1. What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
19.98% of 780.21 + ? + 29.72% of 499.23 = 34.98% of 1359.69

A. 170 B. 90 C. 230 D. 370 E. 29

Answer: Option (A)
2. [latex]\sqrt{1849}[/latex] + 1155.905 ÷ 16.927 = [latex]?^2[/latex] + 64.89% of 95.49

A. 2 B. 14 C. 7 D. 21 E. 18

Answer: Option (D)
3. [latex](12.166)^{5.99}[/latex] ÷ [latex](5.3)^{3.11}[/latex] x [latex](2.3)^{2.98}[/latex] = [latex](2.3)^{? - 3.01}[/latex]

A. 10 B. 12 C. 17 D. 15 E. 18

Answer: Option (E)
4. 28% of 6525 + 35% of 6780 + 20% of ? = 52% of 5475 + 25% of 7248

A. 2295 B. 2265 C. 2225 D. 2195 E. 2165

Answer: Option (A)
5. 56 × 81 + 84 × 29 + ? × 21 = 63 × 79 + 49 × 57

A. 28 B. 33 C. 38 D. 43 E. 48

Answer: Option (C)

1. Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

A. 24400 B. 21300 C. 210 D. 25200

Answer: Option (D)
2. In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

A. 159 B. 209 C. 201 D. 212

Answer: Option (B)
3. From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there in the committee. In how many ways can it be done?

A. 624 B. 702 C. 756 D. 812

Answer: Option (C)
4. In how many different ways can the letters of the word 'OPTICAL' be arranged so that the vowels always come together?

A. 610 B. 720 C. 825 D. 920

Answer: Option (B)
5. In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together?

A. 47200 B. 48000 C. 42000 D. 50400

Answer: Option (D)
6. A box contains 21 balls numbered 1 to 21. A ball is drawn and then another ball is drawn without replacement. What is the probability that both balls are even numbered?

A. [latex]\frac{2}{7}[/latex] B. [latex]\frac{8}{21}[/latex] C. [latex]\frac{3}{14}[/latex] D. [latex]\frac{5}{21}[/latex] E. None of these

Answer: Option (C)

1. The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?

A. 23 years B. 24 years C. 25 years D. None of these

Answer: Option (A)
2. The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:

A. 3500 B. 4000 C. 4050 D. 5000

Answer: Option (B)
3. The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:

A. 35 years B. 40 years C. 50 years D. None of these

Answer: Option (B)
4. A car owner buys petrol at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of petrol if he spends Rs. 4000 each year?

A. Rs. 7.98 B. Rs. 8 C. Rs. 8.50 D. Rs. 9

Answer: Option (A)
5. In Arun’s opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun’s weight is greater than 60 kg but less than 70 kg. His mother’s view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?

A. 67 kg. B. 68 kg. C. 69 kg. D. Data inadequate E. None of these

Answer: Option (A)

1. Four times the difference in ages of C and A is one more than the age if B. Percentage of A’s age to C’s age is 75%. If ratio of B’s age 5 years hence to C’s age 1 year ago is 4 : 3. Find the average of ages A and C.

A) 20 B) 19 C) 12 D) 14 E) 8

Answer: Option (D)
2. 10 years ago daughter’s age was two-fifth of her mother’s age that time. While 10 years hence her age will be three-fifth of her mother’s age then. Find the difference in the ages of the two.

A) 24 B) 19 C) 26 D) 38 E) 16

Answer: Option (A)
3. B is as more younger than C as he is elder than A. Ratio of ages of A to C is 5 : 9. If B’s age after 10 years will be 24, find the average of all of their present ages.

A) 15 B) 16 C) 14 D) 22 E) 19

Answer: Option (C)
4. Kaira is 4 years younger to his brother. Her father was 30 years old when her sister was born while her mother was was 30 years old when she was born. If her sister was 4 years old when their brother was born, find the age of her father when her mother was born.

