Direction to solve(1 to 5): The following pie-chart shows the percentage distribution of the expenditure incurred in publishing a book. Study the pie-chart and the answer the questions based on it.
1. If for a certain quantity of books, the publisher has to pay Rs. 30,600 as printing cost, then what will be amount of royalty to be paid for these books?
A. Rs. 19,450
B. Rs. 21,200
C. Rs. 22,950
D. Rs. 26,150
2. What is the central angle of the sector corresponding to the expenditure incurred on Royalty?
A. 15°
B. 24°
C. 54°
D. 48°
3. The price of the book is marked 20% above the C.P. If the marked price of the book is Rs. 180, then what is the cost of the paper used in a single copy of the book?
A. Rs. 36
B. Rs. 37.50
C. Rs. 42
D. Rs. 44.25
4. If 5500 copies are published and the transportation cost on them amounts to Rs. 82500, then what should be the selling price of the book so that the publisher can earn a profit of 25%?
A. Rs. 187.50
B. Rs. 191.50
C. Rs. 175
D. Rs. 180
5. Royalty on the book is less than the printing cost by:
A. 5%
B. 33%
C. 20%
D. 25%
Direction to solve(6 to 10): The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991 - 1992 to 1998 - 1999.
6. The ratio of the number of years, in which the foreign exchange reserves are above the average reserves, to those in which the reserves are below the average reserves is?
A. 2:6
B. 3:4
C. 3:5
D. 4:4
7. The foreign exchange reserves in 1997-98 was how many times that in 1994-95?
A. 0.7
B. 1.2
C. 1.4
D. 1.5
8. For which year, the percent increase of foreign exchange reserves over the previous year, is the highest?
A. 1992-93
B. 1993-94
C. 1994-95
D. 1996-97
9. The foreign exchange reserves in 1996-97 were approximately what percent of the average foreign exchange reserves over the period under review?
A. 95%
B. 110%
C. 115%
D. 125%
10. What was the percentage increase in the foreign exchange reserves in 1997-98 over 1993-94?
A. 100
B. 150
C. 200
D. 620
11. I. [latex]x^{2}[/latex] - x - 42 = 0,
II. [latex]y^{2}[/latex] - 17y + 72 = 0 to solve both the equations to find the values of x and y?
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established.
12. I. [latex]x^{2}[/latex] + 9x + 20 = 0,
II. [latex]y^{2}[/latex] + 5y + 6 = 0 to solve both the equations to find the values of x and y?
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established.
13. I. [latex]x^{2}[/latex] + 3x - 18 = 0,
II. [latex]y^{2}[/latex] + y - 30 = 0 to solve both the equations to find the values of x and y?
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established.
14. I. [latex]x^{2}[/latex] + 11x + 30 = 0,
II. [latex]y^{2}[/latex] + 15y + 56 = 0 to solve both the equations to find the values of x and y?
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established.
