1. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

A. 39, 30 B. 41, 32 C. 42, 33 D. 43, 34

Answer: Option C
Explanation: Let their marks be (x + 9) and x. Then, x + 9 = [latex]\frac{56}{100}[/latex](x + 9 + x) 25(x + 9) = 14(2x + 9) 3x = 99 x = 33 So, their marks are 42 and 33
2. A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:

A. 588 apples B. 588 apples C. 672 apples D. 700 apples

Answer: Option D
Explanation: Suppose originally he had x apples. Then, (100 - 40)% of x = 420. [latex]\frac{60}{100}[/latex] x x = 420 x = [latex]\frac{420 × 100}{60}[/latex] = 700.
3. A grocer has a sales of Euro 6435, Euro 6927, Euro 6855, Euro 7230 and Euro 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Euro 6500?

A. Euro 4991 B. Euro 5991 C. Euro 6001 D. Euro 6991

Answer: Option A
Explanation: Total sale for 5 months = Euro (6435 + 6927 + 6855 + 7230 + 6562) = Euro 34009. Required sale = Euro [ (6500 x 6) - 34009 ] = Euro (39000 - 34009) = Euro 4991.
4. The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

A. 0 B. 1 C. 10 D. 19

Answer: Option D
Explanation: Average of 20 numbers = 0. Sum of 20 numbers (0 x 20) = 0. It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
5. Look at this series: 7, 10, 8, 11, 9, 12, ... What number should come next?

A. 7 B. 10 C. 12 D. 13

Answer: Option A
Explanation: This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted.
6. Look at this series: 36, 34, 30, 28, 24, ... What number should come next?

A. 20 B. 22 C. 23 D. 26

Answer: Option A
Explanation: This is an alternating number subtraction series. First, 2 is subtracted, then 4, then 2, and so on.
7. A sum of money at simple interest amounts to 815 in 3 years and to 854 in 4 years. The sum is:

A. 650 B. 690 C. 698 D. 700

Answer: Option C
Explanation: S.I. for 1 year = (854 - 815) = 39. S.I. for 3 years = (39 x 3) = 117. Principal = (815 - 117) = 698.
8. Mr. Thomas invested an amount of 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be 3508, what was the amount invested in Scheme B?

A. 6400 B. 6500 C. 7200 D. 7500

Answer: Option A
Explanation: Let the sum invested in Scheme A be x and that in Scheme B be (13900 - x). Then, [latex]\frac{x × 14 × 2 }{100}[/latex] + [latex]\frac{(13900 - x) × 11 × 2) }{100}[/latex]= 3508 28x - 22x = 350800 - (13900 x 22) 6x = 45000 x = 7500. So, sum invested in Scheme B = (13900 - 7500) = 6400.
9. A sum fetched a total simple interest of 4016.25 at the rate of 9 %.p.a. in 5 years. What is the sum?

A. 4462.50 B. 8032.50 C. 8925 D. None of these

Answer: Option C
Explanation: Principal = [latex]\frac{(100 × 4016.25) }{(9 x 5)}[/latex] = [latex]\frac{401625 }{45}[/latex] = 8925.
10. Reena took a loan of 1200 with simple interest for as many years as the rate of interest. If she paid 432 as interest at the end of the loan period, what was the rate of interest?

A. 3.6 B. 6 C. 18 D. Cannot be determined

Answer: Option B
Explanation: Let rate = R% and time = R years. Then, [latex]\frac{(1200 × R × R) }{100}[/latex] = 432 12R² = 432 R² = 36 R = 6.
11. Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

A. [latex]\frac{1 }{2}[/latex] B. [latex]\frac{2 }{5}[/latex] C. [latex]\frac{8 }{15}[/latex] D. [latex]\frac{9 }{20}[/latex]

Answer: Option D
Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}. Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}. P(E) = [latex]\frac{n(E)}{n(S)}[/latex] = [latex]\frac{9 }{20}[/latex].
12. In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?

A. [latex]\frac{1 }{10}[/latex] B. [latex]\frac{2 }{5}[/latex] C. [latex]\frac{2 }{7}[/latex] D. [latex]\frac{5 }{7}[/latex]

Answer: Option C
Explanation: P (getting a prize) = [latex]\frac{10 }{(10+25)}[/latex] = [latex]\frac{10}{35}[/latex] = [latex]\frac{2 }{7}[/latex]
13. A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.

A. 2 hours B. 3 hours C. 4 hours D. 4 hours

Answer: Option C
Explanation: Speed downstream = (13 + 4) km/hr = 17 km/hr. Time taken to travel 68 km downstream = [latex]\frac{68 }{17}[/latex] hrs = 4 hrs
14. In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is:

A. 3 km/hr B. 5 km/hr C. 8 km/hr D. 9 km/hr

Answer: Option C
Explanation: Speed in still water = [latex]\frac{1 }{2x}[/latex] (11 + 5) kmph = 8 kmph.
15. Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is:

A. 16 hours B. 18 hours C. 20 hours D. 24 hours

Speed upstream = 7.5 kmph. Speed downstream = 10.5 kmph. Total time taken = [latex]\frac{105 }{7.5}[/latex] + [latex]\frac{105 }{10.5}[/latex] hours = 24 hours