1. 5 20 320 1280 20480 ?

A. 71960 B. 42480 C. 32340 D. 81920

Answer - Option D
Explanation - Series Pattern Given Series
5 5
5 × 4 20
20 × 16 320
320 × 4 1280
1280 × 16 20480
20480 × 4 81920
Hence, option D is correct.
2. 19 27 43 ? 139 267

A. 90 B. 85 C. 65 D. None of these

Answer - Option D
Explanation - Series Pattern Given Series
19 19
19 × 2 – 11 27
27 × 2 – 11 43
43 × 2 – 11 75
75 × 2 – 11 139
139 × 2 – 11 267
Hence, option D is correct.
3. 10 16 34 70 130 ?

A. 116 B. 220 C. 312 D. 224

Answer - Option B
Explanation - Series Pattern Given Series
9 + 13 10
8 + 23 16
7 + 33 34
6 + 43 70
5 + 53 130
4 + 63 220
Hence, option B is correct.
4. 135135 12285 1365 195 ? 13

A. 13 B. 26 C. 39 D. 52

Answer - Option C
Explanation - Series Pattern Given Series
135135 135135
135135 ÷ 11 12285
12285 ÷ 9 1365
1365 ÷ 7 195
195 ÷ 5 39
39 ÷ 3 13
Hence, option C is correct.
5. 9 13 20 36 79 ?

A. 195 B. 210 C. 203 D. 205

Answer - Option c
Explanation -
Series I : 9 13 20 36 79 ?
Sereis II : 4 7 16 43 ?
Series III : 3 9 27 ?
Series IV : ×3 ×3 ×3
Clearly, the pattern in series IV is multiples of 3.
So, the missing term in series III = 27 × 3 = 81
∴ missing term in series II = 43 + 81 = 124;
∴ missing term in series I = 79 + 124 = 203.
Series I : 9 13 20 36 79 203
Sereis II : 4 7 16 43 124
Series III : 3 9 27 81
Series IV : ×3 ×3 ×3
Hence, option C is correct.

1. Rahul is a Science graduate with 65% marks and has completed post-graduation in Finance. He completed 26 years of age in 2016 and has four years’ experience as a Senior Manager. He is ready to join on one-year probation.

A. if the candidate is to be selected. B. if the data given are not sufficient to take any decision. C. if the case is to be referred to the Asst General Manager. D. if the case is to be referred to the General Manager.

Answer - Option C
2. Mukul is a gold medalist CA and Class I graduate with 77% and 82% marks respectively. He has been working as a professor in Finance for the past four years and has also been a freelance Finance Consultant for the past two years.

A. if the case is to be referred to Executive Head. B. if the case is to be referred to Vice President. C. if the candidate is to be selected. D. if the information is inadequate to take a decision.

Answer - Option D
3. Shivani, a 27-year-old Commerce graduate with 62% post-graduated in Finance with 72% marks. She has been working with a Finance organisation for the last two years. She is ready to join on one-year probation.

A. if the case is to be referred to Executive Head. B. if the case is to be referred to Vice President. C. if the candidate is to be selected. D. if the candidate is not to be selected.

Answer - Option D
4. Avneesh is a Commerce graduate with 74% marks and has been working for the past eight years during which he worked as Accounts Manager for two years. He is pursuing ICWA. He was born on 05.10.1985 and is ready to join on one-year probation.

A. if the case is to be referred to Executive Head. B. if the case is to be referred to Vice President. C. if the candidate is to be selected. D. if the candidate is not to be selected.

Answer - Option D
5. Aditya has been working as Senior Manager for the past eight years. He has completed MBA Finance and graduation with 70% marks each and is ready to join on probation for a year. He was born on 19th March 1984.

A. if the case is to be referred to Executive Head. B. if the case is to be referred to Vice President. C. if the candidate is to be selected. D. if the candidate is not to be selected.

Answer - Option A

1. If in the above word all the vowels are changed to their next letter while all the consonants are changed to their previous letter then the letters of the word thus formed are to be arranged in alphabetic order from left to right end then how many letters are there in alphabetic series between the letters that are fourth from the left end and third from the right end in newly formed word?