15. I. 9[latex]a^{2}[/latex] + 18a + 5 = 0,
II. 2[latex]b^{2}[/latex] + 13b + 20 = 0 to solve both the equations to find the values of a and b?
A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b
E. If a = b or the relationship between a and b cannot be established.
16. Look at this series: 80, 10, 70, 15, 60, ... What number should come next?
17. Look at this series: 2, 6, 18, 54, ... What number should come next?
A. 108
B. 148
C. 162
D. 216
18. Look at this series: 5.2, 4.8, 4.4, 4, ... What number should come next?
A. 3
B. 3.3
C. 3.5
D. 3.6
19. Look at this series: 8, 6, 9, 23, 87 , ... What number should come next?
A. 128
B. 226
C. 324
D. 429
20. Look at this series: 1.5, 2.3, 3.1, 3.9, ... What number should come next?
A. 4.2
B. 4.4
C. 4.7
D. 5.1
21. A man has Rs.480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
22. There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A. 20
B. 80
C. 100
D. 200
23. If a - b = 3 and [latex]a^{2}[/latex] + [latex]b^{2}[/latex] = 29, find the value of ab.
24. In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
A. 160
B. 175
C. 180
D. 195
25. A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
26. Find the highest common factor of 36 and 84.
27. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
A. Rs. 45
B. Rs. 50
C. Rs. 55
D. Rs. 60
28. A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was:
A. Rs. 2000
B. Rs. 10,000
C. Rs. 15,000
D. Rs. 20,000
29. Find the compound interest on Rs. 10,000 at 20% per annum for 6 months. compounded quarterly.
A. Rs.4353
B. Rs. 1329
C. Rs. 1025
D. Rs. 2649
30. The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A. 4 years
B. 8 years
C. 10 years
D. None of these
31. Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
32. A farmer traveled a distance of 61 km in 9 hours. He traveled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance traveled on foot is:
A. 14 km
B. 15 km
C. 16 km
D. 17 km
33. Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
A. [latex]\frac{1}{2}[/latex]
B. [latex]\frac{2}{5}[/latex]
C. [latex]\frac{8}{15}[/latex]
D. [latex]\frac{9}{20}[/latex]
34. In how many different ways can the letters of the word 'LEADING' be arranged in such a way that the vowels always come together?
A. 360
B. 480
C. 720
D. 5040
E. None of these
35. The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
A. 17 kg
B. 20 kg
C. 26 kg
D. 31 kg
36. A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?
A. Rs. 500
B. Rs. 1500
C. Rs. 2000
D. None of these
37. Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs.. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
A. 7 : 6 : 10
B. 12 : 15 : 16
C. 42 : 45 : 56
D. Cannot be determined
38. A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
A. 2 hours
B. 3 hours
C. 4 hours
D. 5 hours
39. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
A. 1 : 3
B. 3 : 2
C. 3 : 4
D. None of these
40. A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
A. 20 hours
B. 25 hours
C. 35 hours
D. Cannot be determined
E. None of these
Direction (41-45): Read the following information carefully and answer the questions given below.
Name of The Colleges |
Total Number of Students (2016) |
Percentage of Male Students |
A |
1850 |
54% |
B |
1550 |
66% |
C |
1340 |
45% |
D |
1675 |
56% |
E |
1250 |
72% |
F |
1450 |
38% |
41. Find the average of the number of female in all the colleges except college C and E?
A. 672.8
B. 683.5
C. 750
D. 753.5
E. 602.8
42. Find the average difference between the number of male and female students in all the colleges?
A. 312.833
B. 314.60
C. 313
D. 314.50
E. None of these
43. The number of female students in college C is what approx. percent of the number of male students of college A?
A. 70%
B. 72%
C. 74%
D. 76%
E. 77%
44. Out of total female in college E, 30% are in Arts department which is 35% of the total students in Arts department. Find out approximately how much percent of male students from E are in Arts department?
A. 20%
B. 22%
C. 19%
D. 23%
E. 25%
45. Find the ratio of [latex]\frac{2}{3}^{rfd}[/latex] of college B male students and female students of college F.
A. 29: 11
B. 29: 33
C. 33: 29
D. 29: 22
E. 22: 29
Direction (46-50): Study the following graph carefully to answer the question given below:
Given below is the demand and production of 6 brands (in units) of a product in the year 2016.
46. If the demand for brand C product increase by 75% then to meet the demand production should be increased by what percent?
A. 32.65%
B. 48.48%
C. 57.14%
D. 31.25%
E. None of these
47. Brand A increase its production to meet its demand. With every 160 unit produced the brand increases its price by 10%. If the earlier price of one product was INR 5000 then find the new price of the product.
A. INR 5500
B. INR 6655
C. INR 7320.5
D. INR 8052.55
E. Cannot be determined
48. The demand for brand D product fell. The new demand is 20% less than its production. Find by what percentage demand fell?
A. 28%
B. 30%
C. 38.88%
D. 72%
E. 32%
49. Brand B decreased its price of the product to meet its demand to its production. When the price decreased by 12% the demand increased by 25%. If the ratio between the new price and new demand is 11:20 then find the price of the product before the decrease.
A. INR 2500
B. INR 2300
C. INR 2200
D. INR 2000
E. INR 2800
50. The production of brand E and F took together is approx. what percent of total demand of E and F?
A. 81%
B. 21%
C. 123%
D. 121%
E. 23%
Answer: Option
Explanation:
Answer & Explanation:
1. Answer: Option C
Explanation:
Let the amount of Royalty to be paid for these books be Rs. r.
