Directions (1 - 10): What value should come in place of question mark (?) in the following equations?
1. ([latex] \sqrt{1444 ÷ 5} [/latex]) × 3.25 = ?

A. 24.7 B. 25.4 C. 26.6 D. 27.2 E. 28.5

Answer: Option A
Solution: x = [latex] \frac{38} {5}[/latex] × 3.25
= 24.7
2. 17.8 + [latex] \frac{3} {7}[/latex] of 89.6 = ?

A. 52.8 B. 54.4 C. 56.2 D. 58.6 E. 60.4

Answer: Option C
Solution: 17.8 + 38.4
= 56.2
3. 373.816 + 274.102 – 199.573 – 108.108 = ?

A. 338.147 B. 339.787 C. 340.237 D. 341.347 E. 342.107

Answer: Option C
Solution: x = 647.918 – 307, 681
= 340.237
4. 14.8 × 7.25 = 20% of = ?

A. 524.5 B. 528.5 C. 532.5 D. 536.5 E. 540.5

Answer: Option D
Solution: 107.3 = [latex] \frac{20} {100}[/latex] × x
x = 536.5
5. [latex] \sqrt{1156} [/latex] x [latex] \sqrt{42.25} [/latex] = ?

A. 212 B. 215 C. 218 D. 220 E. 221

Answer: Option E
Solution: x = 34 × 6.5
= 221
6. 2[latex] \frac{1} {6}[/latex] + (3 [latex] \frac{3}{4} [/latex] - 1[latex] \frac{1}{4}) [/latex] = ?

A. 4[latex] \frac{5} {12}[/latex] B. 4[latex] \frac{1} {4}[/latex] C. 4[latex] \frac{7} {12}[/latex] D. 5[latex] \frac{1} {4}[/latex] E. None of these

Answer: Option E
Solution: (2 + 3 – 1) + [latex] \frac{1}{6} [/latex] + [latex] \frac{3}{4}) [/latex] - [latex] \frac{1}{4} [/latex]
= [latex] \frac{2 + 9 - 3}{12} [/latex]
= 4 + [latex] \frac{8}{12} [/latex]
= [latex] \frac{42}{3} [/latex]
7. 36251 + 43261 = ? + 52310

A. 27202 B. 28102 C. 29302 D. 26602 E. None of these

Answer: Option A
Solution: 36251 + 43261 = x + 52310
79512 = x + 52310
79512 – 52310 = x
x = 27202
8. 7 [latex] \frac{3} {6}[/latex] of 534 + 262 = 61800 – ?

A. 56533 B. 57533 C. 58533 D. 37355 E. None of these

Answer: Option B
Solution: [latex] \frac{45} {6}[/latex] × 534 + 262 = 61800 – x
4005 + 262 = 61800 – x
x = 57533
9. 72% of 486 – 64% of 261 = ?

A. 184.66 B. 183.66 C. 188.88 D. 182.88 E. 186.24

Answer: Option D
Solution: x = 349.92 – 167.04
= 182.88
10. ? ÷ 62 × 12 = 264

A. 1364 B. 1284 C. 1348 D. 1388 E. None of these

Answer: Option A
Solution: [latex] \frac{x} {62}[/latex] × 12
= 264
x = 1364

Directions (1 - 3): Study the table carefully to answer the questions that follow:

1. What is the ratio of total number of boys in University B and D together to the total number of girls in the same universities together?

A. 25 : 19 B. 35 : 21 C. 20 : 7 D. 30 : 13 E. 5 : 3

Answer: Option D
Solution: Total boys in B = [latex] \frac{15} {100}[/latex] × 32500 × [latex] \frac{60} {100}[/latex] = 2925
Total boys in D = [latex] \frac{28} {100}[/latex] × 32500 × [latex] \frac{75} {100}[/latex] = 6825
Total girls in B = [latex] \frac{15} {100}[/latex] × 32500 × [latex] \frac{40} {100}[/latex]= 1950
Total girls in D = [latex] \frac{28} {100}[/latex] × 32500 × [latex] \frac{25} {100}[/latex]= 2275
Reqd. Ratio = ([latex] \frac{2925 + 6825} {1950 + 2275})[/latex]
Reqd. Ratio = [latex] \frac{9750} {4225}[/latex]
Reqd. Ratio = [latex] \frac{30} {13}[/latex]
2. The total number of students in the University A is what per cent of the total number of students in University F?

A. 55% B. 67% C. 60% D. 48% E. 58%

Answer: Option C
Solution: [latex] \frac{12} {100}[/latex] × 32500
= [latex] \frac{x} {100}[/latex] × [latex] \frac{20} {100}[/latex] × 32500
x = 60
3. What is the total number of boys from university A,C and E together?

A. 6030 B. 5030 C. 7030 D. 4030 E. 3030

Answer: Option D
Directions (4 - 7): The following graph shows the number of students participated in annual talent show of Kurukshetra university from different colleges. Study the graph carefully to answer the given questions.

4. Find the ratio of the total number of students participated in dancing from college P, T & V together to the total students participated in singing from college P, Q & R together.?

A. 28 : 27 B. 25 : 26 C. 25 : 29 D. 27 : 29 E. None of these

Answer: Option B
Solution: Ratio = [latex] \frac{340 + 190 + 220} {240 + 320 + 220}[/latex]
= 25 : 26
5. From which of these colleges the total number of students participated is 2nd minimum?

A. College P B. College Q C. College R D. College S E. None of these

Answer: Option D
Solution: Collage P = 840 Q = 900 R = 780 S = 740 T = 790 U = 730 V = 870 Q > V > P > T > R > S >U
6. If 40% of the total students of college S who participated in acting, are doing solo acting and other are in group acting. 66[latex] \frac{2} {3}[/latex]% of the students participated in group acting are a part of comedy dramas. Then find the total number of students who are acting in comedy dramas.?

A. 104 B. 120 C. 110 D. 108 E. None of these

Answer: Option A
Solution: Total in S = 260
Number of students acting In comedy drama
= [latex] \frac{60} {100}[/latex] × [latex] \frac{2} {3}[/latex] × 260
= 104
7. The difference between the no. of students participating in dancing from college P and R and that in singing from T and U?

A. 165 B. 170 C. 82 D. 94 E. None of these

Answer: Option B
Solution: Total in dance from P & R
= 340 + 260 = 600
= Number of students singing
From T & U is = 280 + 150 = 430
Difference = 600 – 430
= 170
8. The length and breadth of a plot are 35 m and 16 m respectively. If the rate of fencing is Rs. 7 per meter, what is cost of its fencing?

A. Rs. 3920 B. Rs. 602 C. Rs. 714 D. Rs. 357 E. None of these

Answer: Option C
Solution: Perimeter of plot = 2 (c + b) = 2
(35 + 16) = 102 m
Total cost of fencing = 7 × 102 = Rs 714
Directions (9 - 10): In the following number series one number is missing. Find out the missing number.
9. 2, 21, 138, 705,?

A. 2386 B. 3540 C. 2820 D. 3236 E. None of these

Answer: Option E
Solution: 2 × 7 + 1 × 7 = 21
21 × 6 + 2 × 6 = 138
138 × 5 + 3 × 5 = 705
705 × 4 + 4 × 4 = 2836
17, 52, 158, 477, ?, 4310

A. 1433 B. 1432 C. 1435 D. 1434 E. None of these

Answer: Option C
Solution: 17 × 3 + 1 = 52
52 × 3 + 2 = 158
158 × 3 + 3 = 477
477 × 3 + 4 = 1435
1435 × 3 + 5 = 4310