A) 11 B) 12 C) 4 D) 10 E) 8

Answer: Option (E)
5. 6 years ago, three times the age of B was 2 more than the age if A that time. 6 years hence, twice age of B will be equal to A’s age that time. Find the total of their ages.

A) 48 B) 66 C) 56 D) 65 E) 60

Answer: Option (B)

Directions (1-5): Study the following table and bar graph to answer the questions given below it.
Percentage of appeared and qualified candidates in a competitive examination from different institutes.

1. What is the ratio of the qualified candidates from institutes A, B and C together to the appeared candidates from institutes D, E and F?

A. 52 : 225 B. 26 : 125 C. 125 : 26 D. 13 : 200 E. None of these

Answer: Option (A)
2. What percent of the candidates from institute ‘E’ has been declared qualified out of the total candidates appeared from this institute?

A. 16% B. 26% C. 16.66% D. 18% E. None of these

Answer: Option (E)
3. What is the approximate percentage of students qualified w.r.t. to those appeared from the institutes B and C together?

A. 20 B. 21 C. 22 D. 23 E. 24

Answer: Option (B)
4. Which institute has the highest percentage of candidates qualified w.r.t. to those appeared?

A. A B. B C. C D. D E. None of these

Answer: Option (A)
5. What is the average number of appeared candidates from the institutes A, B and F together?

A. 19800 B. 2200 C. 6600 D. 8600 E. None of these

Answer: Option (C)

1. A 400m long train is running at 72 Kmph. how much time it will take to cross an electric pole?

A. 15sec B. 20sec C. 19sec D. 21sec

Answer: Option (B)
2. A 180m long train is running at 54 Kmph. how much time it will take to cross a platform of 120m long?

A. 20sec B. 22sec C. 19sec D. 18sec

Answer: Option (A)
3. 320m long train is running at 72 Kmph. how much time it will take to cross a platform of 180m long?

A. 20sec B. 25sec C. 30sec D. 27sec

Answer: Option (B)
4. A 600m long train is running at 90 Kmph. how much time it will take to cross an electric pole?

A. 16sec B. 20sec C. 24sec D. 22sec

Answer: Option (C)
5. Two trains 300m and 400m long run at the speeds of 40 kmph and 50kmph respectively in opposite Directions on parallel tracks. The time taken to cross each other?

A. 20sec B. 25secs C. 26sec D. 28sec

Answer: Option (D)

Directions (1-4): In each of the following questions, a question is followed by three statements numbered I, II and III. Read all the statements and answer accordingly.
1. What is the principal amount?
Statement I: The difference between Compound Interest and Simple Interest for 2 years is 300 Statement II: If the Compound Interest for 3 years at the rate of 10% is 3310 Statement III: If the sum becomes double in 32 years at Compound Interest?

A) Only I B) Only II C) II and III together D) Only I or II E) II and I or III

Answer: Option (B)
Explanation: From II, using the formula of CI, amount can be found.
2. What is the length of the train?
Statement I: If train can cross a platform in 35 second and a pole in 15 sec. Statement II: If the speed of train is 70 kmph Statement III: If the length of platform is 400 m

A) I and III together B) I alone C) I and II together D) II and III together E) Even all I, II, and III are not sufficient

Answer: Option (C)
Explanation: From I and II: speed = 70 km/hr and crosses the pole in 15 sec, so length = speed*time.
3. What will be the increase percent in volume?
Statement I: An ice cube is dip into 10 litre water Statement II: If radius of a cylinder increases by 20% and height increases by 10% Statement III: If the height of ice cube is 10 cm.