Then, 20 : 15 = 30600 : r
r = Rs.([latex]\frac{30600 x 15}{20}[/latex])= Rs. 22,950
2. Answer: Option C
Explanation:
Central angle corresponding to Royalty = (15% of 360)°
= [latex]\frac{15}{100}[/latex] * 360
= 54°
3. Answer: Option B
Explanation:
Clearly, marked price of the book = 120% of C.P.
Also, cost of paper = 25% of C.P
Let the cost of paper for a single book be Rs. n.
Then, 120 : 25 = 180 : n
n = Rs.[latex]\frac{25 * 180}{120}[/latex]= Rs. 37.50
4. Answer: Option A
Explanation:
For the publisher to earn a profit of 25%, S.P. = 125% of C.P.
Also Transportation Cost = 10% of C.P.
Let the S.P. of 5500 books be Rs. x.
Then, 10 : 125 = 82500 : x
x = Rs. ([latex]\frac{125 x 82500}{10}[/latex])= Rs. 1031250
S.P. of one book = Rs.[latex]\frac{1031250}{5500}[/latex]= Rs. 187.50
5. Answer: Option D
Explanation:
Printing Cost of book = 20% of C.P.
Royalty on book = 15% of C.P.
Difference = (20% of C.P.) - (15% of C.P) = 5% of C.P.
Therefore Percentage difference = ([latex]\frac{Difference}{Printing Cost}[/latex]*100)%
= ([latex]\frac{5% of C.P.}{Printing Cost}[/latex]*100)% = 25%
6. Answer: Option C
Explanation:
Average foreign exchange reserves over the given period = 3480 million US $.
The country had reserves above 3480 million US $ during the years 1992-93, 1996-97 and 1997-98, i.e., for 3 years and below 3480 million US $ during the years 1991-92, 1993-94, 1994-95, 1995-56 and 1998-99 i.e., for 5 years.
Hence, required ratio = 3 : 5.
7. Answer: Option D
Explanation:
Required ratio =[latex]\frac{5040}{3360}[/latex]= 1.5
8. Answer: Option A
Explanation:
There is an increase in foreign exchange reserves during the years 1992 - 1993, 1994 - 1995, 1996 - 1997, 1997 - 1998 as compared to previous year (as shown by bar-graph).
The percentage increase in reserves during these years compared to previous year are:
For 1992 - 1993 =[[latex]\frac{(3720 - 2640)}{2640}[/latex]* 100]% = 40.91%.
For 1994 - 1995 =[[latex]\frac{(3360 - 2520)}{2520}[/latex]* 100]% = 33.33%
For 1996 - 1997 =[[latex]\frac{(4320 - 3120)}{3120}[/latex]* 100]% = 38.46%
For 1997 - 1998 =[[latex]\frac{(5040 - 4320)}{4320}[/latex]* 100]% = 16.67%
Clearly, the percentage increase over previous year is highest for 1992 - 1993
9. Answer: Option D
Explanation:
Average foreign exchange reserves over the given period
= [[latex]\frac{1}{8}[/latex]* (2640 + 3720 + 2520 + 3360 + 3120 + 4320 + 5040 + 3120)]million US $
= 3480 million US $.
Foreign exchange reserves in 1996 - 1997 = 4320 million US $.
Therefore Required percentage =([latex]\frac{4320}{3480}[/latex]* 100)% = 124.14% ~= 125%
10. Answer: Option A
Explanation:
Foreign exchange reserves in 1997 - 1998 = 5040 million US $.
Foreign exchange reserves in 1993 - 1994 = 2520 million US $.
Therefore Increase = (5040 - 2520) = 2520 US $.
Therefore Percentage Increase =([latex]\frac{2520}{2520}[/latex]* 100)% = 100%
11. Answer: Option A
Explanation:
I. [latex]x^{2}[/latex] - 7x + 6x - 42 = 0
(x - 7)(x + 6) = 0 => x = 7, -6
II. [latex]y^{2}[/latex] - 8y - 9y + 72 = 0
(y - 8)(y - 9) = 0 => y = 8, 9
= x < y
12. Answer: Option A
Explanation:
I. [latex]x^{2}[/latex] + 4x + 5x + 20 = 0
(x + 4)(x + 5) = 0 => x = -4, -5
II. [latex]y^{2}[/latex] + 3y + 2y + 6 = 0
(y + 3)(y + 2) = 0 => y = -3, -2
= x < y.
