1. A shopkeeper sells his gods at its CP only. But he uses 650 g weight at the place of 1000 g weight for a kg. What is his net profit percentage?

A. 55% B. 20 [latex]\frac {1}{3}[/latex]% C. 49 [latex]\frac {2}{3}[/latex]% D. 53 [latex]\frac {11}{13}[/latex]% E. None of These

2. A seller calculated his intended selling price at 6% profit on the cost of a product. However, owing to some mistake while selling, the units and tens digits of the selling price got interchanged. This reduced the profit by Rs. 180 and profit percentage to 2.4%. What is the cost price of the product?

A. Rs. 4500 B. Rs. 5000 C. Rs. 4750 D. Rs. 6000 E. None of these

3. Veena bought a watch costing Rs. 1404 including sales tax at 8%. She asked the shopkeeper to reduce the price of the watch so that she can save the amount equal to the tax. The reduction of the price of the watch is?

A. Rs. 108 B. Rs. 104 C. Rs. 112 D. Rs. 120 E. None of these

4. A Sales Executive gets a commission on total sales at 8%. If the sale is exceeded Rs.10,000 he gets an additional commission as a bonus of 4% on the excess of sales over Rs.10,000. If he gets the total commission of Rs.950, then the bonus he received is?

A. 40 B. 50 C. 36 D. 48 E. None of these

5. An amount of money is to be divided between P, Q and R in the ratio of 3:7:12. If the difference between the shares of P and Q is Rs.X, and the difference between Q and R’s share is Rs.3000. Find the total amount of money?

A. 11000 B. 12400 C. 13200 D. None of these E.

Answers and Explanations
1. Answer - Option D
Explanation -
His profit% = [latex]\frac {350}{650} \times 100 = 53 \frac {11}{13}%[/latex]
2. Answer - Option B
Explanation -
Profit % reduced = 6 - 2.4 = 3.6%
i.e, Rrquired CP = [latex]\frac {180}{3.6} \times 100[/latex]
= 5000 Rs.
3. Answer - Option B
Explanation -
1.08x = 1404
x = 1300
The reduction of the price of the watch = 104
4. Answer - Option B
Explanation -
Commission up to [latex]10000 = 10000 \times \frac {8}{100} = 800[/latex]
Ratio = 2x:x ; Commission = 2x, Bonus = x ;
Bonus = [latex]950 – 800 \times \frac {1}{3} = 150 \times \frac {1}{3} = 50[/latex]
5. Answer - Option c
Explanation -
12a-7a = 3000
5a = 3000
a = 600
7a - 4a = x
3a = x
x = 1800
[latex]22 \times 600 = 13200[/latex]

1. A sum of Rs.4880 was divided among boys and girls in such a way that each boy gets Rs.44.50 and each girl get Rs. 55.25. If the total number of girls and boys is 100, find the number of girls?

A. 60 B. 50 C. 40 D. 30 E. None of these

2. The income of Vinay and Prakash are in the ratio of 4:5 and their expenditure is in the ratio of 2:3. If each of them saves 5000, then find their income.

A. 11000, 8550 B. 12000, 7750 C. 15000, 8750 D. 13000, 9780 E. None of these

3. A Container contains ‘X’ Liters of Milk. A thief stole 50 Liters of Milk and replaced it with the same quantity of water. He repeated the same process further two times. And thus Milk in the container is only ‘X-122’ liters. Then what is the quantity of water in the final mixture?

A. 122 Liter B. 124 Liter C. 128 Liter D. 250 Liter E. Cannot be determined

4. A Container contains 192 liter of Milk. A seller draws out x% of Milk and replaced it with the same quantity of water. He repeated the same process for 3 times. And thus Milk content in the mixture is only 81 liter. Then how much percent he withdraw every time?

A. 10% B. 15% C. 18% D. 20% E. 25%

5. A train running at [latex]\frac {7}{11}[/latex] of its own speed reached a place in 33 hrs. How much time could be saved if the train runs at its own speed?

