kmph

Answer: Option C
Explanation: Let speed of the car be x kmph Then, speed of the train = [latex]\frac{150}{100}[/latex] x = [latex]\frac{3}{2}[/latex] ∴ [latex]\frac{75}{×}[/latex] - [latex]\frac{75}{3/2}[/latex] x = [latex]\frac{125}{10 × 60 }[/latex] ⇒[latex]\frac{75}{×}[/latex] - [latex]\frac{50}{×}[/latex] = [latex]\frac{5}{24}[/latex] ⇒x = [latex]\frac{25 × 24}{5}[/latex] = 120 kmph
5. Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

A. 9 B. 10 C. 12 D. 20

Answer: Option B
Explanation: Due to stoppages, it covers 9 km less. Time taken to cover 9 km = [[latex]\frac{9}{54}[/latex] x 60] min = 10 min

1. The seven digit number 43567X is divisible by 3, where X is a single digit whole number. Find X.

A. 2 B. 5 C. 8 D. All of these

Answer: Option D
Explanation: A number is divisible by 3 when sum of its digits is divisible by 3. Here, sum of digits = 4 + 3 + 5 + 6 + 7 + X = 25 + X. So, X can be 2, 5, 8 which gives the sum 27, 30 and 33 respectively. Therefore, X has 3 values here, for which the number is divisible by 3. So, the answer is option D.
2. Simplify the expression using BODMAS rule ([latex]\frac{3}{7}[/latex]) of ([latex]\frac{4}{5}[/latex]) of 20 ([latex]{25}^{2}[/latex] - [latex]{24}^{2}[/latex])

A. 336 B. 168 C. 84 D. None of these

Answer: Option A
Explanation: ([latex]\frac{3}{7}[/latex]) × ([latex]\frac{4}{5}[/latex]) of 20 (625 - 576)⇒ ([latex]\frac{3}{7}[/latex]) × ([latex]\frac{4}{5}[/latex]) × 20 × 49 =336
3. Simplify the expression using BODMAS rule (105 + 206) - 550 ÷ [latex]{5}^{2}[/latex] + 10

A. 399 B. 289 C. 298 D. 299

Answer: Option D
Explanation: (105 + 206) - 550 ÷ 52 + 10 = 311 – 550 ÷ 25 + 10 = 311 – 22 + 10 = 289 + 10 = 299
4. Simplify the expression using BODMAS rule:: ([latex]\frac{3}{3}[/latex]) of ([latex]\frac{4}{7}[/latex]) {(10 × 3) – (8 × 2)}

A. 6 B. 12 C. 18 D. 14

Answer: Option B
Explanation: Applying BODMAS rule = ([latex]\frac{3}{2}[/latex]) of ([latex]\frac{4}{7}[/latex]) {30 – 16} = ([latex]\frac{12}{14}[/latex]) × 14 = 12
5. The six-digit number 54321A is divisible by 9 where A is a single digit whole number. Find A.

A. 0 B. 2 C. 4 D. 3

Answer: Option D
Explanation: A number is divisible by 3 when sum of its digits is divisible by 3. Here, sum of digits = 4 + 3 + 5 + 6 + 7 + X = 25 + X. So, X can be 2, 5, 8 which gives the sum 27, 30 and 33 respectively. Therefore, X has 3 values here, for which the number is divisible by 3.

1. A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :

A. 4 days B. 6 days C. 8 days D. 12 days

Answer: Option C
Explanation: (A + B + C)'s 1 day's work = [latex]\frac{1}{6}[/latex] (A + B)'s 1 day's work = [latex]\frac{1}{8}[/latex] (B + C)'s 1 day's work = [latex]\frac{1}{12}[/latex] ∴(A + C)'s 1 day's work = [2[latex]\frac{1}{6}[/latex]] - [[latex]\frac{1}{8}[/latex] + [latex]\frac{1}{12}[/latex]] = [latex]\frac{1}{3}[/latex] - [latex]\frac{5}{24}[/latex] = [latex]\frac{3}{24}[/latex] = [latex]\frac{1}{8}[/latex] So, A and C together will do the work in 8 days.
2. A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:

A. 5 days B. 6 days C. 10 days D. 10[latex]\frac{1}{2}[/latex] days

Answer: Option C
Explanation: (B + C)'s 1 day's work = [[latex]\frac{1}{9}[/latex] + [latex]\frac{1}{12}[/latex]] = [latex]\frac{7}{36}[/latex] Work done by B and C in 3 days =[ [latex]\frac{7}{36}[/latex] x 3] = [latex]\frac{7}{12}[/latex] Remaining work = [1 - [latex]\frac{7}{12}[/latex]] = [latex]\frac{5}{12}[/latex] Now, [latex]\frac{1}{24}[/latex] work is done by A in 1 day So, [latex]\frac{5}{12}[/latex] work is done by A in [24 x [latex]\frac{5}{12}[/latex]] = 10 days
3. X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work?

A. 13[latex]\frac{1}{3}[/latex] days B. 15 days C. 20 days D. 26 days

Answer: Option A
Explanation: Work done by X in 8 days = [[latex]\frac{1}{40}[/latex] x 8] = [latex]\frac{1}{5}[/latex] Remaining work = [1 - [latex]\frac{1}{5}[/latex]] = [latex]\frac{4}{5}[/latex] Now,[latex]\frac{4}{5}[/latex] work is done by Y in 16 days. Whole work will be done by Y in [16 x[latex]\frac{5}{4}[/latex]] = 20 days ∴X's 1 day's work = [latex]\frac{1}{40}[/latex], Y's 1 day's work = [latex]\frac{1}{20}[/latex] (X + Y)'s 1 day's work = [[latex]\frac{1}{40}[/latex] + [latex]\frac{1}{20}[/latex]] = [latex]\frac{3}{40}[/latex] = [latex]\frac{3}{40}[/latex] Hence, X and Y will together complete the work in [latex]\frac{40}{3}[/latex] = 13[latex]\frac{1}{3}[/latex]
4. The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

A. 15 B. 16 C. 18 D. 25

Answer: Option B
Explanation: Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x. S.P. of x articles = Rs. 20. Profit = Rs. (20 - x). ∴[[latex]\frac{20 - ×}{×}[/latex] x 100 = 25] ⇒2000 - 100x = 25x ⇒125x = 2000 ⇒ x = 16.
5. In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?

A. 30% B. 70% C. 100% D. 250%

Answer: Option B
Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295. ∴Required percentage = [[latex]\frac{295}{420}[/latex] x 100]% = [latex]\frac{1475}{21}[/latex]% = 70%