A) All I, II and III B) II alone and I and III together C) I and II together D) II and III alone E) II alone

Answer: Option (B)
Explanation: Using II: Volume = π*r*r*h So by successive formula, the increase in volume can be found First: r*r So 20 + 20 + (20)(20)/100 = 44% Next: 44 + 10 + (44)*(10)/100 – final increase in volume From I and III: volume of given shape (cylinder, cube, cone etc) = 10 l (initial volume). And ice cube of height 10 cm is dip into it. So after finding new volume or increase in volume after the ice cube is dipped, % increase in volume can be found.
4. Find the increase percent in Cost Price to make Marked Price if
Statement I: A trader gain 25% on Cost Price Statement II: A trader gain 20% on Selling Price Statement III: A trader gain 20% on Cost Price after giving a discount of 20% on Marked Price

A) I and II Together B) II and III Together C) Only III D) All I, II and III Together E) None of these

Answer: Option (C)
Explanation: Using III. Gain=20%=1/5 CP : SP=5:6— (i) Discount=20%=1/5 MP:SP=5:4 —-(ii) hence CP:SP:MP= 10:12:15 hence (15-10)/10*100

1. By selling an article for Rs. 69 there is a loss of 8%, when the article is sold for Rs. 78, the gain or loss per cent is:

A. neither loss nor gain B. 4% gain C. 4% loss D. 40% gain E. 40% loss

Answer: Option (B)
2. By selling an article for Rs. 240, a man incurs a loss of 10%. At what price should he sell it, so that he makes a profit of 20%?

A. Rs. 264 B. Rs. 288 C. Rs. 300 D. Rs. 320 E. Rs. 420

Answer: Option (D)
3. The difference between the selling price and cost price of an article is Rs. 210. If the profit percent is 25, then the selling price of the article is:

A. Rs. 950 B. Rs. 1050 C. Rs. 1150 D. Rs. 1250 E. Rs. 1500

Answer: Option (B)
4. Richa purchased an article at 4/5 of its list price and sold it at 20% more than the list price. Richa’s profit percent was

A. 50% B. 40% C. 30% D. 25% E. 35%

Answer: Option (A)
5. X sells two articles for Rs. 4,000 each with no loss and no gain in the transaction. If one was sold at a gain of 25% the other is sold at a loss of

A. 25% B. 18% C. 16.66% D. 20% E. 22.22%

Answer: Option (C)

1. The parameter of a square is equal to the perimeter of a rectangle of length 14 cm and breadth 20 cm. Find the circumference of a semicircle (approx.) whose diameter is equal to the side of the square.

A. 32 cm B. 22 cm C. 30 cm D. 27 cm E. 19 cm

Answer: Option (D)
Answer: Parameter of square = 2 * (14+20) = 68cm So side of square = 68/4 = 17 cm So diameter of semicircle = 17 cm So circumference of a semicircle = πr = 22/7 * 17/2 = 27 cm
2. There are two circles of different radius such that radius of the smaller circle is three – sevens that of the larger circle. A square whose area equals 3969 sq cm has its side as thrice the radius of the larger circle. What is the circumference of the smaller circle?

A. 59 cm B. 56.5 cm C. 49.5 cm D. 65.5 cm E. 62 cm

Answer: Option (B)
Answer: Side of square = √3969 = 63 cm So radius of larger circle = 1/3 * 63 = 21 cm So radius of smaller circle = 3/7 * 21 = 9 cm So circumference of smaller circle = 2 * 22/7 * 9 = 56.5 cm
3. A Birthday cap is in the form of a right circular cone which has base of radius as 9 cm and height equal to 12 cm. Find the approximate area of the sheet required to make 8 such caps.

A. 3225 [latex]cm^2[/latex] B. 3278 [latex]cm^2[/latex] C. 3132 [latex]cm^2[/latex] D. 3392 [latex]cm^2[/latex] E. 3045 [latex]cm^2[/latex]

Answer: Option (D)
Answer: r = 9, h = 12 So slant height, l = √([latex]9^2[/latex] + [latex]12^2[/latex]) = 15 cm So curved surface area of a cap = πrl = 22/7 * 9 * 15 = 424 sq. cm So curved surface area of 8 such cap = 424*8 = 3392 sq. cm which is also equal to area of sheet required to make 8 such caps
4. The barrel of a fountain pen is cylindrical in shape which radius of base as 0.7 cm and is 5 cm long. One such barrel in the pen can be used to write 300 words. A barrel full of ink which has a capacity of 14 cu cm can be used to write how many words approximately?