13. Answer: Option E
Explanation:
I. [latex]x^{2}[/latex] + 6x - 3x - 18 = 0
(x + 6)(x - 3) = 0 => x = -6, 3
II. [latex]y^{2}[/latex] + 6y - 5y - 30 = 0
(y + 6)(y - 5) = 0 => y = -6, 5
No relationship can be established between x and y.
14. Answer: Option B
Explanation:
I. [latex]x^{2}[/latex] + 6x + 5x + 30 = 0
(x + 6)(x + 5) = 0 => x = -6, -5
II. [latex]y^{2}[/latex] + 8y + 7y + 56 = 0
(y + 8)(y + 7) = 0 => y = -8, -7
= x > y
15. Answer: Option A
Explanation:
I. 9[latex]a^{2}[/latex] + 3a + 15a + 5 = 0
(3a + 5)(3a + 1) = 0 => a = -[latex]\frac{5}{3}[/latex], -[latex]\frac{1}{3}[/latex]
II. 2[latex]b^{2}[/latex] + 8b + 5b + 20 = 0
(2b + 5)(b + 4) = 0 => b = -[latex]\frac{5}{2}[/latex], -4
a is always more than b.
= a > b.
16. Answer: Option A
Explanation:
This is an alternating addition and subtraction series. In the first pattern, 10 is subtracted from each number to arrive at the next. In the second, 5 is added to each number to arrive at the next.
17. Answer: Option C
Explanation:
This is a simple multiplication series. Each number is 3 times more than the previous number.
18. Answer: Option D
Explanation:
In this simple subtraction series, each number decreases by 0.4.
19. Answer: Option D
Explanation:
8 * 1 - 2 = 6
6 * 2 - 3 = 9
9 * 3 - 4 = 23
23 * 4 - 5 = 87
87 * 5 - 6 = 429 ...
20. Answer: Option C
Explanation:
In this simple addition series, each number increases by 0.8.
21. Answer: Option D
Explanation:
Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Hence, total number of notes = 3x = 90.
22. Answer: Option C
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10
x - y = 20 .... (i)
and x + 20 = 2(y - 20)
x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
23. Answer: Option C
Explanation:
2ab = ([latex]a^{2}[/latex] + [latex]b^{2}[/latex]) - (a - b)2
= 29 - 9 = 20
ab = 10.
24. Answer: Option B
Explanation:
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
25. Answer: Option D
Explanation:
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140
x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
26. Answer: Option C
Explanation:
36 = [latex]2^{2}[/latex] x [latex]3^{2}[/latex]
84 = [latex]2^{2}[/latex] x 3 x 7
H.C.F. = [latex]2^{2}[/latex] x 3 = 12.
27. Answer: Option D
Explanation:
(C.P. of 17 balls) - (S.P. of 17 balls) = (C.P. of 5 balls)
C.P. of 12 balls = S.P. of 17 balls = Rs.720.
C.P. of 1 ball = Rs.([latex]\frac{720}{12}[/latex])= Rs. 60
28. Answer: Option C
Explanation:
Principal = Rs.([latex]\frac{100 x 5400}{12*3}[/latex])= Rs. 15000
29. Answer: Option C
Explanation:
P = 10000, T = 6 months, R = [latex]\frac{20}{4}[/latex] = 5%(rate of interest apply quarterly)
By the net% effect we would calculate the effective compound rate of interest for 6 months = 10.25% (Refer to sub-details)
CI = 10.25% of 10000
CI =[latex]\frac{10.25 × 10000}{100}[/latex]
CI = 1025.
30. Answer: Option A
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
31. Answer: Option B
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x
x =([latex]\frac{4*20}{5}[/latex])
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
32. Answer: Option C
Explanation:
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
So,[latex]\frac{x}{4}[/latex]+[latex]\frac{(61 -x)}{9}[/latex]= 9
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
33. Answer: Option D
Explanation:
Here, S = {1, 2, 3, 4, ...., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) = [latex]\frac{n(E)}{n(S)}[/latex]= [latex]\frac{9}{20}[/latex]
34. Answer: Option C
Explanation:
The word 'LEADING' has 7 different letters.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
35. Answer: Option D
Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
B's weight = 31 kg.
