1. A man can row a certain distance down stream in 6 hours and return the same distance in 9 hours. If stream flows at the rate of 2 km/hr, then what will be man’s speed if he rows in still water?
A. 10 km/hr
B. 12 km/hr
C. 14 km/hr
D. 15 km/hr
Answer - Option A
Explanation -
[latex]( {v}_{1} + {v}_{2}) {t}_{1}[/latex] = [latex]( {v}_{1} - {v}_{2}) {t}_{2}[/latex]
i.e, [latex]( {v}_{1} + {v}_{2}) * 6[/latex] = [latex]( {v}_{1} - {v}_{2}) * 9[/latex]
[latex]( {v}_{1}[/latex] = 10 km/hr
2. A boat against the current of water goes 9 km/hr and in the direction of the current 12 km/hr. The boat takes 4 hours and 12 minute es to move upward and downward direction from A to B. What is the distance between A and B?
A. 21.6 km
B. 21.0 km
C. 22 km
D. 30 km
Answer - Option A
Explanation -
[latex]\frac {d}{9} + \frac {d}{12}[/latex] = [latex]4 \frac {12}{60}[/latex]
d = 21.6 km
3. A man takes 3 hours and 45 minutes to boat 15 km with the current in a river and 2 hours 30 minutes to cover a distance of 5 km against the current. Speed of the boat in still water and speed of the current respectively will be
A. 3 km/hr, 1 km/hr
B. 1 km/hr, 3 km/hr
C. 2 km/hr, 5 km/hr
D. none of these
Answer - Option A
Explanation -
[latex]({v}_{1} + {v}_{2})[/latex] = [latex] \frac {15}{3 \frac {3}{4}}[/latex] = 4 km/hr
[latex] ({v}_{1} - {v}_{2})[/latex] = [latex] \frac {5}{2 \frac {1}{2}}[/latex] = 2 km/hr
Solving equations (i) and (ii), we get
[latex] {v}_{1}[/latex] = 3 km/hr and [latex]{v}_{2}[/latex] = 1 km/hr
4. A boat can be rowed 6 km/hr along the current and 4 km/hr against the current. Speed of the current and speed of the boat in still water, respectively will be
A. 1 km/hr, 5 km/hr
B. 5 km/hr, 1 km/hr
C. 2 km/hr, 4 km/hr
D. none of these
Answer - Option B
Explanation -
[latex]({v}_{1} + {v}_{2})[/latex] = 6 .....(1)
[latex]( {v}_{1} - {v}_{2})[/latex] = 4 .....(2)
From equations (i) and (ii), we get
[latex] {v}_{1}[/latex] = 5 km/hr and [latex]{v}_{2}[/latex] = 1 km/hr
5. A boat moves down the stream at the rate of 1 km in 6 minutes and up the stream at the rate of
1 km in 10 minutes. The speed of the current is
A. 2 km/hr
B. 1 km/hr
C. 1.5 km/hr
D. 2.5 km/hr
Answer - Option A
Explanation -
[latex]({v}_{1} + {v}_{2})[/latex] = [latex] \frac {1 km}{6 min}[/latex] = 10 km/hr ...(1)
[latex]({v}_{1} - {v}_{2})[/latex] = [latex] \frac {1 km}{10 min}[/latex] = 6 km/hr ....(2)
subtracting equation (2) from (1), we get
[latex]{v}_{1}[/latex] = 2 km/hr