A. 545 B. 656 C. 508 D. 598 E. 687

Answer: Option (A)
Answer: Volume of the barrel of pen = π[latex]r^2[/latex]h = 22/7 * 0.7*0.7 * 5 = 7.7 cu cm A barrel which has capacity 7.7 cu cm can write 300 words So which has capacity 14 cu cm can write = 300/7.7 * 14 = 545 words
5. A vessel is in the form of a hemi-spherical bowl on which is mounted a hollow cylinder. The diameter of the sphere is 14 cm and the total height of vessel is 15 cm, find the capacity of the vessel.

A. 1977.23 [latex]cm^3[/latex] B. 1999.45 [latex]cm^3[/latex] C. 1950.67 [latex]cm^3[/latex] D. 1840.67 [latex]cm^3[/latex] E. 1833.27 [latex]cm^3[/latex]

Answer: Option (C)
Answer: Diameter is 14, so radius is 7 cm Total height = 15 cm, so height of cylinder = 15-7 = 8 cm (because height of hemisphere is same as its radius) Capacity of vessel = volume of cylinder + vol of hemisphere So = π[latex]r^2[/latex]h + 2/3 *π[latex]r^3[/latex] = 22/7 * 7 * 7 * 8 + 2/3 * 22/7 * 7 * 7 * 7 = 1232 + 718.67 = 1950.67 cu cm

1. A certain sum of money was divided among A, B and C in a certain way. C got half as much as A and B together got. A got one third of what B and C together got. What is the ratio of A’s share to that of C’ s share?

A. 1 : 4 B. 3 : 4 C. 4 : 1 D. 3 : 5 E. None of these

Answer: Option (B)
2. The wages of laborers in a factory increased in the ratio 22 : 25 and there was a reduction in their number in the ratio 15 : 11. Find the original wage bill if the present bill is Rs 5000.

A. Rs 2500 B. Rs 3000 C. Rs 5000 D. Rs 6000 E. None of these

Answer: Option (D)
3. Rs 1220 is divided, among A, B, C and D such that B’s share is 5/9 th of A’s; C’s share is 7/10 th of B’s and D has 1/3rd as much as B and C together. Find A’s share

A. Rs 540 B. Rs 802 C. Rs 100 D. Rs 650 E. None of these

Answer: Option (A)
4. A, B and C are partners. A receives 9/10 of the profit and B and C share the remaining profit equally. A’s income is increased by Rs 270 when the profit rises from 12 to 15%. Find the capital invested by B and C each

A. Rs 5000 B. Rs 1000 C. Rs 500 D. Rs 1500 E. None of these

Answer: Option (C)
5. Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by ‘A’ is Rs 40,000, out of a total annual profit of Rs 33,000, C’s share will be

A. Rs 9,000 B. Rs 12,000 C. Rs 11,000 D. Rs 10,000 E. None of these

Answer: Option (A)

1. Directions: Study the following arrangement and answer the following questions given below.
E 4 B % R 3 A 6 # F H @ I 2 D 9 & K U $ W 1 M P 5 * Q 8 T
If all the numbers are dropped from the arrangement, then which of the following is ninth to the left of W?

A. A B. # C. R D. & E. None of these

Answer: Option (E)
2. E 4 B % R 3 A 6 # F H @ I 2 D 9 & K U $ W 1 M P 5 * Q 8 T
How many such numbers are there in the above arrangement each of which is immediately preceded by symbol and immediately followed by letter?

A. One B. Two C. Three D. None E. More than three

Answer: Option (D)
3. E 4 B % R 3 A 6 # F H @ I 2 D 9 & K U $ W 1 M P 5 * Q 8 T
Four of the following five are alike in certain way based on their positions in the above arrangement and so form group. Which is the one that does not belong to group?

