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Nainital Bank Recruitment Quantitative Aptitude – SO & PO

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Nainital Bank Recruitment Quantitative Aptitude – SO & PO

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The Nainital Bank Recruitment Selection Process involves Single Online Exam followed by an interview. The Quantitative Aptitude section, in the Nainital Bank Recruitment SO CBT Exam has a total of 50 questions with a maximum of 50 marks. Every correct answer earns 1 mark and every wrong answer has a penalty of 0.25 i.e 0.25 marks are deducted for every wrong answer.
  • The successful candidates will be called for an interview. After issuance of appointment letter to the selected candidates, he/she will be allowed to join in Officers Cadre of the Bank subject to their being medically fit for the assignment.
  • The Bank reserves the right to reject any application without assigning any reason and no correspondence in this regard will be entertained.

shape Exam Pattern

Nainital Bank Recruitment SO - Exam Pattern
S.No Name Of Test No.of Questions Maximum Marks Duration
1. Reasoning 50 50 40 Minutes
2. English Language 40 40 35 Minutes
3. Quantitative Aptitude 50 50 40 Minutes
4. Professional Knowledge in the related stream. 60 60 40 Minutes
Total 200 200 155 Minutes

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DIRECTIONS(1-5): These questions are based on the following bar graph and line graph. The following bar graph gives the total population of five villages and the number of males in each of the five villages.
The following line graph gives the percentage of literates amount males, for each of the five villages.
1. In which village is the number of females as a percentage of the total population, the lowest?
    A. A B. B C. C D. D E. E

Answer: Option B Explanation: Percentage of females as a percentage of total population in A = [latex]\frac{24000}{64000}[/latex] × 100 = 37.5% B = [latex]\frac{24000}{72000}[/latex] × 100 = 33[latex]\frac{1}{3}[/latex]% C = [latex]\frac{24000}{54000}[/latex] × 100 = 44[latex]\frac{4}{9}[/latex]% D = [latex]\frac{30000}{80000}[/latex] × 100 = 37.5% E = [latex]\frac{36000}{60000}[/latex] × 100 = 60%
2. What is the ratio of the number of illiterate males in B to that in C?
    A. 24 : 5 B. 7 : 16 C. 9 : 13 D. 11 : 19 E. None of these

Answer: Option A Explanation: Total illiterate males in B = 48000 x [latex]\frac{30}{100}[/latex] = 14400 Total illiterate males in C = 300000 x [latex]\frac{10}{100}[/latex] = 3000 The required ratio = [latex]\frac{14400}{3000}[/latex] = 24:5
3. What is the average number of literate males per village?
    A. 32240 B. 24420 C. 28120 D. 29430 E. None of these

Answer: Option C Explanation: The required average = (40000 × [latex]\frac{80}{100}[/latex] + 48000 × [latex]\frac{70}{100}[/latex] + 30000 × [latex]\frac{90}{100}[/latex] + 50000 × [latex]\frac{60}{100}[/latex] + 24000 × [latex]\frac{75}{100}[/latex]/ 5 = 140600/5 = 28120
4. In how many villages is the number of illiterate males, as a percentage of the total population, more than 21%
    A. 1 B. 2 C. 3 D. 4 E. None of these

Answer: Option A Explanation: Percentage of illiterate males in the given villages is as follows. A = [latex]\frac{8000}{64000}[/latex] × 100 = 12.5% B = [latex]\frac{14400}{72000}[/latex] × 100 = 20% C = [latex]\frac{3000}{54000}[/latex] × 100 = 5.55% D = [latex]\frac{20000}{80000}[/latex] × 100 = 25%
5. In which village is the number of literate males, as a percentage of the total population, the lowest?
    A. A B. D C. B D. C E. E

Answer: Option E Explanation: % of litreate males in A = [latex]\frac{32000}{64000}[/latex] × 100 = 50% B = [latex]\frac{33600}{72000}[/latex] × 100 = 46[latex]\frac{2}{3}[/latex]% C = [latex]\frac{27000}{54000}[/latex] × 100 = 50% D = [latex]\frac{30000}{80000}[/latex] × 100 = 37.5% D = [latex]\frac{18000}{60000}[/latex] × 100 = 30% It is the lowest in village E.
DIRECTIONS(1-5): Study the following graph to answer the following questions
Total number of students = 90,000