36. Answer: Option C
Explanation:
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x - 3x = 1000
x = 1000.
B's share = Rs. 2x = Rs. (2 * 1000) = Rs. 2000.
37. Answer: Option B
Explanation:
Aman : Rakhi : Sagar = (70,000 x 36) : (1,05,000 x 30) : (1,40,000 x 24) = 12 : 15 : 16.
38. Answer: Option C
Explanation:
Speed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream =([latex]\frac{68}{17}[/latex])hrs = 4 hrs
39. Answer: Option B
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
[latex]\frac{27x + 17y}{x+ y}[/latex]= 23
27x + 17y = 23x + 23y
4x = 6y
[latex]\frac{x}{y}[/latex]= [latex]\frac{3}{2}[/latex]
40. Answer: Option C
Explanation:
Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take[latex]\frac{x}{2}[/latex] and [latex]\frac{x}{4}[/latex]hours respectively to fill the tank.
[latex]\frac{1}{x}[/latex]+[latex]\frac{2}{x}[/latex]+[latex]\frac{4}{x}[/latex]=[latex]\frac{1}{5}[/latex]
x = 35 hrs
41. Answer: Option D
Explanation:
Total number of students in college A = 1850
54% of the total students are male
⇒ 46% of the total students are female
∴ Number of female students in college A = 46% of 1850
⇒ Number of female students in college A = 851
Total number of students in college B = 1550
66% of the total students are male
⇒ 34% of the total students are female
∴ Number of female students in college B = 34% of 1550
⇒Number of female students in college B = 527
Total number of students in college D = 1675
56% of the total students are male
⇒ 44% of the total students are female
∴ Number of female students in college D = 44% of 1675
⇒ Number of female students in college D = 737
Total number of students in college F = 1450
38% of the total students are male
⇒ 62% of the total students are female
∴ Number of female students in college F = 62% of 1450
⇒ Number of female students in college F = 899
Now, required average =
[latex]\frac{851 + 527 + 737 + 899}{4}[/latex] = [latex]\frac{3014}{4}[/latex] = 753.5
42. Answer: Option A
Explanation:
Total number of students in college A = 1850
54% of the total students are male
⇒ 46% of the total students are female
∴8% difference between male and female students
⇒ Difference between male and female students in college A = 8% of 1850
⇒ Difference between male and female students in college
A = 148
Total number of students in college B = 1550
66% of the total students are male
⇒ 34% of the total students are female
∴32% difference between male and female students
⇒ Difference between male and female students in college B = 32% of 1550
⇒Difference between male and female students in college B = 496
Total number of students in college C = 1340
45% of the total students are male
⇒ 55% of the total students are female
∴10% difference between male and female students
⇒ Difference between male and female students in college C = 10% of 1340
⇒ Difference between male and female students in college C = 134
Total number of students in college D = 1675
56% of the total students are male
⇒ 44% of the total students are female
∴12% difference between male and female students
⇒ Difference between male and female students in college D = 12% of 1675
⇒ Difference between male and female students in college D = 201
Total number of students in college E = 1250
72% of the total students are male
⇒ 28% of the total students are female
∴44% difference between male and female students
⇒ Difference between male and female students in college E = 44% of 1250
⇒ Difference between male and female students in college E = 550
Total number of students in college F = 1450
38% of the total students are male
⇒ 62% of the total students are female
∴ 24% difference between male and female students
⇒ Difference between male and female students in college F = 24% of 1450
⇒ Difference between male and female students in college F = 348
Now, required average = [latex]\frac{148 + 496 + 134 + 201 + 550 + 348}{6}[/latex] = [latex]\frac{1877}{6}[/latex] = 312.8
43. Answer: Option C
Explanation:
Total number of students in college C = 1340
45% of the total students are male
⇒ 55% of the total students are female
∴ Number of female students in the college C = 55% of 1340
⇒ Number of female students in the college C = 737
Total number of students in college A = 1850
54% of the total students are male
∴ Number of male students in the college A = 54% of 1850
⇒ Number of male students in the college A = 999