A. F@# B. D & 2 C. U W K D. % 3 B E. 5 Q M

Answer: Option (E)
4. Directions: Study the following arrangement and answer the following questions given below.
‘Barin’ village is 20 kilometers to the north of village ‘Khanof’ village, ‘Banoha’ is 18 kilometers to east of village’ Khanof’ village, Palasi village is 12 kilometers to the west of ‘Barin’. Nitin starts from village Banoha and goes to village palasi in which direction is he from starting point?

A. North-East B. North-west C. South-East D. North E. None of these

Answer: Option (B)
5. One morning before sunset two friends Rohit and ajay were talking to each other face to face. If Rohit’s shadow was exactly to his right side, which direction was Ajay facing?

A. South B. North C. West D. Data inadequate E. None of these

Answer: Option (A)

1. A sum becomes triple in 6 years at S.I. The same sum will become 19 times in how many years?

A. 50 years B. 48 years C. 54 years D. 57 years E. None of these

Answer: Option (C)
Explanation: SI=A-P=> A=3P as sum triples SI=3P-P=2P in 6 years In 19 times SI=18 P—54 years (2:6 hence 18=54)
2. A sum of Rs 343 becomes 512 in 3 years at C.I. Find the rate of interest.

A. 14 (2/7) % B. 12.5 % C. 8 (2/3) % D. 16 (2/3) % E. None of these

Answer: Option (A)
Explanation: Sum=353; Amount=512 as many year, put that many root i.e cuberoot(343): cuberoot(512) 7:8 rate=(8-7)/7 *100 =14 (2/7)%
3. Find the C.I on Rs 20,000 at 10% rate of interest in 2 years if compounded half yearly. (Approximately)

A. Rs 4210 B. Rs 4310 C. Rs 4410 D. Rs 4510 E. None of these

Answer: Option (B)
Explanation: In half yearly=> Time-double; Rate= half Rate=5% ; Time=4 years; Sum = Rs 20,000 1 years————–2 years————3 years———-4 years 1000—————–1000—————1000————-1000 ————————50——————50—————–50 ———————————————50—————–50 ———————————————2.5—————-50 —————————————————————–2.5 —————————————————————–2.5 —————————————————————–2.5 —————————————————————-0.125 Total = Rs 4000 +300 + 10+0.125= Rs 4310.125
4. A sum of Rs 6,000 was taken as a loan. This is to be repaid in two equal annual installments. If the rate of interest is 20% compounded annually then find the value of each installment.

A. Rs 4400 B. Rs 2220 C. Rs 4320 D. Rs 4420 E. None of these

Answer: Option (C)
Explanation: Formula= x/(1+R/100)^T x/ (1+20/100)^1 + x/(1+20/100)^2 = 6600 solve and get x=4320
5. If the ratio of difference between CI and SI for 3 years and 2 years is 31:10, then find the Rate of Interest.

A. 11.11% B. 10% C. 20% D. 25% E. None of these

Answer: Option (B)
Explanation: Sum= A Interest= B A——–A———A ——B———B ———————B ———————C CI for 3 years=3A+3B+C SI for 3 years =3A Diff= 3B+cCI for 2 years=2A+B SI for 2 years=2A diff=B ratio=(3B+C)/B=31/10 B=10; C=1 Rate=C/B=1/10=10%

1. The following numbers form a series. Find the odd one out. 56, 58, 62, 70, 86, 120, 182

A. 120 B. 58 C. 182 D. 62 E. 86

Answer: Option (A)
Explanation: The series follows the pattern 56 + [latex]2^1[/latex] = 58, 58 + [latex]2^2[/latex] = 62, 62 + [latex]2^3[/latex] = 70, 70 + [latex]2^4[/latex] = 86, 86 + [latex]2^5[/latex] = 118, 118 + [latex]2^6[/latex] = 182 Therefore, 118 should be in place of 120.
2. The following numbers form a series. Find the odd one out. 733, 365, 181, 89, 38, 20

