Q1. The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number?
Answer: Option D
Explanation :
ets digit at tens and ones place be 2x and 3x
So,number is 2x*10 + 3x
After interchanging number will be 3x*10 +2x
so, [3x*10 + ] – [2x*10 + 3x]27
we get, x = 3
so number = 69
Q2. What least number would be subtracted from 427398 so that the remaining number is divisible by 15?
Answer: Option B
Explanation :
On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted
Q3. In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, the dividend is:
A. 4236
B. 4306
C. 4336
D. 5336
Answer: Option D
Explanation :
Divisor = (5 x 46) = 230.
Also, 10 x Q = 230
Q = 23. And, R = 46.
Dividend = (230 x 23 + 46) = 5336
Q4. Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are
A. 18, 22 and 23
B. 18, 19 and 20
C. 19, 20 and 21
D. 20, 21 and 22
Answer: Option C
Explanation :
let number be x,x+1,x+2
2x + 3(x + 1) + 4(x + 2) = 180
x = 19
so numbers are 19,20,21
Q5. In a division sum ,the divisor is 3 times the quotient and 6 times the remainder.If the remainder is 2 then the dividend is
Answer: Option D
Explanation :
Divident = Quotient × Divisor +Remainder
Divisor = 6 × 2 = 12
Q = [latex]\frac{12}{3}[/latex] = 4
Divident = 4 × 12 + 3 = 48 + 2 = 50