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Percentages Practice Set 9

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Percentages Practice Set 9

shape Introduction

Percentages: A Percentage is a dimensionless ratio or number expressed as a fraction of 100. It is often denoted by the character (%).
Example: 10% = [latex]\frac{10}{100}[/latex] = [latex]\frac{1}{10}[/latex]
Percentages is one of the important topic in the Quantitative Aptitude section. The article Percentages Practice Set 9 consists of different models of questions with answers useful for candidates preparing for different competitive examinations like RRB ALP/Technical Exams/Junior Engineer Recruitment Exams, SSC, IBPS PO Exams and other examinations across the globe that include Quantitative Aptitude section. Prepare better for all exams with this Percentages Practice Set 9 for SSC CGL & Railways. This Percentages Practice Set 9 for SSC, Railways Exams will help you learn concepts of mensuration.

shape Quiz

1. What percent of a day in 6 hours?
    A. 25% B. 52% C. 50% D. 5%

Answer: Option A
Explanation: ([latex]\frac{6}{24}[/latex] × 100 = 25%
2. Two-fifth of one-third of three seventh of a number is 15.What is 40% of that number?
    A. 501 B. 105 C. 525 D. 150

Answer: Option C
Explanation: X * [latex]\frac{2}{5}[/latex] x [latex]\frac{1}{3}[/latex] x [latex]\frac{3}{7}[/latex] × x = 15 X = 15 x ([latex]\frac{7}{3}[/latex]) x ([latex]\frac{5}{2}[/latex]) x 3 = [latex]\frac{525}{2}[/latex] 40% of x = [latex]\frac{40}{100}[/latex] [latex]\frac{525}{2}[/latex]=>105
3. The population of of a town is 176000.If it increase at the rate of 5% per annum,what will be it’s population 2 years hence?
    A. 194000 B. 194040 C. 190440 D. 194104

Answer: Option B
Explanation: 176000 x [latex]\frac{105}{100}[/latex] = 88 × 105 × 21 = 194040
4. The length and breath of a rectangle are increased by 20% and 30%.The area of the resulting rectangle exceeds the area of the original rectangle?
    A. 50% B. 65% C. 56% D. 156%

Answer: Option C
Explanation: [latex]\frac{120}{100}[/latex] x [latex]\frac{130}{100}[/latex] x 150 = 156. 156 - 100 = 56.
5. Water tax is is increased by 20% but its consumption is decreased by 20%.Then increase or decrease in the expenditure of the money is
    A. 40% B. 4% C. 96% D. None of the above

Answer: Option B
Explanation: X - [latex]\frac{20 × 20 }{100}[/latex] = 4
1. Sugar contain 5% water .What quantity of pure Sugar should be added to 10 liters of water to reduce this to 2%.
    A. 5 lit B. 6 lit C. 10 lit D. 15 lit

Answer: Option D
Explanation: [latex]\frac{ 0.5 }{x + 10}[/latex] = [latex]\frac{ 2 }{100}[/latex] 2x = 30 X = 15
2. In an election between 2 candidates,Candidate who gets 40% of the total vote defeated by 15000.The no of votes polled by winner
    A. 10000 B. 45000 C. 30000 D. 6000

Answer: Option B
Explanation: 40% - looser, 60% - winner, defeated 15000 = 20% Winner = 60% = 15000 × 3 = 45000.
3. The price of a fan is decreased by 20%.as a result of wh ich the sale increased by 40%.What will be the effect on the total revenue of the shop?
    A. 12% B. 10% C. 20% D. 30%

Answer: Option A
Explanation: Original revenue = 100 × 100 = 10000. After 20% decrease = 80 × 140 = 11200. X * [latex]\frac{(11200-10000)}{10000}[/latex]) ×100 = [latex]\frac{1200}{10000}[/latex]) × 100 = 12%.
4. Raj save 10%,after 2 years when his income is increased by 10%,he could save the same money then how much his expenditure increased?
    A. 10% B. 20% C. 50% D. 15%

Answer: Option A
Explanation: Let income = 100, saving = 10 and expenditure =90. New income = 110, saving = 11 and e = 99. alcohol = [latex]\frac{99-90}{90}[/latex] × 100 = [latex]\frac{9}{90}[/latex] × 100 = 10%
5. 45% of ? = 25% of 355
    A. 195 B. 176 C. 127 D. 197.22

Answer: Option D
Explanation: [latex]\frac{45}{100}[/latex] x X = [latex]\frac{25}{100}[/latex] × 355 [latex]\frac{100}{45}[/latex] x [latex]\frac{25}{100}[/latex] = 197.22
1. Out of 500 students of a school 35% students plays football, 25% plays cricket and 20% neither play football nor cricket.How many students play football and cricket ?
    A. 200 B. 100 C. 50 D. 94

Answer: Option A
Explanation: Football = n(A) = ([latex]\frac{35}{100}[/latex]) × 500 = 175 Cricket = n(B) = ([latex]\frac{25}{100}[/latex]) × 500 = 125 neither play football nor cricket = ( [latex]\frac{20}{100}[/latex]) × 500 = 100 both football and cricket = n(A U B) = 175 + 125 -100 = 200
2. The price of sugar is reduced by 3%.How many kg of sugar can now be bought for the money which was sufficient to buy 50kg of rice earlier ?
    A. 50 kg B. 55 kg C. 51.5 kg D. 56 kg

Answer: Option C
Explanation: Let one kg of sugar earlier = Rs. 100 50 kg of sugar earlier = Rs. 5000 Now 1 kg of sugar = Rs.97 Quantity to buy now = [latex]\frac{5000}{97}[/latex] = 51.5 kg
3. Fresh fruits contains 70% of water and dry fruits contain 20% of water.How much dry fruit can be obtained from 100 kg of fresh fruits ?
    A. 35 B. 37 C. 37.5 D. 40

Answer: Option C
Explanation: Quantity of pulb in 100 kg of fresh fruit = (100 – 70) × 100 = 30 kg Quantity of dry fruit be x kg (100 – 20 ) % of x = 30 ([latex]\frac{80}{100}[/latex]) x = 30 X = [latex]\frac{(30 × 100)}{80}[/latex] = 37.5
4. In an examination , full mark is 500, A gets 25% more than B, B gets 40% more than C and C gets 60% more than D.If A got 320, what percentage of full marks did D got (approx)?
    A. 21 B. 22 C. 23 D. 24

Answer: Option C
Explanation: A = [latex]\frac{125}{100}[/latex] of B => B = [latex]\frac{4}{5}[/latex] A B = [latex]\frac{140}{100}[/latex] of C => C = [latex]\frac{5}{7}[/latex] B C = [latex]\frac{160}{100}[/latex] 0f D => D = [latex]\frac{5}{8}[/latex] C B = ([latex]\frac{4}{5}[/latex] ) × 320 = 256 C = ([latex]\frac{5}{7}[/latex] ) × 256 = 183 D = ([latex]\frac{5}{8}[/latex] ) × 183 = 114 D percentage = ([latex]\frac{114}{500}[/latex] ) × 100 = 23%
5. The population of a city is increased 5% ,7% and 11% in the last three years, What will be the present population if the population of a town is 2,40,000 three years ago ?
    A. 2,99,600 B. 2,99,500 C. 2,99,400 D. 2,99,300

Answer: Option D
Explanation: 2,40,000 × ([latex]\frac{105}{100}[/latex]) × ([latex]\frac{107}{100}[/latex]) × ([latex]\frac{111}{100}[/latex]) = 2,99,300
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