A. 365 B. 181 C. 89 D. 38 E. 20

Answer: Option (D)
Explanation: The series follows the pattern (733 – 3) ÷ 2 = 365, (365 – 3) ÷ 2 = 181, (181 – 3) ÷ 2 = 89, (89 – 3) ÷ 2 = 43, (43 – 3) ÷ 2 = 20 Therefore, 43 should be in place of 38.
3. The following numbers form a series. Find the odd one out. 5, 21, 101, 501, 2510, 12501

A. 101 B. 21 C. 2510 D. 12501 E. 501

Answer: Option (C)
Explanation: The series follows the pattern 5 × 5 – 4 = 21, 21 × 5 – 4 = 101, 101 × 5 – 4 = 501, 501 × 5 – 4 = 2501, 2501 × 5 – 4 = 12501 Therefore, 2501 should be in place of 2510.
4. The following numbers form a series. Find the odd one out. 1, 13, 37, 73, 125, 181

A. 13 B. 37 C. 73 D. 125 E. 181

Answer: Option (D)
Explanation: The series follows the pattern 1 + (11 × 1 + 1) = 13, 13 + (11 × 2 + 2) = 37, 37 + (11 × 3 + 3) = 73, 73 + (11 × 4 + 4) = 121, 121 + (11× 5 + 5) = 181 Therefore, 121 should be in place of 125.
5. The following numbers form a series. Find the odd one out. 1, 4, 12, 27, 47, 86

A. 4 B. 12 C. 27 D. 47 E. 86

Answer: Option (D)
Explanation: The series follows the pattern 1 + [latex]2^2[/latex] – 1 = 4, 4 + [latex]3^2[/latex] – 1 = 12, 12 + [latex]4^2[/latex] – 1 = 27, 27 + [latex]5^2[/latex]– 1 = 51, 51 + [latex]6^2[/latex]– 1 = 86 Therefore, 51 should be in place of 47.

1. 2450 ÷ 7 + 112 × 2.5 = ? × 2

A. 300 B. 315 C. 325 D. 330 E. None of these

Answer: Option (B)
2. [latex]\sqrt{1444}[/latex] + [latex]\sqrt{5184}[/latex] = 22 x ?

A. 3 B. 4 C. 5 D. 6 E. None of these

Answer: Option (C)
3. 125% of [latex]\frac{7}{6}[/latex] of x = 84% of 1250

A. 550 B. 630 C. 680 D. 720 E. None of these

Answer: Option (D)
4. [latex]\frac{4}{7}[/latex] of 441 ÷ 18 + 14 = [latex]\sqrt{?}[/latex]

A. 684 B. 740 C. 784 D. 810 E. None of these

Answer: Option (C)
5. [latex]\frac{6}{5}[/latex] of [latex]\frac{7}{8}[/latex] x [latex]\frac{24}{21}[/latex] of 2425 = ?

A. 2910 B. 3220 C. 3450 D. 3870 E. None of these

Answer: Option (A)

1. Three friends Divya, Bhanu, Chitra invested in a business in the ratio of 3:4:7. After 3 months Bhanu withdraw half of her capital. If the sum invested by Divya is 27000, then the profit earned by Bhanu at the end of the year out of the total profit of Rs.40150 is,

A. Rs.17000 B. Rs.19800 C. Rs.3850 D. Rs.8030 E. None of these

Answer: Option (D)
Explanation: Let Divya, Bhanu & Chitra investment be 3X, 4X & 7X respectively. Then from Divya’s investment, 3X = 27000 => X = Rs.9000 Then Bhanu & Chitra investment is Rs.36000 & Rs.63000 respectively. Profit ratio of Divya, Bhanu, Chitra is, 27000 × 12 : 36000×3 + 18000 × 9 : 63000 × 12 => 36 : 30 : 84 Bhanu’s profit = 40150 × 30/150 = Rs.8030
2. Anu starts business with Rs.33000 and after 6 months, Banu joins with Anu as his partner. After 17 months, the profit is divided in the ratio 6 : 5. What is Banu’s contribution in the capital?

