Q1.A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

A. 120 metres B. 180 metres C. 324 metres D. 150 metres

Answer: Option D
Explanation: Speed = 60 x [latex]{5}{18}[/latex] m/sec = [latex]{50}{3}[/latex] m/sec Length of the train = (Speed x Time). Length of the train = [latex]{50}{3}[/latex] x 9 m = 150 m
Q2. The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:

A. 9000 B. 9400 C. 9600 D. 9800

Answer: Option C
Explanation: Greatest number of 4-digits is 9999. L.C.M. of 15, 25, 40 and 75 is 600. On dividing 9999 by 600, the remainder is 399. Required number (9999 - 399) = 9600.
Q3. The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

A. 101 B. 107 C. 111 D. 185

Answer: Option C
Explanation: Let the numbers be 37a and 37b. Then, 37a x 37b = 4107 ab = 3. Now, co-primes with product 3 are (1, 3). So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Q4. If log 27 = 1.431, then the value of log 9 is:

A. 0.934 B. 0.945 C. 0.954 D. 0.958

Answer: Option C
Explanation: log 27 = 1.431 log ([latex]{3}^{3}[/latex] ) = 1.431 3 log 3 = 1.431 log 3 = 0.477 log 9 = log([latex]{3}^{2}[/latex] ) = 2 log 3 = (2 x 0.477) = 0.954.
Q5. A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:

A. [latex]\frac{1}{13}[/latex] B. [latex]\frac{2}{13}[/latex] C. [latex]\frac{1}{26}[/latex] D. [latex]\frac{1}{52}[/latex]

Answer: Option C
Explanation: Here, n(S) = 52. Let E = event of getting a queen of the club or a king of heart. Then, n(E) = 2. P(E) = [latex]\frac{ n(E)}{n(S) }[/latex] [latex]\frac{2}{52}[/latex] = [latex]\frac{1}{26}[/latex]
Q6. Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

A. 1 [latex]\frac{13}{17}[/latex] hours B. 2 [latex]\frac{8}{11}[/latex] hours C. 3 [latex]\frac{9}{17}[/latex] hours D. 4 [latex]\frac{1}{2}[/latex] hours

Answer: Option C
Explanation: Net part filled in 1 hour [latex]\frac{13}{17}[/latex]
Q7. 6, 9, 15, 21, 24, 28, 30

A. 28 B. 21 C. 24 D. 30

Answer: Option A
Explanation: Each of the numbers except 28, is a multiple of 3.
Q8. 331, 482, 551, 263, 383, 362, 284

A. 263 B. 383 C. 331 D. 551

Answer: Option B
Explanation: In each number except 383, the product of first and third digits is the middle one.
Q9. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is::

A. Rs. 45 B. Rs. 50 C. Rs. 55 D. Rs. 60

Answer: Option D
Explanation: (C.P. of 17 balls) - (S.P. of 17 balls) = (C.P. of 5 balls) C.P. of 12 balls = S.P. of 17 balls = Rs.720. C.P. of 1 ball = Rs. [latex]\frac{720}{12}[/latex] = Rs. 60.
Q10. The least perfect square, which is divisible by each of 21, 36 and 66 is:

A. 213444 B. 214344 C. 214434 D. 231444

Answer: Option A
Explanation: L.C.M. of 21, 36, 66 = 2772. Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11 To make it a perfect square, it must be multiplied by 7 x 11. So, required number = [latex]{2}^{2}[/latex] x [latex]{3}^{2}[/latex] x [latex]{7}^{2}[/latex] x [latex]{11}^{2}[/latex] = 213444
Q11. Dynamic Host Configuration Protocol [DHCP]

A. is the same as bootp B. uses static allocation of IP addresses C. helps prevent conflicts between assigned IP addresses D. assigns IP addresses, which when allocated, cannot be reused

Answer: Option C
Q12. The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A. 25% increase B. 50% increase C. 50% decrease D. 75% decrease

Answer: Option B
Explanation: Let original length = x and original breadth = y. Original area = xy. New length = [latex]\frac{X}{2}[/latex] New breadth = 3y. New area = [latex]\frac{X}{2}[/latex] X 3y = [latex]\frac{3}{2}[/latex]xy Increase % = [latex]\frac{1}{2}[/latex]xy x [latex]\frac{1}{xy}[/latex] x 100 = 50%
Q13. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A. 40 B. 50 C. 120 D. 60

Answer: Option D
Explanation: Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = [latex]\frac{5300}{26.50}[/latex] = 200 m. 2[(x + 20) + x] = 200 2x + 20 = 100 2x = 80 x = 40. Hence, length = x + 20 = 60 m.
Q14. A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

A. 34 B. 40 C. 68 D. 88

Answer: Option D
Explanation: We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.
Q15. A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:

A. 14 years B. 19 years C. 33 years D. 38 years

Answer: Option A
Explanation: Let the son's present age be x years. Then, (38 - x) = x 2x = 38. x = 19. Son's age 5 years back (19 - 5) = 14 years.