1. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs

A. 5
B. 7.4
C. 6.25
D. 5.5

Answer - Option C
Explanation - [latex]\frac {10×3.2+40x}{10+40}[/latex]=[latex]\frac {282}{50}[/latex]
32+40x=282
x=6.25
2. A grocer has a sale of ₹6435,₹6927,₹6855,₹7230 and ₹6562for 5consecutive months. How much sale must he have in the sixth month so that he gets an average sale of ₹6500?

A. ₹5000
B. ₹4991
C. ₹4800
D. ₹5004

Answer - Option B
Explanation - Total sale of 6months =6500×6=39000
Therefore, sale in the sixth month
=39000−(6435+ 6927+ 6855+ 7230+ 6562)
=4991

1. Two numbers are in the ratio 2 : 3. If their L.C.M. is 48. what is sum of the numbers?

A. 64
B. 42
C. 28
D. 40

Answer - Option D
Explanation - Let the numbers be 2xand 3x
LCM of 2x and 3x = 6x(∵ LCM of 2 and 3 is 6. Hence LCM of 2 and 3x is 6x)
Given that LCM of 2x and 3X is 48
6x=48
x= [latex]\frac {48}{6}[/latex]= 8
Sum of the numbers=2x+3x
=5x
= 5 × 8 = 40
2. The H.C.F. of two numbers is 5 and their L.C.M. is 150. If one of the numbers is 25, then the other is:

A. 20
B. 28
C. 24
D. 30

Answer - Option D
Explanation - Product of two numbers = Product of their HCF and LCM.
Let one number = x
=> [latex]25\times[/latex] x = [latex]5\times[/latex]150
=> x =[latex]\frac {5\times150}{25}[/latex]=30

1. The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, find the value of x

A. 16
B. 15
C. 25
D. 18

Answer - Option A
Explanation - 25 = [latex]\frac {(20-X)100}{X}[/latex]
⇒x=4(20−x)
⇒5x=80
⇒x=16
2. If the selling price is doubled, the profit triples. What is the profit percent?

A. 105[latex]\frac {1}{3}[/latex]%
B. 66[latex]\frac {2}{3}[/latex]%
C. 120%
D. 100%

Answer - Option D
Explanation - If selling price is doubled, the profit triples. In this case, the amount of increase in the selling price is equal to the amount of increase in profit. Therefore,
selling price = 2 × profit
⇒ selling price - profit = profit
⇒ cost price = profit
⇒ profit percent
= 100 %

1. P can finish a work in 18 days. Q can finish the same work in 15 days. Q worked for 10 days and left the job. how many days does P alone need to finish the remaining work?

A. 6
B. 4
C. 5
D. 8

Answer - Option A
Explanation - Work done by P in 1 day = [latex]\frac {1}{18}[/latex]
Work done by Q in 1 day = [latex]\frac {1}{15}[/latex]
Work done by Q in 10 days = [latex]\frac {10}{15}[/latex] = [latex]\frac {2}{3}[/latex]
Remaining work = 1 - [latex]\frac {2}{3}[/latex] = [latex]\frac {1}{3}[/latex]
Number of days in which P can finish the remaining work = ([latex]\frac {1}{3}[/latex]) ([latex]\frac {1}{18}[/latex]) = 6
2. P is 30% more efficient than Q. P can complete a work in 23 days. If P and Q work together, how much time will it take to complete the same work?

A. 9
B. 11
C. 13
D. 15

Answer - Option C
Explanation - Work done by P in 1 day = [latex]\frac {1}{23}[/latex]
q × [latex]\frac {130}{100}[/latex] = [latex]\frac {1}{23}[/latex]
Let work done by Q in 1 day = q => q = [latex]\frac {100}{23\times130}[/latex] = [latex]\frac {10}{23\times13}[/latex]
Work done by P and Q in 1 day = [latex]\frac {1}{23}[/latex] + [latex]\frac {10}{23\times13}[/latex] = [latex]\frac {23}

{23\times13}[/latex] = [latex]\frac {1}{13}[/latex]

1.The cost of Type 1 material is Rs. 15 per kg and Type 2 material is Rs.20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then what is the price per kg of the mixed variety of material?

A. Rs. 17
B. Rs.18
C. Rs. 19
D. Rs. 16

Answer - Option B
Explanation - Cost Price(CP) of Type 1 material is Rs. 15 per kg
Cost Price(CP) of Type 2 material is Rs. 20 per kg
Type 1 and Type 2 are mixed in the ratio of 2 : 3.
Hence Cost Price(CP) of the resultant mixture
= [latex]\frac {(15\times2)\times(20\times3)}{(2\times3}[/latex]
= [latex]\frac {(30 + 60)}{5}[/latex]=[latex]\frac {90}{5}[/latex]=18
2. Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.

A. 2:3
B. 4:3
C. 3:2
D. 3:4

Answer - Option A
Explanation - CP of 1kg 1st kind rice = Rs.7.20
CP of 1kg 2nd kind rice = Rs.5.70
CP of 1kg mixed rice = Rs.6.30
By rule of alligation,

Required Ratio = .6 : .9 = 6:9 = 2:3