A. Rs.40500 B. Rs.42500 C. Rs.44600 D. Rs.45500 E. None of these

Answer: Option (B)
Explanation: Ratio of their profits, Anu : Banu = 33000 × 17 : X × 11 => 51000 : X = 6 : 5 => X = 42500 Banu’s contribution in the capital = Rs.42500
3. Two persons A and B invested in a business with 3.5 Lakh and 4.2 Lakh rupees respectively. They agree that 23% of the profit should be divided equally among them and rest is divided between them according to their investment. If B got Rs.2100 more than A, then the total profit is.

A. Rs.20000 B. Rs.25000 C. Rs.27000 D. Rs.30000 E. None of these

Answer: Option (D)
Explanation: Ratio of profit of A & B is, A : B = 3.5 : 4.2 => 5 : 6 Let the total profit earned be X Since, 23% of the profit should be divided equally among them, Then the remaining share is = 77% of X. A’s share = 77/100 * X * 5/11 & B’s share = 77/100 * X * 6/11 From question, 77/100 * X * 6/11 -77/100 * X * 5/11 = 2100 => X = Rs.30000
4. X, Y & Z invested in the ratio of 11:12:13. After the end of business term they receive the profit in the ratio 6:7:8. Find the ratio of time in which they invested in the business.

A. 934:1001:1055 B. 1054:1000:937 C. 936:1001:1056 D. Cannot be determined E. Other than the given options.

Answer: Option (C)
Explanation: X, Y & Z invested in ratio 11:12:13 respectively. Also, T1, T2 & T3 are duration of their investment respectively. Profit earned = Investment × Time Profit ratio = 6 : 7 : 8 = 11 × T1 : 12 × T2 : 13 × T3 T1 : T2 : T3 = 936 : 1001 : 1056
5. Three persons enter into a partnership by investing in the ratio of 6:7:9. After one year A invest Rs.22000 more. Now, the ratio of investment changes to 5:4:7. Approximately how much A invested initially?

A. Rs.88000 B. Rs.68000 C. Rs.48000 D. Rs.66000 E. Other than the given options.

Answer: Option (C)
Explanation: Let the investment of A,B & C initially be 6X, 7X & 9X respectively for an year. After one year ratio of their investment is, 5 : 4 : 7 = 6X + 22000 : 7X : 9X => X = Rs.8000 A’s investment initially = 6X = 6 × 8000 = Rs.48000

1. A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:

A. 4 days B. 6 days C. 8 days D. 12 days

Answer: Option (B)
2. A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in:

A. 8 days B. 10 days C. 12 days D. 15 days

Answer: Option (C)
3. A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?

A. 18 days B. 24 days C. 30 days D. 36 days

Answer: Option (A)
4. A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in:

A. 4 days B. 6 days C. 8 days D. 18 days

Answer: Option (A)
5. Twenty women can do a work in sixteen days. Sixteen men can complete the same work in fifteen days. What is the ratio between the capacity of a man and a woman?

A. 3 : 4 B. 4 : 3 C. 5 : 3 D. Data inadequate

Answer: Option (B)

1. Two students appeared at an examination. One of them secured 17 marks more than the other and his marks was 60% of the sum of their marks. What are the marks obtained by them?

A. 33, 42 B. 51, 34 C. 50, 60 D. 45, 35 E. None

Answer: Option (B)
Explanation: Let the marks secured by them be x and (x + 17) sum of their marks = x + (x + 17) = 2x + 17 Given that (x + 17) was 60% of the sum of their marks. ⇒ (x + 17) = 60/100(2x + 17)==> 5x + 85 = 6x + 51 X = 34 Then (x + 17) = 34 + 17 = 51
2. If the price of petrol increases by 20% and Novena intends to spend only an additional 10% on petrol, by how much percent will she reduce the quantity of petrol purchased?