A. Ten B. Thirteen C. Five D. Eight

Answer - Option D
Explanation - The given word = EQUANIMITY
After changing all the vowels of the above word to their next letter and all the consonants to their previous letter, we get: FPVBMJLJSX
After, arranging the letters of the above word in alphabetic order from left to right end, we get: BFJJLMPSVX
Now, the fourth letter from the left end is J and third letter from the right end is S.
BFJJLMPSVX
And the letters between ‘J’ and ‘S’ in alphabetic series are ‘8’.
Hence, the correct answer is option E.
2. If in the word ‘FAVOURITE’ all the consonants are arranged on the left in reversed alphabetical order after that on the right of these consonants all the vowels are arranged in alphabetical order then how many letters are there in alphabetical series between third letter from right end and fourth letter from left end?

A. 2 B. 5 C. 6 D. 8

Answer - Option A
Explanation - We have,
The given word = FAVOURITE
After arranging all the consonants on the left in reversed alphabetical order, we get: VTRF
Now, arranging all the vowels on the right of these consonants, we get: VTRFAEIOU
Here, the third letter from right end is I and fourth letter from left end F.
And, we know that there are two letters between F and I in alphabetical series.
Hence, the correct answer is option A.
3. If in the word ‘CAPITALIZATION’ all the letters are arranged in alphabetic order then how many vowels are replaced by a new vowel?

A. None B. One C. Two D. Three

Answer - Option C
Explanation - We have,
The given word = CAPITALIZATION
After arranging the letters in alphabetic order the word becomes = AAACIIILNOPTTZ
Before C A P I T A L I Z A T I O N
After A A A C I I I L N O P T T Z
Here, there are two such vowels which are replaced by a new vowel.
Hence, the correct answer is option C.
4. If the letter of the words ‘FUTURISTIC’ are arranged in alphabetic order from left to right then what would be the third letter of the meaningful English word formed using third, fifth, sixth and eighth letter of the word formed after arranging? (If no word is formed mark ‘L’ as your answer and if more than one word are formed mark ‘M’ as your answer)

A. R B. I C. S D. L

Answer - Option B
Explanation - We have, the given word = FUTURISTIC
After arranging the letters of the word in alphabetic order from left to right we get = CFIIRSTTUU
Now, the third, fifth, sixth and eighth letter of the word ‘CFIIRSTTUU’ are I, R, S and T.
The meaningful English word that can be formed using I, R, S and T is STIR.
STIR – move a spoon or other implement round and round in (a liquid or other substance) in order to mix it thoroughly.
Here, the third letter of the word ‘STIR’ is ‘I’.
Hence, the correct answer is option B.
5. How many such pair(s) of letters are there in the word ‘ELOQUENT’ which has as many letters between them as in the alphabetical series?

A. None B. One C. Two D. Three

Answer - Option
Explanation - We have,
E L O Q U E N T
Possible pair of letters in the above word which has as many letters between them as in the English alphabetical series:
Pair 1:
Letters in the word O Q U E N T
Letters in the alphabetical series O P Q R S T
Pair 2:
Letters in the word Q U E N
Letters in the alphabetical series Q P O N
Here, we can observe that there are two such possible pairs of letters satisfy the above conditions.
Hence, the correct answer is option C.

1. A dice is numbered from 1 to 6 in different ways.If 1 is adjacent to 2, 4 and 6, then which of the following statements is necessarily true?

A. 2 is opposite to 6 B. 1 is adjacent to 3 C. 3 is adjacent to 5 D. 3 is opposite to 5

Answer - Option C
Explanation - If 1 is adjacent to 2, 4 and 6 then either 3 or 5 lies opposite to 1. So, the numbers 3 and 5 cannot lie opposite to each other. Hence, 3 is adjacent to 5 (necessarily).
2. Four usual dice are thrown on the ground. The total of numbers on the top faces of these four dice is 13 as the top faces showed 4, 3, 1 and 5 respectively. What is the total of the faces touching the ground?

A. 12 B. 13 C. 15 D. Cannot be determined

Answer - Option C
Explanation - In a usual dice, the sum of the numbers on any two opposite faces is always 7. Thus, 1 is opposite 6, 2 is opposite 5 and 3 is opposite 4.
Consequently, when 4, 3, 1 and 5 are the numbers on the top faces, then 3, 4, 6 and 2 respectively are the numbers on the face touching the ground. The total of these numbers = 3 + 4 + 6 + 2 = 15.

1. A certain number of persons were sitting in a row facing north such that the number of persons on the right of Roop was the same as the number of persons on the left of Gaur. Gaur sits on the left of Roop. Deep sits exactly in the middle of Roop and Gaur, and the number of persons between Deep and Roop was twice the number of persons on the right of Roop, who was 58th from the left end. How many person(s) were there in the row?