Now, required percentage
= [latex]\frac{737}{999}[/latex] × 100
Hence, the number of female students in college C is approx. 74% of number of male students of college A
44. Answer: Option B
Explanation:
Total number of students in college E = 1250
72% of the total students are male
⇒ 28% of the total students are female
∴ Number of female students in college E = 28% of 1250
⇒ Number of female students in college E = 350
Out of 350 students, 30% are in Arts department
⇒ Number of female students in Arts department = 30%
of 350
⇒ Number of female students in Arts department = 105
105 female students is 35% of total students in Arts department
Let the total number of students in Arts department be x
⇒ Number of female students in Arts department = 35%
of x
⇒ [latex]\frac{7x}{20}[/latex] = 105
⇒ x = 300
∴Number of male students in arts department = 300 – 105 = 195
Number of male students in college E = 72% of 1250
⇒Number of male students in college E = 900
Now, required percentage
= [latex]\frac{195}{900}[/latex] × 100= 22%
45. Answer: Option E
Explanation:
Total number of students in college B = 1550
66% of the total students are male
∴ Number of male students in college B = 66% of 1550
⇒ Number of male students in college B = 1023
∴ [latex]\frac{2}{3}^{rd}[/latex] of male students of college B = 682
Total number of students in college F = 1450
38% of the total students are male
⇒ 62% of the total students are female
∴ Number of female students in college F = 62% of 1450
⇒ Number of male students in college F = 899
Now, required ratio =[latex]\frac{682}{899}[/latex] = [latex]\frac{22}{29}[/latex]
Hence, the ratio of [latex]\frac{2}{3}^{rd}[/latex] of college B male students and
female students of college F is 22: 29
46. Answer: Option B
Explanation:
Demand for brand C product = 2800 units
Demand for brand C product increase by 75%
⇒ New demand of brand C product = 175% of 2800 units
⇒ New demand of brand C product = 4900 units
Production of brand C product = 3300 units
To meet the demand the brand C should raise the production of product to 4900 units
∴ 1600 more units should be produced.
⇒ required percentage = [latex]\frac{1600}{3300}[/latex]
Hence, to meet the demand the brand C should raise the production by 48.48%.
47. Answer: Option D
Explanation:
Demand for brand A product = 2200 units
Production of brand A product = 1400 units
Difference between demand and production of brand A
product = 800 units
The company has to raise its production t0 2200 to meet its demand for that it has to produce 800 units more.
With every 160 unit produced the brand increases its price by 10%.
⇒ Number of times the brand increase its price by 10% = [latex]\frac{800}{160}[/latex] = 5
Earlier price of one product was INR 5000
⇒ New price of the product
= 5000 × [latex]\frac{110}{100}[/latex] ×[latex]\frac{110}{100}[/latex] × [latex]\frac{110}{100}[/latex] × [latex]\frac{110}{100}[/latex] ×[latex]\frac{110}{100}[/latex]
Hence, the new price of the product is INR 8052.55
48. Answer: Option A
Explanation:
Demand of brand D product = 5000 units
Production of brand D product = 4500 units
The new demand is 20% less than its production
New demand for brand D product = 80% of 4500 units
⇒New demand of brand D product = 3600 units
∴Difference in earlier demand and new demand = 5000 – 3600 = 1400
⇒Demand fell by 1400 units
Now, required percentage =[latex]\frac{1400}{5000}[/latex] × 100 = 28%
Hence, the demand for brand D product fell by 28%.
49. Answer: Option A
Explanation:
Let the price of the product be INR x
The brand B decreased its price by 12% which led to increasing in demand by 25%
⇒ New price of the product = 88% of x
Demand for the brand B product = 3200 units
⇒ New demand of the brand B product = 125% of 3200
⇒ New demand of the brand B product = 4000 units
The ratio between the new price and new demand is
11 : 20
⇒ [latex]\frac{88x}{100 }[/latex] = [latex]\frac{11}{20}[/latex] × 4000
⇒ x = 2500
Hence, original price of the brand B product is INR 2500
50. Answer: Option C
Explanation:
Production of brand E product = 3500 units
Production of brand F product = 4400 units
Total production of brand E and F = 7900 units
Demand of brand E product = INR 2800 units
Demand of brand F product = INR 3600 units
Total demand of brand E and F = 6400 units
Now, required percentage
= [latex]\frac{7900}{6400}[/latex] × 100 ≈123%