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NABARD Grade B Quantitative Aptitude

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NABARD Grade B Quantitative Aptitude

shape Introduction

NABARD Grade B 2019 – Preliminary Examination, conducted in online Mode, has: a duration of 2 hours, a total of 200 questions, a maximum score of 200 marks, and consists of 7 sections, namely – Reasoning Ability, English Language, Computer Knowledge, General Awareness, Quantitative Aptitude, Economic & Social Issues and Agriculture & Rural Development. There is a Negative marking in NABARD Grade B Preliminary exam and [latex]{(\frac {1}{4})}^{th}[/latex] marks are deducted for each wrong answer. Candidates must clear the cut-off in all the sections to qualify for the NABARD Grade B Main exam.
The article NABARD Grade B Quantitative Aptitude provides complete details of Quantitative Aptitude syllabus and provides study guide with answers. By solving this questions candidates can improve and maintain, speed, and accuracy in the exams.

shape Pattern

The NABARD Grade B Prelims exam pattern 2019 is conducted for screening purpose that is consists of seven different sections containing different marks with a total of 200 marks.
Phase I – Preliminary Examination (Online Exam)
S.no Subjects Number of questions Marks
1. Test of Reasoning 20 20 marks
2. English Language 40 40 marks
3. Computer Knowledge 20 20 marks
4. General Awareness 20 20 marks
5. Quantitative Aptitude 20 20 marks
6. Economic & Social Issues (with focus on Rural India) 40 40 marks
7. Agriculture & Rural Development (with focus on Rural India) 40 40 marks
Duration: 120 Minutes Composite Time - Total 200 marks - 200 Questions

shape Syllabus

NABARD Officer Grade B Exam Syllabus – Preliminary Exam:
Quantitative Aptitude Syllabus - 20 Marks
  • Number Systems
  • Averages
  • Percentages
  • Profit and Loss
  • Discount
  • Decimals and Fractions
  • Ratio and Proportion
  • Interest
  • Mensuration
  • Use of Tables and Graphs
  • Time and Work
  • Time and Distance
  • Computation of Whole Numbers etc.


shape Samples

1. Rambabu can do a piece of work in 5 days and Santosh can do the same work in 7 days. If both work together, they will finish the work in how many days?
    A. 12 days B. 2 days C. [latex] 2 \frac{11}{12}[/latex] D. [latex]\frac{12}{35}[/latex]

Answer - Option C
Explanation -
[latex]\frac{5 * 7}{5 + 7} = \frac{35}{12} = 2 \frac{11}{12}[/latex] days
2. A man goes from Delhi to Dehradun. Half the distance he covers by bus at an average speed of 50 km/hr and the other half by train at an average speed of 70 km/hr. The average speed for the whole journey was
    A. 56 km/hr B. 64 km/hr C. 60 km/hr D. None of these

Answer - Option D
Explanation -
v - bar = [latex]\frac {2uv} {u + v}[/latex] = [latex]\frac {2 * 50 * 70} {50 + 70}[/latex] =[latex] 58 \frac {1} {3}[/latex]
3. Rakesh took a loan for 7 years at the rate of 6 % p.a. S.I. If total interest paid was Rs. 2100, then principal was
    A. Rs. 4400 B. Rs. 4800 C. Rs. 5000 D. Rs. 5200

Answer - Option C
Explanation -
Principal = Rs[latex](\frac {2100 * 100} {7 * 6} )[/latex] = Rs. 500
4. How much should money lender lend at simple rate of interest of 15% in order to have Rs. 3234 at the end of [latex] 1 \frac {1} {2}[/latex] years
    A. Rs. 1640 B. Rs. 2620 C. Rs. 2610 D. Rs. 2640

Answer - Option D
Explanation -
Let required money be x
Then [latex]( x + \frac {x * 15} {100} * \frac {3}{2}[/latex] = 3234
[latex]\frac {49 x} {40}[/latex] = 3234
i.e, x = [latex]\frac {3234 * 40} {49}[/latex] = 2640
5. Rajan buys lemons at the rate of 9 for 80p and sells them at 11 for 120p. His gain per lemon is
    A. [latex]\frac {200} {99}[/latex] B. [latex]\frac {11} {99}[/latex] C. [latex]\frac {120} {99}[/latex] D. [latex]\frac {11} {9}[/latex]

Answer - Option A
Explanation -
CP = [latex]\frac {80} {9}[/latex]; SP = [latex]\frac {120} {11}[/latex]
i.e, Gain per lemon = [latex]\frac {120} {11} - \frac {80} {9} = \frac {200} {99}[/latex]
6. A man travels first 80 km at 20 kmph, next 30 km at 15 kmph and then 80 km at 20 kmph. His average speed for the whole journey (in kmph) is
    A. 20 B. 22 C. 17 D. 19

Answer - Option D
Explanation -
Man travels total distance of 80 + 30 + 80 = 190 kilometers.
Times taken
for [latex]{1}^{st}[/latex] phase = [latex]\frac{80 km}{20 km/hr}[/latex] = 4hr
for [latex]{2}^{nd}[/latex] phase= [latex]\frac{30 km}{15 km/hr}[/latex] = 2hr
for [latex]{3}^{rd}[/latex] phase= [latex]\frac{80 km}{20 km/hr}[/latex] = 4hr
So, average speed for the whole journey
= [latex]\frac{Total dist ance}{Total time taken}[/latex]
= [latex]\frac{80 + 30 + 80}{4 + 2 + 4}hr[/latex] = [latex]\frac{190 km}{10 hr}[/latex] = 19 km/hr
7. A horse is tethered to one corner of a rectangular grassy field 40 m by 24 m with a rope 14 m long. Over how much area of the field can it graze ?
    A. 154 [latex] {m}^{2}[/latex] B. 308 [latex] {m}^{2}[/latex] C. 150 [latex] {m}^{2}[/latex] D. None of these

Answer - Option A
8. The difference between the local value and face value of 7 in the numeral 657903 is:
    A. O B. 7896 C. 6993 D. 903

Answer - Option C
Explanation -
(Local value) - (Face value) = (7000 - 7) = 6993.
9. The sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the numbers is:
    A. 7 B. 29 C. 41 D. 67

Answer - Option D
Explanation -
x + (x + 36) + y = 100 [latex]\Rightarrow[/latex] 2x + y = 64
Therefore y must be even prime, which is 2.
Therefore 2x + 2 = 64 [latex]\Rightarrow[/latex] x = 31
Third prime number= (x + 36) = (31 + 36) = 67.
10. (51 + 52 + 53 +………+ 100) is equal to:
    A. 2225 B. 3345 C. 3775 D. 3770

Answer - Option C
Explanation -
(51+52+53+………+100) = (1+2+3+…….+100)- (1+2+3+4+……+50)
= [latex]\frac {(100 \times 101)}{2}[/latex] - [latex]\frac {(50 \times 51)}{2}[/latex]
= (5050 - 1275)= 3775.
NABARD Grade B Quantitative Aptitude – Study Guide Click Here

NABARD Grade B 2019 – Related Information
NABARD Grade B 2019 – Reasoning Ability - Study Guide
NABARD Grade B 2019 – English Language - Study Guide
NABARD Grade B 2019 – Computer Knowledge - Study Guide
NABARD Grade B 2019 – General Awareness - Study Guide