Direction(1-5): Find Odd One Out
1. 3, 5, 11, 14, 17, 21

A. 21 B. 17 C. 14 D. 3

Answer - Option C
Explanation -
Each of the numbers except 14 is an odd number.
The number '14' is the only EVEN number.
2. 8, 27, 64, 100, 125, 216, 343

A. 27 B. 100 C. 125 D. 343

Answer - Option B
Explanation -
The pattern is [latex] {2}^{3}, {3}^{3}, {4}^{3}, {5}^{3}, {6}^{3}, {7}^{3}[/latex].
But, 100 is not a perfect cube.
3. 10, 25, 45, 54, 60, 75, 80

A. 10 B. 45 C. 54 D. 75

Answer - Option C
Explanation -
Each of the numbers except 54 is multiple of 5.
4. 396, 462, 572, 427, 671, 264

A. 396 B. 427 C. 671 D. 264

Answer - Option B
Explanation - In each number except 427, the middle digit is the sum of other two.
5. 6, 9, 15, 21, 24, 28, 30

A. 28 B. 21 C. 24 D. 30

Answer - Option A
Explanation - Each of the numbers except 28, is a multiple of 3.

Direction(1-5): Find out the wrong number in the given sequence of numbers.
1. 582, 605, 588, 611, 634, 617, 600

A. 634 B. 611 C. 605 D. 600

Answer - Option A
Explanation -
Alternatively 23 is added and 17 is subtracted from the terms. So, 634 is wrong.
2. 22, 33, 66, 99, 121, 279, 594

A. 33 B. 121 C. 279 D. 594

Answer - Option C
Explanation -
Each of the number except 279 is a multiple of 11.
3. 8, 13, 21, 32, 47, 63, 83

A. 47 B. 63 C. 32 D. 83

Answer - Option A
Explanation -
Go on adding 5, 8, 11, 14, 17, 20.
So, the number 47 is wrong and must be replaced by 46.
4. 1, 8, 27, 64, 124, 216, 343

A. 8 B. 27 C. 64 D. 124

Answer - Option D
Explanation -
The numbers are [latex]{1}^{3}, {2}^{3}, {3}^{3}, {4}^{3}[/latex] etc. So, 124 is wrong; it must have been [latex]{5}^{3}[/latex] i.e., 125.
5. 1, 2, 6, 15, 31, 56, 91

A. 31 B. 91 C. 56 D. 15

Answer - Option B
Explanation -
[latex]1, 1 + {1}^{2} = 2, 2 + {2}^{2} = 6, 6 + {3}^{2} = 15, 15 + {4}^{2} = 31, 31 + {5}^{2} = 56, 56 + {6}^{2} = 92[/latex]
Last number of given series must be 92 not 91.

Direction(1-5): Insert the missing number.
1. 16, 33, 65, 131, 261, (....)

A. 523 B. 521 C. 613 D. 721

Answer - Option A
Explanation -
Each number is twice the preceding one with 1 added or subtracted alternatively.
So, the next number is (2 x 261 + 1) = 523.
2. 10, 5, 13, 10, 16, 20, 19, (....)

A. 22 B. 40 C. 38 D. 23

Answer - Option B
Explanation - There are two series (10, 13, 16, 19) and (5, 10, 20, 40), one increasing by 3 and the other multiplied by 2.
3. 1, 4, 9, 16, 25, 36, 49, (....)

A. 54 B. 56 C. 64 D. 81

Answer - Option C
Explanation -
Numbers are [latex]{1}^{2}, {2}^{2}, {3}^{2}, {4}^{2}, {5}^{2}, {6}^{2}, {7}^{2}.[/latex]
So, the next number is [latex]{8}^{2} = 64.[/latex]
4. 2, 4, 12, 48, 240, (....)

A. 960 B. 1440 C. 1080 D. 1920

Answer - Option B
Explanation -
Go on multiplying the given numbers by 2, 3, 4, 5, 6.
So, the correct next number is 1440.
5. 8, 7, 11, 12, 14, 17, 17, 22, (....)

A. 27 B. 20 C. 22 D. 24

Answer - Option B
Explanation -
There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.