1. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?

A. 57% B. 60% C. 65% D. 90%

Answer: Option A
Explanation: Total number of votes polled = (1136 + 7636 + 11628) = 20400. Required percentage = [[latex]\frac {11628}{20400}[/latex] x 100] % = 57% R = 5% I = [latex]\frac {(450*6*5)}{100}[/latex]= 135 450 + 135 = 585
2. Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

A. Rs. 200 B. Rs. 250 C. Rs. 300 D. None of these

Answer: Option B
Explanation: Let the sum paid to Y per week be Rs. z. Then, z + 120% of z = 550. z + [latex]\frac {120)}{100}[/latex]Z = 500 [latex]\frac {11)}{5}[/latex]Z = 550 z = [latex]\frac {550 x 5)}{11}[/latex] = 250
3. Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax-free items?

A. Rs. 15 B. Rs. 15.70 C. Rs. 19.70 D. Rs. 20

Answer: Option C
Explanation: Let the amount taxable purchases be Rs. x. Then, 6% of x = [latex]\frac {30)}{100}[/latex] x = {[latex]\frac {30)}{100}[/latex] X [latex]\frac {100)}{6}[/latex]} = 5 Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70
4. Rajeev buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods.

A. Rs. 6876.10 B. Rs. 6876.10 C. Rs. 6654 D. Rs. 7000 E. None of these

Answer: Option A
Explanation: Rebate = 6% of Rs. 6650 = Rs. [[latex]\frac {6}{100}[/latex] x 6650] = Rs. 399. Sales tax = 10% of Rs. (6650 - 399) = Rs. [latex]\frac {10}{100}[/latex] x 6251] = Rs. 625.10 Final amount = Rs. (6251 + 625.10) = Rs. 6876.10
5. The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:

A. 4.37% B. 5% C. 6% D. 8.75%

Answer: Option B
Explanation: Increase in 10 years = (262500 - 175000) = 87500. Increase% = [[latex]\frac {87500}{175000}[/latex] x 100]% = 50%. Required average = [latex]\frac {50}{10}[/latex]% = 5%

1. Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

A. 24 B. 27 C. 40 D. Cannot be determined

Answer: Option A
Explanation: Let the present ages of Sameer and Anand be 5x years and 4x years respectively. Then, [latex]\frac {5x + 3}{4x + 3}[/latex] = [latex]\frac {11}{9}[/latex] 9(5x + 3) = 11(4x + 3) 45x + 27 = 44x + 33 45x - 44x = 33 - 27 x = 6 Anand's present age = 4x = 24 years.
2. A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?

A. 7 B. 8 C. 9 D. 10 E. 11

Answer: Option C
Explanation: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years. (2x + 2) + 2x + x = 27 5x = 25 x = 5. Hence, B's age = 2x = 10 years.
3. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:

A. 14 years B. 18 years C. 20 years D. 22 years

Answer: Option D
Explanation: Let the son's present age be x years. Then, man's present age = (x + 24) years. (x + 24) + 2 = 2(x + 2) x + 26 = 2x + 4 x = 22.
4. Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?

A. 16 years B. 18 years C. 20 years D. Cannot be determined

Answer: Option A
Explanation: Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively. Then, [latex]\frac {(6x + 6) + 4}{(5x + 6) + 4 }[/latex] = [latex]\frac {11}{10 }[/latex] 10(6x + 10) = 11(5x + 10) 5x = 10 x = 2. Sagar's present age = (5x + 6) = 16 years.
5. The sum of the present ages of a father and his son is 60 years. Six years ago, the father's age was five times the age of the son. After 6 years, son's age will be:

A. 12 years B. 14 years C. 18 years D. 20 years

Answer: Option D
Explanation: Let the present ages of son and father be x and (60 -x) years respectively. Then, (60 - x) - 6 = 5(x - 6) 54 - x = 5x - 30 6x = 84 x = 14. Son's age after 6 years = (x+ 6) = 20 years..

1. At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?

A. 12 years B. 15 years C. 19 and half D. 21 years

Answer: Option B
Explanation: Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then, 4x + 6 = 26 4x = 20 x = 5. Deepak's age = 3x = 15 years.
2. Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?

A. 16 years B. 18 years C. 28 years D. 24.5 years

Answer: Option D
Explanation: Let Rahul's age be x years. Then, Sachin's age = (x - 7) years. [latex]\frac {x - 7}{x}[/latex] [latex]\frac {7}{9}[/latex] 9x - 63 = 7x 2x = 63 x = 31.5 Hence, Sachin's age =(x - 7) = 24.5 years.
3. A hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:

A. 720 B. 900 C. 1200 D. 1800

Answer: Option C
Explanation: 2(15 + 12) x h = 2(15 x 12) h = [latex]\frac {180}{27}[/latex]m = [latex]\frac {20}{3}[/latex]m Volume = 15 x 12 x [latex]\frac {20}{3}[/latex][latex]{m}^{3}[/latex]
4. A boat having a length of 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:

A. 12 kg B. 60 kg C. 72 kg D. 96 kg

Answer: Option B
Explanation: Volume of water displaced = (3 x 2 x 0.01) [latex]{m}^{3}[/latex] 0.06 [latex]{m}^{3}[/latex] Mass of man = Volume of water displaced x Density of water = (0.06 x 1000) kg = 60 kg.
5. A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in [latex]{m}^{3}[/latex]) is:

A. 4830 B. 5120 C. 6420 D. 8960

Answer: Option B
Explanation: Clearly, l = (48 - 16)m = 32 m, b = (36 -16)m = 20 m, h = 8 m. Volume of the box = (32 x 20 x 8) [latex]{m}^{3}[/latex] = 5120 [latex]{m}^{3}[/latex]