A. 10 hrs B. 12 hrs C. 8 hrs D. 16 hrs E. None of these

Answers and Explanations
1. Answer - Option C
Explanation -
x + y = 100 ————– (i)
44.50x + 55.25y = 4880 ————– (ii)
Solving (i) and (ii) Y = 40
2. Answer - Option C
Explanation -
4x – 2y = 5000 and 5x – 3y = 5000.
X = 8750, so income = 8750 and 15000
3. Answer - Option A
Explanation -
X-122 = [latex] X {(1 - \frac {50}{x})}^{³}[/latex]
X = 250 Liter
Milk = 250 - 122 = 128
Water = 122
4. Answer - Option E
Explanation -
81 = [latex]192{(1 - \frac {x}{100})}^{³}[/latex]
x = 25
5. Answer - Option B
Explanation -
Distance is same Then
[latex]\frac {{s}_{2}}{{s}_{1}} = \frac {{t}_{1}}{{t}_{2}}[/latex]
[latex]\frac {7}{11} = \frac {{t}_{1}}{33}[/latex]
[latex]\Rightarrow = {t}_{1} = 21 hours[/latex]
Total time saved = 33 - 21 = 12 hours

1. A labourer was appointed by a contractor on the condition he would be paid Rs 150 for each day of his work but would be, fined a the rate of Rs 30 per day for his absent. After 20 days, the contractor paid the laborer’s 2820. Find the number of days he worked:

A. 13 days B. 19 days C. 5 days D. 12 days E. None of these

2. Ramesh can finish a job in 20 days. He worked for 10 days alone and completed the remaining job working with Dinesh, in 2 days. How many days would both Dinesh and Ramesh together take to complete the entire job?

A. 4 B. 5 C. 10 D. 12 E. None of these

3. Ram decided to plough a farmland in 50 days. He employed 50 men in the beginning and 50 more after 35 days and completed the construction in stipulated time. If he had not employed the additional men, how many days behind schedule would it have been finished?

A. 5 days B. 6 days C. 8 days D. 10 days E. None of these

4. Manoj borrowed a certain sum from Anuj at a certain rate of simple interest for 2 years. He lent this sum to Rakesh at the same rate of interest compounded annually for the same period. At the end of two years, he received Rs. 4200 as compound interest but paid Rs. 4000 only as simple interest. Find the rate of interest?

A. 10% B. 20% C. 25% D. 30% E. None of these

5. If a sum on compound interest becomes three times in 4 years, then with the same interest rate, the sum will become 27 times in:

A. 8 years B. 12 years C. 24 years D. 36 years E. None of these

Answers and Explanations
1. Answer - Option B
Explanation -
Let the required number of days = x days
So, 150x - (20 - x)30 = 2820
x = 19 days
2. Answer - Option A
Explanation -
Ramesh alone finished [latex]\frac {1}{2}[/latex] of the work in 10 days.
Remaining [latex]\frac {1}{2}[/latex] was finished by Ramesh and Dinesh together in 2 days.
Therefore, they both together can finish the complete job in 4 days.
3. Answer - Option A
Explanation -
Given that, 50 men employed for 35 days and 50 more men employed for 15 days so that the work could be finished in 50 days.
Thus, the total work [latex]= 50 \times 35 + (50 + 50)15 = 3250[/latex]
Suppose, it takes x days to the finish the whole work, if additional men were not employed.
So, we have an equation here.
50 [latex]\times[/latex] x = 3250
x = 65 days
Therefore, it takes 15 days more than stipulated time.
4. Answer - Option A
Explanation -
Suppose the sum borrowed = Rs X
Rate of interest = R% Time = 2 years
[latex] 4000 = \frac {X x R x 2 }{100}[/latex] [simple interest formula] RX = 200,000………….(1)
compound interest= [latex]P{(1 + \frac {r}{n})}^{nt}[/latex]
[latex]X {1+ \frac {R}{100}}^{2}= X + 4200 [/latex]
after solving and using value of RX
we get R = 10%
5. Answer - Option B