Place values:
A positional system of notation in which the position of a number with respect to a point determines its value is known as place value.
The value of the digits is based on the number ‘10’ in the decimal system.
Each position in a decimal number has a value that is a power of 10.
Example:

for decimal form, 82.743
Here
Before the decimal point
8 is in ten’s place
2 is in one’s place
After the decimal point
7 is in ten’s place
4 is in hundred’s place
3 is in thousand’s place
So, 82.743 is written as
(8 x 10) + (2 x 1) + (7 x [latex]\frac{1}{10}[/latex]) + (4 x [latex]\frac{1}{100}[/latex]) + (3 x [latex]\frac{1}{1000}[/latex])

If a number is considered and zeros are added to the last digit after the decimal point, the value of the number is not changed.
Example:

5.32 = (5 x 1) + (3 x [latex]\frac{1}{10}[/latex]) + (2 x [latex]\frac{1}{100}[/latex])
Now, add two zeros to the last digit after the decimal point
5.3200 = (5 x 1) + (3 x [latex]\frac{1}{10}[/latex]) + (2 x [latex]\frac{1}{100}[/latex]) + (0 x [latex]\frac{1}{1000}[/latex]) + (0 x [latex]\frac{1}{10,000}[/latex])
So, Adding zeros have no effect on the value of the number

Operations with decimals
Adding and subtracting decimals
To add and subtract the decimals, the rule is line up the decimals
After the decimal point, add additional zeros (or assume there are zeros) if required before adding or subtracting.
Example 1:

2.0756 + 17.5 + 0.083 = 2.0756 + 17.5000 + 0.0830 = 19.6586

Example 2:

14.248 – 3.18749 = 14.24800 – 3.18749 = 11.06051

Multiplying decimals
First, count the total number of digits that are to the right of each decimal.
Then, ignore the decimals and find the product.
Take the product and move the decimal place to the left based on the total number of digits that were originally to the right of each decimal.
Example:

23.456 x 7.8
Ignore the decimals and find the product
23456 x 78 = 1829568
There are 4 digits to the right of the decimal
So, move decimal 4 space to the left of 1829568
i.e. 182.9568

Dividing decimals
Move both decimals until the divisor becomes an integer.
Divide and keep the decimal in the same location.
Example:

43.548 ÷ 2.85
Take the divisor i.e. 2.85 and turn it into an integer by moving the decimal two spaces to the right i.e. 285
Since decimal in the divisor is moved to two spaces to the right, also take the dividend i.e. 43.548 and move the decimal two spaces to the right i.e. 4354.8
Now, divide 4354.8 by 285,
4354.8 ÷ 285 = 15.28

Rounding Decimals
Next digit is 0, 1, 2, 3, or 4 → round down
Next digit is 5, 6, 7, 8 or 9 → roundup
Example 1:

7.38241 rounded to the nearest tenth is?
First, locate the digit in tenth position i.e. 3
Since the tenth place after the decimal is ‘3’ and digit ‘8’ is to the right of ‘3’. It is rounded up to ‘4’
Now the given digit becomes equal to 7.4

Example 2:

15.02318 rounded to the nearest thousandth is?
First, locate the digit in thousandth position i.e. 3
Since the thousandth place after the decimal is ‘3’ and digit ‘1’ is to the right of ‘3’. It is rounded down to ‘3’
Now the given digit becomes equal to 15.023

1. Quantitative Comparison

A. Quantity A is greater. B. Quantity B is greater. C. The two quantities are equal. D. The relationship cannot be determined from the information given.

Solution:

By dividing 4 by 11, you get the decimal form D = 0.363636…, where the sequence of two digits “36” repeats without end. Continuing the repeating pattern, you see that the 1st digit, the 3rd digit, the 5th digit, and every subsequent odd-numbered digit to the right of the decimal point is 3.
Therefore, Quantity A, the 25th digit to the right of the decimal point, is 3. Since Quantity A is 3 and Quantity B is 4, the correct answer is Choice B.

2. What is the 25th digit to the right of the decimal point in the decimal form of [latex]\frac{6}{11}[/latex]?

A. 3 B. 4 C. 5 D. 6 E. 7

Solution:

[latex]\frac{6}{11}[/latex] = 0.5454…….
Every odd-numbered digit, to the right of the decimal point, is 5, thus 25th (odd) digit will also be 5.
Hence, option C is the answer.

3. Quantitative Comparison

A. Column A’s quantity is greater. B. Column B’s quantity is greater. C. The quantities are the same. D. The relationship cannot be determined from the information given.

Solution:

0.25% of 0.25
0.0025 (0.25) --- Move the decimal on 0.25% two places to the left.
0.000625
6.25 * [latex](10)^{-5}[/latex] --- Move decimal 5 places to the left.
0.0000625
Since 0.000625 > 0.0000625, the answer is column A is greater.
Option A is the right choice.

4. Evaluate: [latex]\frac{((2.39)^2 + (1.61)^2)}{(2.39 – 1.61)}[/latex]

A. 2 B. 4 C. 6 D. 8

Solution:

Apply [latex]\frac{(a^2 + b^2)}{a - b}[/latex] = [latex]\frac{(a + b)(a - b)}{(a - b)}[/latex] = (a + b)
So, here (a + b) = (2.39 + 1.61) = 4.

5. What decimal of an hour is a second?

A. 0.0025 B. 0.0256 C. 0.00027 D. 0.000126

Solution:

Required decimal = [latex]\frac{1}{60 * 60}[/latex] = [latex]\frac{1}{3600}[/latex] = 0.00027