1. The no of girls students in District T is what % of the total no students in District Q ?
    A. 47% B. 31% C. 37% D. 40% E. 43%

Answer: Option B Explanation: No of girls in T = (12 × [latex]\frac{90000}{100}[/latex]) – 7200 = 10800 – 7200 = 3600 Total no of students in Q = 13×90000/100 = 11700 % = 3600 × [latex]\frac{100}{1700}[/latex]) = 30.77% = 31%
2. What is the average number of boys students in all the districts together?
    A. 7533 B. 7353 C. 7550 D. 7300 E. 7800

Answer: Option A Explanation: ([latex]\frac{6500 + 8900 + 5500 + 9100 + 7200 + 8000}{6}[/latex]) = [latex]\frac{45200}{6}[/latex]
3. What is the difference between the number of girls students in District P and the total number of students in District R?
    A. 11000 B. 9700 C. 10000 D. 10100 E. 10200

Answer: Option D Explanation: Total no. of students in R = ([latex]\frac{22 × 90000 }{100}[/latex]) = 19800 No. of girls in P = ([latex]\frac{18 × 90000 }{100}[/latex]) - 6500 = 9700 Difference = 19800 – 9700 = 10100
4. What is the ratio of the no of boys in District U to the total no of girls in District S ?
    A. 43:76 B. 50:75 C. 53:80 D. 80:53 E. 54:82

Answer: Option D Explanation: Boys in U = 8000 Girls in S = (16×90000/100) – 9100 = 5300 80:53
5. What is the total no of students in District P,R and T ?
    A. 46000 B. 46800 C. 48600 D. 45000 E. 45500

Answer: Option B Explanation: P = 18 × ([latex]\frac{ 90000 }{100}[/latex]) = 16200 R = 22 × ([latex]\frac{ 90000 }{100}[/latex]) = 19800 T = 12 × ([latex]\frac{ 90000 }{100}[/latex]) = 10800 Total = 46,800
1. 8 4 6 15 52.5 ?
    A. 234.50 B. 236.25 C. 152.25 D. 183.75 E. None of these

Answer: Option B
Explanation:
Series Pattern Given Series
8 8
8 × 0.5 × 1 = 4 4
4 × 0.5 × 3 = 6 6
6 × 0.5 × 5 = 15 15
15 × 0.5 × 7 = 52.5 52.5
52.5 × 0.5 × 9 = 236.25 236.25

2. 14 35 98 287 ? 2555
    A. 854 B. 864 C. 860 D. 888 E. None of these

Answer: Option A
Explanation:
Series Pattern Given Series
14 14
14 × 3 – 7 = 35 35
35 × 3 – 7 = 98 98
98 × 3 – 7 = 287 287
287 × 3 – 7 = 854 854
854 × 3 – 7 = 2555 2555

3. 3 4 10 33 136 ?
    A. 680 B. 690 C. 685 D. 675 E. None of these

Answer: Option C
Explanation:
Series Pattern Given Series
3 3
3 × 1 + 1 = 4 4
4 × 2 + 2 = 10 10
10 × 3 + 3 = 33 33
33 × 4 + 4 = 136 136
136 × 5 + 5 = 685 685

4. 40 31 47 22 58 ?
    A. 24 B. 11 C. 17 D. 10 E. None of these

Answer: Option E
Explanation:
Series Pattern Given Series
40 40
40 – 32 = 31 31
31 + 42 = 47 47
47 – 52 = 22 22
22 + 62 = 58 58
58 – 72 = 9 9

5. 75 58 39 16 -13 ?
    A. -18 B. -44 C. 18 D. -42 E. None of these

Answer: Option B
Explanation:
Series Pattern Given Series
75 75
75 - 17 = 58 58
58 - 19 = 39 39
39 - 23 = 16 16
16 - 29 = -13 -13
- 13 - 31 = – 44 -44

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