A. 8% B. 7 ¼% C. 8 1/3% D. 9% E. None

Answer: Option (C)
Explanation: Let the price of the petrol be Rs 100. Now New Price is 120. She intend to spend is Rs 110. Amount become 120 - 110 = 10 10/120 * 100 = 8 1/3 % Reduction
3. 30% of the men are more than 50 years old and 70% of the men are less than or equal to 50 years old. 20% of all men play football. If 20% of the men above the age of 50 play football, what percentage of the football players are less than or equal to 50 years?

A. 60% B. 70% C. 80% D. 90% E. None

Answer: Option (B)
Explanation: Let number of men = 100 less than or equal to 50 years old is 70 then 30 men are greater than 50 years of age. Number of men above 50 years who play football = 20% of 30 = 6 20% of all men play football means total no. of men who play football = 20, out of which 6 men are above 50 years old. So, 20 – 6 = 14 men are less than or equal to 50 years old. Therefore, percentage of football players less than or equal to 50 years = (14/20) * 100 = 70%
4. A man spends 20% of his income on food, 15% on children’s education 25% on shopping ,10% on house rent and saves the remaining. What is his income?

A. Rs 25000 B. Rs18000 C. Rs23000 D. Rs30000 E. None

Answer: Option (C)
Explanation: Let his income be 100% Then spend (20 + 15 + 25 + 10) = 70% Remaining 30% saving 30 == 6900 100 ? == Rs23,000
5. The present population of a district is 2,80,000. If it increases at the rate of 2.5% per annum then at the end of 2 years, it will be:

A. 2,55,800 B. 2,85,400 C. 3,45,000 D. 2,94,175 E. None

Answer: Option (D)
Explanation: 2,80,000 * 102.5/100 * 102.5/100 = 2,80,000 * 205/100 * 205/100 41 * 41 * 175 = 2,94,175.

1. How many minutes Raman will take to cover a distance of 400 meters if he runs at a speed of 20 km/hr?

A. 2 mins B. 1.5 mins C. 1⅕ mins D. 2.5 mins E. None of these

Answer: Option (D)
Explanation: Raman's speed = 20 km/hr = 20 × 5/18 = 50/9 m/sec ⇒ 400 × 9/50 = 1⅕ mins
2. John travelled from his town to city. John went to city by bicycle at the speed of 25 km/h and came back at the speed of 4 km/h. If John took 5 hours and 48 min to complete his journey, what is the distance between town and city?

A. 15 km B. 22 km C. 20 km D. 25 km

Answer: Option (C)
Explanation: Average speed of John = 2xy/x+y = 2 × 25 × 4 / 25 + 4= 200/29 km/h ⇒ Distance traveled = Speed × Time = 200/29 × 29/5 = 40 Km ⇒ Distance between city and town = 40/2 = 20 km
3. Speed of a train is 20 meters per second. It can cross a pole in 10 seconds. What is the length of train?

A.150 m B.250 m C.200 m D.300 m

Answer: Option (C)
Explanation: ⇒ Lenght of train = 20 × 10 = 200 meters
4. Ram walks at a speed of 12 km/h. Today the day was very hot so walked at ⅚ of his average speed. He arrived his school 10 minutes late. Find the usual time he takes to cover the distance between his school and home?

A. 40 mins B. 45 mins C. 50 mins D. 60 mins

Answer: Option (C)
Explanation: If Ram is walking at ⅚ of his usual speed that means he is taking 6/5 of using time. ⇒ 6/5 of usual time - usual time = 10 mins ⇒ 1/5 of usual time = 10 mins ⇒ Usual time = 50 mins
5. A car running at 65 km/h takes one hour to cover a distance. If the speed is reduced by 15 km/hour then in how much time it will cover the distance ?

A. 72 mins B. 78 mins C. 76 mins D. None of these

Answer: Option (B)
Explanation: Reduced speed = 65-15 = 50 km/h ⇒ Now car will take 65/50 × 60 mins = 78 mins