Q1. Look at this series: 8, 6, 9, 23, 87 , ... What number should come next?

A. 128 B. 226 C. 324 D. 429 E. None of these

Answer: Option D
Explanation: 8 x 1 - 2 = 6 6 x 2 - 3 = 9 9 x 3 - 4 = 23 23 x 4 - 5 = 87 87 x 5 - 6 = 429 ..
Q2. Look at this series: 201, 202, 204, 207, ... What number should come next?

A. 205 B. 208 C. 210 D. 211

Answer: Option D
Explanation:
Q3. Look at this series: 3, 4, 7, 8, 11, 12, ... What number should come next?

A. 7 B. 10 C. 14 D. 15 E. None of these

Answer: Option D
Explanation: This alternating addition series begins with 3; then 1 is added to give 4; then 3 is added to give 7; then 1 is added, and so on.
Q4. Look at this series: 8, 22, 8, 28, 8, ... What number should come next?

A. 9 B. 29 C. 32 D. 34

Answer: Option D
Explanation: This is a simple addition series with a random number, 8, interpolated as every other number. In the series, 6 is added to each number except 8, to arrive at the next number.
Q5. A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?

A. Rs. 375 B. Rs. 400 C. Rs. 600 D. Rs. 800

Answer: Option B
Explanation: C's 1 day's work = [latex]\frac{1}{3}[/latex] - [[latex]\frac{1}{6}[/latex] + [latex]\frac{1}{8}[/latex]] = [latex]\frac{1}{3}[/latex] - [latex]\frac{7}{24}[/latex] = [latex]\frac{1}{24}[/latex] A's wages : B's wages : C's wages = [latex]\frac{1}{6}[/latex]: [latex]\frac{1}{8}[/latex]: [latex]\frac{1}{24}[/latex] = 4 : 3 : 1. C's share (for 3 days) = Rs. [ 3 x [latex]\frac{1}{24}[/latex] x 3200] = Rs. 400

Q1. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

A. 4 days B. 5 days C. 6 days D. 7 days

Answer: Option A
Explanation: Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y. Then, 6x + 8y = [latex]\frac{1}{10}[/latex] and 26x + 48y = [latex]\frac{1}{2}[/latex] Solving these two equations, we get x = [latex]\frac{1}{100}[/latex] and y = [latex]\frac{1}{200}[/latex] (15 men + 20 boy)'s 1 day's work = [ [latex]\frac{15}{100}[/latex] + [latex]\frac{20}{200}[/latex]] = [latex]\frac{1}{4}[/latex] 15 men and 20 boys can do the work in 4 days.
Q2. A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?

A. 8 hours B. 10 hours C. 12 hours D. 24 hours

Answer: Option C
Explanation: A's 1 hour's work = [latex]\frac{1}{4}[/latex] (B + C)'s 1 hour's work = [latex]\frac{1}{3}[/latex] (A + C)'s 1 hour's work = [latex]\frac{1}{2}[/latex] (A + B + C)'s 1 hour's work = [latex]\frac{1}{4}[/latex] + [latex]\frac{1}{3}[/latex] = [latex]\frac{7}{12}[/latex] B's 1 hour's work = [ [latex]\frac{7}{12}[/latex] - [latex]\frac{1}{2}[/latex]] = [latex]\frac{1}{12}[/latex] B alone will take 12 hours to do the work.
Q3. A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in

A. 15 days B. 20 days C. 25 days D. 30 days

Answer: Option C
Explanation: (A + B)'s 1 day's work = [latex]\frac{1}{10}[/latex] C's 1 day's work = [latex]\frac{1}{50}[/latex] (A + B + C)'s 1 day's work = [latex]\frac{1}{10}[/latex] + [latex]\frac{1}{50}[/latex] = [latex]\frac{6}{50}[/latex] = [latex]\frac{3}{25}[/latex].... (i) A's 1 day's work = (B + C)'s 1 day's work .... (ii) From (i) and (ii), we get: 2 x (A's 1 day's work) = [latex]\frac{3}{25}[/latex] A's 1 day's work = [latex]\frac{3}{50}[/latex] B's 1 day's work = [latex]\frac{1}{10}[/latex] - [latex]\frac{3}{50}[/latex] = [latex]\frac{2}{50}[/latex] = [latex]\frac{1}{25}[/latex] So, B alone could do the work in 25 days.
Q4. A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ?

A. 11:30 A.M. B. 12 noon C. 12:30 P.M. D. 1:00 P.M.

Answer: Option D
Explanation: (P + Q + R)'s 1 hour's work = [latex]\frac{1}{8}[/latex] + [latex]\frac{1}{10}[/latex] + [latex]\frac{1}{12}[/latex] = [latex]\frac{37}{120}[/latex] Work done by P, Q and R in 2 hours = [latex]\frac{37}{120}[/latex] x 2 = [latex]\frac{37}{60}[/latex] Remaining work = 1 - [latex]\frac{37}{60}[/latex] = [latex]\frac{23}{60}[/latex] (Q + R)'s 1 hour's work = [[latex]\frac{1}{10}[/latex] + [latex]\frac{1}{12}[/latex] ] = [latex]\frac{11}{60}[/latex] Now, [latex]\frac{11}{60}[/latex] work is done by Q and R in 1 hour. So, [latex]\frac{23}{60}[/latex] work will be done by Q and R in [latex]\frac{60}{11}[/latex] x [latex]\frac{23}{11}[/latex] hours = 2 hours So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M.
Q5. 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?

A. 35 B. 40 C. 45 D. 50

Answer: Option B
Explanation: Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y. Then, 4x + 6y = [latex]\frac{1}{8}[/latex] and 3x + 7y = [latex]\frac{1}{10}[/latex] Solving the two equations, we get: x = [latex]\frac{11}{400}[/latex], y = [latex]\frac{1}{40}[/latex] Hence, 10 women will complete the work in 40 days.

Q1. The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:

A. 17 kg B. 20 kg C. 26 kg D. 31 kg

Answer: Option D
Explanation: Let A, B, C represent their respective weights. Then, we have: A + B + C = (45 x 3) = 135 .... (i) A + B = (40 x 2) = 80 .... (ii) B + C = (43 x 2) = 86 ....(iii) Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv) Subtracting (i) from (iv), we get : B = 31. B's weight = 31 kg.
Q2. The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.

A. 47.55 kg B. 48 kg C. 48.55 kg D. 49.25 kg

Answer: Option C
Explanation: Required average = [latex]\frac{50.25 × 16 + 45.15 × 8}{16 + 8}[/latex] = [latex]\frac{804 + 361.20}{24}[/latex] = [latex]\frac{1165.20}{24}[/latex] 48.55
Q3. The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is

A. 15 B. 16 C. 18 D. 25

Answer: Option B
Explanation: Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x. S.P. of x articles = Rs. 20. Profit = Rs. (20 - x). [latex]\frac{20 - x}{x}[/latex] x 100 = 25 2000 - 100x = 25x 125x = 2000 x = 16.
Q4. In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?

A. 30% B. 70% C. 100% D. 250%

Answer: Option B
Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125 New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295. Required percentage = [[latex]\frac{295}{420}[/latex] x 100]% = [latex]\frac{1475}{21}[/latex]% 70% (approximately)
Q5. A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?

A. 3 B. 4 C. 5 D. 6

Answer: Option C
Explanation: C.P. of 6 toffees = Re. 1 S.P. of 6 toffees = 120% of Re. 1 = Rs [latex]\frac{6}{5}[/latex] For Rs. , toffees sold = 6. For Re. 1, toffees sold = 6 x [latex]\frac{5}{6}[/latex] = 5