A. 35 B. 55 C. 69 D. 72

Answer - Option C
Explanation - Final Solution:
Order of persons in the row = 11 persons + Gaur + 22 persons + Deep + 22 persons + Roop + 11 persons
Total number of persons in the row = 69 persons.
The number of persons on the right of Roop was the same as the number of persons on the left of Gaur.
Gaur sits on the left of Roop.
Deep sits exactly in the middle of Roop and Gaur
Inference:
Let’s assume that number of persons on the right of Roop and on the left of Gaur was X, and the number of persons
between Deep and Roop, and Gaur and Deep are Y. Then,
Order of persons in the row = X persons + Gaur + Y persons + Deep + Y persons + Roop + X persons
Reference:
The number of persons between Deep and Roop were twice the number of persons on the right of Roop, who was 58th from the left end.
Inference:
After using the above references, we have:
Position of Roop from left end = 58th
And, Number of persons between Deep and Roop was twice the number of persons on the right of Roop i.e. 2X = Y.
Here, the number of persons to the left of Roop in the row = X persons + Gaur + Y persons + Deep + Y persons.
Now, 57 = X persons + 1 + 2X persons + 1 + 2X persons
X = 11 persons
Then,Order of persons in the row = 11 persons + Gaur + 22 persons + Deep + 22 persons + Roop + 11 persons
2. A certain number of persons were sitting in a row facing north such that the number of persons on the right of Roop was the same as the number of persons on the left of Gaur. Gaur sits on the left of Roop. Deep sits exactly in the middle of Roop and Gaur, and the number of persons between Deep and Roop was twice the number of persons on the right of Roop, who was 58th from the left end. What is the position of Deep from the right end of the row?

A. 20th B. 25th C. 30th D. 35th

Answer - Option D
Explanation - Final Solution: Order of persons in the row = 11 persons + Gaur + 22 persons + Deep + 22 persons + Roop + 11 persons
Total number of persons in the row = 69 persons.
Reference:
Number of persons on the right of Roop was same as the number of persons on the left of Gaur.
Gaur sits on the left of Roop.
Deep sits exactly in the middle of Roop and Gaur.
Inference:
Let’s assume that number of persons on the right of Roop and on the left of Gaur was X, and the number of persons between Deep and Roop, and Gaur and Deep are Y. Then,
Order of persons in the row = X persons + Gaur + Y persons + Deep + Y persons + Roop + X persons
Reference:
The number of persons between Deep and Roop was twice the number of persons on the right of Roop, who was 58th from the left end.
Inference:
After using the above references, we have:
Position of Roop from left end = 58th
And, Number of persons between Deep and Roop was twice the number of persons on the right of Roop i.e. 2X = Y.
Here, the number of persons to the left of Roop in the row = X persons + Gaur + Y persons + Deep + Y persons.
Now, 57 = X persons + 1 + 2X persons + 1 + 2X persons
X = 11 persons
Then,Order of persons in the row = 11 persons + Gaur + 22 persons + Deep + 22 persons + Roop + 11 persons

1. It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A. Sunday B. Saturday C. Friday D. Wednesday

Answer - Option C
Explanation - On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan 2010, it is Friday.
2. Today is Monday. After 61 days, it will be:

A. Wednesday B. Saturday C. Tuesday D. Thursday

Answer - Option B
Explanation - Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.

Directions to Solve
In each of the following questions, you are given a figure (X) followed by four alternative figures (1), (2), (3) and (4) such that figure (X) is embedded in one of them. Trace out the alternative figure which contains fig. (X) as its part.
1. Find out the alternative figure which contains figure (X) as its part.

A. 1 B. 2 C. 3 D. 4

Answer - Option D
2. Find out the alternative figure which contains figure (X) as its part.

A. 1 B. 2 C. 3 D. 4

Answer - Option C

1. Pointing to a photograph of a boy Suresh said, "He is the son of the only son of my mother." How is Suresh related to that boy?

A. Brother B. Uncle C. cousin D. Father

Answer - Option D
Explanation - The boy in the photography is the only son of the son of suresh mother i.e., the son of suresh Hence, suresh is the father of boy.
2. If A + B means A is the mother of B; A - B means A is the brother B; A % B means A is the father of B and A x B means A is the sister of B, which of the following shows that P is the maternal uncle of Q?

A. Q - N + M x P B. P + S x N - Q C. P - M + N x Q D. Q - S % P

Answer - Option C
Explanation - P - M → P is the brother of M
M + N → M is the mother of N
N x Q → N is the sister of Q
Therefore, P is the maternal uncle of Q.