1. A clock is started at noon. By 10 minutes past 5, the hour hand has turned through:

A. 145° B. 150° C. 155° D. 160°

Answer: Option C
Explanation: Angle traced by hour hand in 12 hrs = 360°. Angle traced by hour hand in 5 hrs 10 min. i.e.= [latex]\frac {31}{6}[/latex]hrs = [latex]\frac {360}{12}[/latex] X [latex]\frac {31}{6}[/latex] = 155°
2. How many times in a day, the hands of a clock are straight?

A. 22 B. 24 C. 44 D. 48

Answer: Option C
Explanation: In 12 hours, the hands coincide or are in opposite direction 22 times. In 24 hours, the hands coincide or are in opposite direction 44 times a day.
3. A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?

A. 2 p.m. on Tuesday B. 2 p.m. on Wednesday C. 3 p.m. on Thursday D. 1 p.m. on Friday

Answer: Option B
Explanation: Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours = 170 hours. The watch gains 2 + 4 [latex]\frac {4}{5}[/latex]min. or [latex]\frac {34}{5}[/latex] min. in 170 hrs. [latex]\frac {34}{5}[/latex] min. are gained in 170 hrs. 2 min. are gained in 170 x [latex]\frac {5}{34}[/latex] x 2 hrs = 50 hrs. Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m. on Wednesday.
4. How many times do the hands of a clock coincide in a day?

A. 20 B. 21 C. 22 D. 24

Answer: Option C
Explanation: The hands of a clock coincide 11 times in every 12 hours (Since between 11 and 1, they coincide only once, i.e., at 12 o'clock). AM 12:00 1:05 2:11 3:16 4:22 5:27 6:33 7:38 8:44 9:49 10:55 PM 12:00 1:05 2:11 3:16 4:22 5:27 6:33 7:38 8:44 9:49 10:55 The hands overlap about every 65 minutes, not every 60 minutes. The hands coincide 22 times in a day..

1. The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

A. 123 B. 127 C. 235 D. 305

Answer: Option B
Explanation: Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 = 127.
2. Which of the following has the most number of divisors?

A. 99 B. 101 C. 176 D. 182

Answer: Option C
Explanation: 99 = 1 x 3 x 3 x 11 101 = 1 x 101 176 = 1 x 2 x 2 x 2 x 2 x 11 182 = 1 x 2 x 7 x 13 So, divisors of 99 are 1, 3, 9, 11, 33, .99 Divisors of 101 are 1 and 101 Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176 Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182. Hence, 176 has the most number of divisors.
3. The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

A. 28 B. 32 C. 40 D. 64

Answer: Option C
Explanation: 64
4. Find the lowest common multiple of 24, 36 and 40.

A. Rs. 10 B. Rs. 10.40 C. Rs. 15.20 D. Rs. 13

Answer: Option B
Explanation: S.I. on Rs. (260 - 20) for a given time = Rs. 20. S.I. on Rs. 240 for half the time = Rs. 10. T.D. on Rs. 250 = Rs. 10. T.D. on Rs. 260 = Rs. [latex]\frac {10 }{250}[/latex] X 260 = = Rs. 10.40 Sagar's present age = (5x + 6) = 16 years.
5. Find the lowest common multiple of 24, 36 and 40.

A. 120 B. 240 C. 360 D. 480

Answer: Option C
Explanation: 2 | 24 - 36 - 40 -------------------- 2 | 12 - 18 - 20 -------------------- 2 | 6 - 9 - 10 ------------------- 3 | 3 - 9 - 5 ------------------- | 1 - 3 - 5 L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.

1. 16, 33, 65, 131, 261, (....)

A. 523 B. 521 C. 613 D. 721

Answer: Option A
Explanation: Each number is twice the preceding one with 1 added or subtracted alternatively. So, the next number is (2 x 261 + 1) = 523.
2. 10, 5, 13, 10, 16, 20, 19, (....)

A. 22 B. 40 C. 38 D. 23

Answer: Option B
Explanation: There are two series (10, 13, 16, 19) and (5, 10, 20, 40), one increasing by 3 and the other multiplied by 2.
3. 1, 4, 9, 16, 25, 36, 49, (....)

A. 54 B. 56 C. 64 D. 81

Answer: Option C
Explanation: Numbers are [latex]{1}^{2}[/latex], [latex]{2}^{2}[/latex], [latex]{3}^{2}[/latex], [latex]{4}^{2}[/latex], [latex]{5}^{2}[/latex], [latex]{6}^{2}[/latex], [latex]{7}^{2}[/latex]. So, the next number is [latex]{8}^{2}[/latex] = 64.
4. 8, 7, 11, 12, 14, 17, 17, 22, (....)

A. 27 B. 20 C. 22 D. 24

Answer: Option B
Explanation: Greatest number of 4-digits is 9999. There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.
5. 7, 8, 18, 57, 228, 1165, 6996

A. 8 B. 18 C. 57 D. 228

Answer: Option D
Explanation: Let the given numbers be A, B, C, D, E, F, G. Then, A, A x 1 + 1, B x 2 + 2, C x 3 + 3, D x 4 + 4, E x 5 + 5, F x 6 + 6 are the required numbers. Clearly, 228 is wrong.