1. Compounds which have different arrangements of atoms in space while having same atoms bonded to each other are said to have
A. position isomerism
B. functional group isomerism
C. chain isomerism
D. stereoisomerism
Answer - Option D
Explanation:
Stereoisomer his contrasts with structural isomers, which share the same molecular formula, but the bond connections or their order differs. By definition, molecules that are stereoisomers of each other represent the same structural isomer.
2. Which of the following can make difference in optical isomers?
A. heat
B. temperature
C. polarized light
D. pressure
Answer - Option C
Explanation:
An optically active substance is one which can rotate the plane of polarisation of plane polarised light. if you shine a beam of polarised monochromatic light (light of only a single frequency – in other words a single colour) through a solution of an optically active substance, when the light emerges, its plane of polarisation is found to have rotated.
3. Which of the following Fischer projections is different from the other three?
Answer - Option D
Explanation:
When comparing Fischer projections, it is important to recognize that the horizontal bonds point out of the page, and vertical bonds point into the page. If a substituent is held in place, and the other three substituents are rotated, the new structure is the same as the original structure. Holding the phenyl substituent of 4 in place and rotating the other three clockwise gives 1, so these structures are the same.
4. What is the stereochemical relationship between the following two molecules?
A. Geometrical isomers
B. Enantiomers
C. Diastereomers
D. Identical
Answer - Option D
Explanation:
Both molecules have the same molecular formula ([latex]{C}_{9}[/latex][latex]{H}_{16}[/latex]BrCl) and the same connectivity. Each molecule also has three stereocenters, marked above with an asterisk, and does not contain a plane of symmetry. Therefore, both molecules are chiral. Using one of the methods outlined in this tutorial, it can be determined that these molecules are superimposable. Therefore, the molecules are identical.
5. Which of the following statements can be deduced about the stereochemistry of this compound?
A. This compound is optically active because it has stereogenic centers that create cis-trans isomers
B. This compound is optically active because the compound contains a center, plane, or axis of chirality
C. This compound is not optically active since there are no stereogenic centers
D. This compound is not optically active because of its symmetry
Answer - Option A
Explanation:
In identifying stereogenic centers, any quaternary or tertiary carbons would be a good place to look. There are no quaternary carbons, and all the tertiary carbons are part of a benzene ring structure.