Arithmetic
1. A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
A. Rs. 650
B. Rs. 690
C. Rs. 698
D. Rs. 700
Answer: Option (C)
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
2. How much time will it take for an amount of Rs.450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A. 3.5 years
B. 4 years
C. 4.5 years
D. 5 years
Answer: Option (B)
Explanation:
Time = [latex]\frac{100 \times 81}{450 \times 4.5}[/latex] years = 4 years.
3. A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest. What is the rate of interest?
A. 3%
B. 4%
C. 5%
D. 6%
E. None of these
Answer: Option (D)
Explanation:
S.I. = Rs. (15500 - 12500) = Rs. 3000.
Rate = [latex] \frac{100 \times 3000}{12500 \times 4}[/latex]% = 6%
4. Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
A. Rs. 6400
B. Rs. 6500
C. Rs. 7200
D. Rs. 7500
E. None of these
Answer: Option (A)
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then, [latex]\frac{x \times 14 \times 2}{100}[/latex] + [latex]\frac{(13900 - x) \times 11 \times 2}{100}[/latex] = 3508
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
5. A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
A. Rs. 4462.50
B. Rs. 8032.50
C. Rs. 8900
D. Rs. 8925
E. None of these
Answer: Option (D)
Explanation:
Principal
= Rs. [latex]\frac{100 \times 4016.25}{9 \times 5}[/latex]
= Rs. [latex]\frac{401625}{45}[/latex]
= Rs. 8925.
Algebra
1. The zero of the polynomial p(x) = 2x + 5 is
Answer: Option (D)
2. If one of the factor of x[latex]^{2}[/latex] + x – 20 is (x + 5). Find the other
A. x – 4
B. x + 2
C. x + 4
D. x – 5
Answer: Option (A)
3. If the value of 104 × 96 is
A. 9984
B. 9469
C. 10234
D. 11324
Answer: Option (A)
4. The value of 5.63 × 5.63 + 11.26 × 2.37 + 2.37 × 2.37 is
A. 237
B. 126
C. 56
D. 64
Answer: Option (D)
5. If x + y = 3, x2 + y2 = 5 then xy is
Answer: Option (C)
Trigonometry
1. Cotθ =
A. 1/cosθ
B. 1/tanθ
C. sinθ/cosθ
D. cosecθ
Answer: Option (B)
2. 60th part of one degree is called one
A. second
B. radian
C. degree
D. minute
Answer: Option (D)
3. If an arc of length l of the circle of radius r students' an angle θ radian at center, then l =
A. 1/r θ
B. r/θ
C. θ/r
D. rθ
Answer: Option (D)
4. Two cities whose longitudes are 20°E and 40°W on the equator are apart
A. 1000km
B. 2000km
C. 2500km
D. 6702km
Answer: Option (D)
5. Cosθ =
A. 1/cscθ
B. 1/secθ
C. 1/cotθ
D. 1/sinθ
Answer: Option (B)
Geometry
1. Surface area of hollow cylinder with radius ‘r’ and height ‘h’ is measured by
A. 2πr - h
B. 2πr + h
C. πrh
D. 2πrh
Answer: Option (D)
2. The perimeter of a rectangle with base ‘b’ and height ‘h’ is measured by
A. 2 × b⁄h
B. 2(h + b)
C. 2(b - h)
D. 2(h - b)
Answer: Option (B)
3. In terms of radius, a diameter is equals to
A. 2 + r
B. 2r
C. r⁄2
D. 2⁄r
Answer: Option (B)
4. When a polygon's all sides and angles are equal, it is said to be
A. reflective
B. quadrilateral
C. regular
D. vertical
Answer: Option (C)
5. Simplify (1 ⁄ s) - (1 ⁄ t)
A. (s - t) ⁄ st
B. (t - s) ⁄ st
C. 0
D. 1 ⁄ (s - t)
Answer: Option (B)
Mensuration
1. The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?
A. 1: 96
B. 1: 48
C. 1: 84
D. 1: 68
E. None of these
Answer: Option (A)
Explanation:
Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12x[latex]^{2}[/latex] = 6912
x[latex]^{2}[/latex] = 576 = 4 * 144 = 2[latex]^{2}[/latex] * 12[latex]^{2}[/latex] (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12x[latex]^{2}[/latex] = 1 : 4x = 1: 96.
2. What will be the cost of building a fence around a square plot with an area equal to 289 sq ft, if the price per foot of building the fence is Rs.58?
A. Rs. 3944
B. Rs. 3828
C. Rs. 4176
D. Cannot be determined
E. None of these
Answer: Option (A)
Explanation:
Let the side of the square plot be an ft.
a[latex]^{2}[/latex] = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 58 = Rs. 3944.
3. The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?
A. 600 cm
B. 800 cm
C. 400 cm
D. 1000 cm
E. None of these
Answer: Option (B)
Explanation:
Area of the square = s * s = 5(125 * 64)
=> s = 25 * 8 = 200 cm
Perimeter of the square = 4 * 200 = 800 cm.
4. A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangular, whose length and breadth are in the ratio of 6: 5. What is the area of the rectangle?
A. 60 cm[latex]^{2}[/latex]
B. 30 cm[latex]^{2}[/latex]
C. 45 cm[latex]^{2}[/latex]
D. 15 cm[latex]^{2}[/latex]
E. None of these.
Answer: Option (B)
Explanation:
The circumference of the circle is equal to the perimeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm[latex]^{2}[/latex]
5. A cube of side one-meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
A. 10
B. 100
C. 1000
D. 10000
E. None of these
Answer: Option (C)
Explanation:
Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge, 10 cubes can be cut. (Along length, breadth, and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000
Statistics
1. In a week the prices of a bag of rice were 350,280,340,290,320, 310,300. The range is
Answer: Option (B)
2. The mean of a distribution is 14 and the standard deviation is 5. What is the value of the coefficient of variation?
A. 60.4%
B. 48.3%
C. 35.7%
D. 27.8%
Answer: Option (C)
3. In statistics, a population consists of
A. All People living in a country
B. All People living in the area under study
C. All subjects or objects whose characteristics are being studied
D. None of the above
Answer: Option (B)
4. The middle value of an ordered array of numbers is the
A. Mode
B. Mean
C. Median
D. MidPoint
Answer: Option (C)
5. The sum of the percent frequencies for all classes will always equal
A. one
B. the number of classes
C. the number of items in the study
D. 100
Answer: Option (D)