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DRDO MTS Prelims Quantitative Aptitude

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DRDO MTS Prelims Quantitative Aptitude

shape Introduction

DRDO MTS Tier - 1 Examination consisting of Objective Tests for 100 marks will be conducted online. This test would be of 90 minutes duration consisting of 3 Sections as follows. There is no separate timing for each section. DRDO MTS Quantitative Aptitude presents the samples related to Quantitative Aptitude sections.

shape Pattern

Tier - 1 Examination consisting of Objective Tests for 100 marks will be conducted online. This test would be of 90 minutes duration consisting of 3 Sections as follows. There is no separate timing for each section.
S. No. Name of Test Number of Questions Maximum Marks Time allotted for each test (Separately timed)
1 General Intelligence & Reasoning Ability 35 35

90 minutes
2 General Awareness 30 30
3 Quantitative Aptitude & Numerical Ability 35 35

shape Syllabus

S. No. Name of the topic
1 Number Systems
2 Whole Numbers.
3 Decimals
4 Fractions
5 Arithmetical operations.
6 Percentages
7 Profit and Loss.
8 Interest.
9 Discount.
10 Averages.
11 Area
12 Pictorial Representation.
13 Ratio and Proportion.
14 Time and Work.
15 Ratio and Time.
16 Time and Distance.
17 Mixtures & Allegations.
18 Mensuration.
19 Data Interpretation etc.

shape Samples

1. How many of the following numbers are divisible by 132 ? 264, 396, 462, 792, 968, 2178, 5184, 6336
    (A) 4 (B) 5 (C) 6 (D) 7

Answer: Option A
Explanation: 32 = 4 x 3 x 11 So, if the number divisible by all the three numbers 4, 3 and 11, then the number is divisible by 132 also. 264 11,3,4 (/) 396 11,3,4 (/) 462 11,3 (X) 792 11,3,4 (/) 968 11,4 (X) 2178 11,3 (X) 5184 3,4 (X) 6336 11,3,4 (/) Therefore the following numbers are divisible by 132: 264, 396, 792 and 6336. Required number of number = 4.
1. What decimal of an hour is a second ?
    (A) .0025 (B) .0256 (C) .00027 (D) .000126

Answer: Option C
Explanation: Required decimal = [latex]\frac{1}{60 × 60}[/latex]
1. [latex]\frac{.009 }{0? }[/latex] = .01
    (A) .0009 (B) .09 (C) .9 (D) 9

Answer: Option C
Explanation: Let = [latex]\frac{.009 }{0? }[/latex] = .01; Then x = [latex]\frac{.009 }{.01 }[/latex] = [latex]\frac{.9 }{1 }[/latex] = .9
1. The two's complement system is to be used to add the signed numbers 11110010 and 11110011. Determine, in decimal, the sign and value of each number and their sum.
    (A) –14 and –13; –27 (B) –113 and –114; 227 (C) –27 and –13; 40 (D) –11 and –16; –27

Answer: Option A
Explanation: First number:11110010 Here first MSB(Most Significant Bit)is 1. So the number is negative number. 1's complement of first number:00001101 2's complement of first number:00001110 Decimal number corespond to 00001110 is 14. here the number is negative. so -14. In the same way, find the second number that is -13 so the sum is -27
1. What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
    (A) 1 (B) 14 (C) 20 (D) 21

Answer: Option D
Explanation: Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69. Number of such numbers = 14 Required percentage = [latex]\frac{14 }{70 }[/latex] x 100]
1. In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
    (A) 30% (B) 70% (C) 100% (D) 250%

Answer: Option B
Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295. Required percentage = [[latex]\frac{295 }{420 }[/latex] x 100] % = [latex]\frac{1475}{21 }[/latex] %]
1. A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
    (A) Rs. 650 (B) Rs. 690 (C) Rs. 698 (D) Rs. 700

Answer: Option C
Explanation: S.I. for 1 year = Rs. (854 - 815) = Rs. 39. S.I. for 3 years = Rs.(39 x 3) = Rs. 117. Principal = Rs. (815 - 117) = Rs. 698.
1. If Rs. 10 be allowed as true discount on a bill of Rs. 110 due at the end of a certain time, then the discount allowed on the same sum due at the end of double the time is:
    (A) Rs. 20 (B) Rs. 21.81 (C) Rs. 22 (D) Rs. 18.33

Answer: Option D
Explanation: S.I. on Rs. (110 - 10) for a certain time = Rs. 10. S.I. on Rs. 100 for double the time = Rs. 20. T.D. on Rs. 120 = Rs. (120 - 100) = Rs. 20. T.D. on Rs. 110 = Rs. [latex]\frac{20 }{120 }[/latex] X 100 = Rs. 18.33
1. A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
    (A) Rs. 4991 (B) Rs. 5991 (C) Rs. 6001 (D) Rs. 6991

Answer: Option A
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009. Required sale = Rs. [ (6500 x 6) - 34009 ] = Rs. (39000 - 34009) = Rs. 4991.
1. A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
    (A) 30 days (B) 40 days (C) 60 days (D) 70 days

Answer: Option C
Explanation: Let A's 1 day's work = x and B's 1 day's work = y. Then, x + y = [latex]\frac{1 }{30 }[/latex] and 16x + 44y = 1. Solving these two equations, we get: x = [latex]\frac{1 }{60 }[/latex] and y = [latex]\frac{1 }{60 }[/latex] B's 1 day's work = [latex]\frac{1 }{60 }[/latex] Hence, B alone shall finish the whole work in 60 days.
1. The fourth proportional to 5, 8, 15 is:
    (A) 18 (B) 24 (C) 19 (D) 20

Answer: Option B
Explanation: Let the fourth proportional to 5, 8, 15 be x. Then, 5: 8 : 15: x 5x = (8 x 15) x = [latex]\frac{8 × 15 }{5}[/latex]
1. The fourth proportional to 5, 8, 15 is:
    (A) 18 (B) 24 (C) 19 (D) 20

Answer: Option B
Explanation: Let the fourth proportional to 5, 8, 15 be x. Then, 5: 8 : 15: x 5x = (8 x 15) x = [latex]\frac{8 × 15 }{5}[/latex]
The bar graph given below shows the sales of books (in thousand number) from six branches of a publishing company during two consecutive years 2000 and 2001. Sales of Books (in thousand numbers) from Six Branches - B1, B2, B3, B4, B5 and B6 of a publishing Company in 2000 and 2001.

1. What is the ratio of the total sales of branch B2 for both years to the total sales of branch B4 for both years?
    (A) 2:3 (B) 3:5 (C) 4:5 (D) 7:9

Answer: Option B
Explanation: Required ratio = [latex]\frac{(75 + 65) }{(85 + 95) }[/latex] = [latex]\frac{140 }{180 }[/latex] = [latex]\frac{7 }{9 }[/latex]

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