1. Two pipes P and Q can fill a tank in 10 hours and 14 hours respectively. If both pipes are opened simultaneously, how much time will be taken to fill the tank?
A. 4 hours 20 min
B. 5 hours 49 min
C. 3 hours 50 min
D. 3 hours 22 min
Answer: Option B
Explanation:
Part filled by P in 1 hour = [latex]\frac{1}{10 }[/latex]
Part filled by Q in 1 hour = [latex]\frac{1}{14 }[/latex]
Part filled by (P + Q) in 1 hour = ( [latex]\frac{1}{10 }[/latex] + [latex]\frac{1}{14 }[/latex] ) = ([latex]\frac{6}{35 }[/latex] )
Time taken to fill the tank is ([latex]\frac{35}{6 }[/latex]) = 5 hours 49 min
2. A inlet pipe can fill a tank in 12 hours and an outlet pipe can empty the tank in 16 hours. If both the pipes are opened simultaneously, find the time taken to fill the tank.
A. 36 hours
B. 12 hours
C. 4 hours
D. 48 hours
Answer: Option D
Explanation:
As the inlet can fill the tank in 12 hours, in one hour it will fill [latex]\frac{1}{12}[/latex]th of the tank.
Similarly, the outlet pipe in one hour can empty [latex]\frac{1}{16 }[/latex] th part of the tank.
If both are opened simultaneously, the part of the tank filled in one hour is:
[latex]\frac{1}{12 }[/latex] - [latex]\frac{1}{16 }[/latex] = [latex]\frac{1}{48 }[/latex]
Hence, the tank gets filled in 48 hours.
3. If pipe A can fill the tank in 45 minutes and pipe B in 30 minutes, find the time to fill the tank if both the pipes are opened together.
A. 12 minutes
B. 20 minutes
C. 18 minutes
D. 15 minutes
Answer: Option C
Explanation:
In 1 minute pipe A can fill [latex]\frac{1}{45 }[/latex]th part of the tank and pipe B can fill [latex]\frac{1}{30 }[/latex]th part of the tank. If they are opened simultaneously then in 1 minute they can fill ([latex]\frac{1}{45 }[/latex]
+ [latex]\frac{1}{30 }[/latex]) part of the tank = [latex]\frac{1}{18 }[/latex]th part of the tank.
4. If a pipe can fill a tank in 6 hours, find the part of tank it fills in one hour.
A. [latex]\frac{1}{6 }[/latex]
B. [latex]\frac{2}{3 }[/latex]
C. [latex]\frac{1}{2 }[/latex]
D. None of these
Answer: Option C
Explanation:
Let the capacity of the tank be C liters.
Time to fill the tank = 6 hours
Hence, in 1 hour [latex]\frac{C}{6 }[/latex] liters gets filled.
Therefore, [latex]\frac{1}{6 }[/latex]th part of the tank gets filled in one hour.
5. A leak at the bottom of the tank can empty the tank in 5 hours, while an inlet pipe can fill the same tank at the rate of 6 litres per minute. When the tank is full, the inlet is opened and the tank gets empty in 8 hours due to the leakage. Find the capacity of the tank.
A. 1800 litres
B. 3600 litres
C. 4800 litres
D. 5760 litres
Answer: Option C
Explanation:
The capacity of the tank is given by C = [latex]\frac{(p*q*r)}{(r – p) }[/latex] litres
Where, p = time in which the leakage can empty the tank in hours = 5 hours
q = rate at which the inlet fills the tank in lph = 6*60 = 360 lph
r = time in which the tank gets emptied in hours = 8 hours
Hence, C = [latex]\frac{(5*360*8)}{(8 – 5) }[/latex]
C = 4800 litres